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MECHANICAL ENGINEERING – FLUID MECHANICS
MECHANICAL ENGINEERING – FLUID MECHANICS
Pressure (P):
If F be the normal force acting on a surface of area A in contact with liquid, then
pressure exerted by liquid on this surface is: AFP /
Units : 2/ mN or Pascal (S.I.) and Dyne/cm2 (C.G.S.)
Dimension : ][][
][
][
][][ 21
2
2
TMLL
MLT
A
FP
Atmospheric pressure: Its value on the surface of the earth at sea level is nearly 25 /10013.1 mN or Pascal in S.I. other practical units of pressure are atmosphere,
bar and torr (mm of Hg)
torr760bar01.11001.11 5 Paatm
Fluid Pressure at a Point: dF
dA
Density ( ρ ):
In a fluid, at a point, density ρ is defined as: dV
dm
V
m
V
0lim
In case of homogenous isotropic substance, it has no directional properties, so is a
scalar.
It has dimensions ][ 3ML and S.I. unit kg/m3 while C.G.S. unit g/cc with
33 /10/1 mkgccg
Density of body = Density of substance
Relative density or specific gravity which is defined as : of water Density
of body DensityRD
If 1m mass of liquid of density 1 and 2m mass of density 2 are mixed, then as
21 mmm and )/()/( 2211 mmV [As /mV ]
)/()/()/( 2211
21
ii
i
pm
m
mm
mm
V
m
If 21 mm ,
21
212
Harmonic mean
If 1V volume of liquid of density 1 and 2V volume of liquid of density 2 are
mixed, then as: 2211 VVm and 21 VVV [As Vm / ]
If VVV 21 2/)( 21 = Arithmetic Mean
MECHANICAL ENGINEERING – FLUID MECHANICS
With rise in temperature due to thermal expansion of a given body, volume will
increase while mass will remain unchanged, so density will decrease, i.e.,
)1()/(
)/(
0
00
00
V
V
V
V
Vm
Vm [As )1(0 VV ]
or
)1(–~)1(
00
With increase in pressure due to decrease in volume, density will increase, i.e.,
V
V
Vm
Vm 0
00 )/(
)/(
[As
V
m ]
By definition of bulk-modulus:V
pVB
0 i.e.,
B
pVV 10
B
p
B
p1~1 0
1
0
Specific Weight ( w ):
It is defined as the weight per unit volume.
Specific weight .
.Weight m g
gVolume Volume
Specific Gravity or Relative Density (s):
It is the ratio of specific weight of fluid to the specific weight of a standard fluid.
Standard fluid is water in case of liquid and H2 or air in case of gas.
.
.
w w w
gs
g
Where, w Specific weight of water, and w Density of water specific.
Specific Volume ( v ):
Specific volume of liquid is defined as volume per unit mass. It is also defined as the
reciprocal of specific density.
Specific volume 1V
m
Inertial force per unit area = A
dtdmv
A
dtdp )/(/ =
A
Avv = 2v
MECHANICAL ENGINEERING – FLUID MECHANICS
Viscous force per unit area: r
vAF
/
Reynold’s number: area unit per force Viscous
area unit per forceInertial RN
rv
rv
v
/
2
Pascal’s Law: x y zp p p ; where, xp , yp and zp are the pressure at point x,y,z respectively.
Hydrostatic Law:
p
pgz
or dp pg dz
p h
o odp pg dz
p pgh and p
hpg
; where, h is known as pressure head.
Pressure Energy Potential energy Kinetic energy
It is the energy possessed by a
liquid by virtue of its pressure. It
is the measure of work done in
pushing the liquid against
pressure without imparting any
velocity to it.
It is the energy possessed by
liquid by virtue of its height or
position above the surface of
earth or any reference level
taken as zero level.
It is the energy possessed by a
liquid by virtue of its motion or
velocity.
Pressure energy of the liquid PV Potential energy of the liquid
mgh
Kinetic energy of the liquid
mv2/2
Pressure energy per unit mass of
the liquid P/ ρ
Potential energy per unit mass of
the liquid gh
Kinetic energy per unit mass of
the liquid v2/2
Pressure energy per unit volume
of the liquid P
Potential energy per unit volume
of the liquid ρgh
Kinetic energy per unit volume
of the liquid ρ v2/2
Quantities that Satisfy a Balance Equation
Quantit
y
mass x momentum y momentum z
momentum
Energy Species
m mu mv mw E + mV2/2 m
(K)
1 u v w e + V2/2 W
(K)
In this table, u, v, and w are the x, y and z velocity components, E is the total
thermodynamic internal energy, e is the thermodynamic internal energy per unit mass,
and m(K)
is the mass of a chemical species, K, W(K)
is the mass fraction of species K.
MECHANICAL ENGINEERING – FLUID MECHANICS
The other energy term, mV2/2, is the kinetic energy.
zyxtt
zyx
t
m
tStorage
)()()(
xywzxvzyuInflowzyx
xywzxvzyuOutflowzzyyxx
zyxSource S
S
z
ww
y
vv
x
uu
t
zzzyyyxxx
*
S
z
w
y
v
x
u
t
Szyx
Lim
0S*
The Mass Balance Equations:
0
i
i
x
u
t
0
z
w
y
v
x
u
t
0
i
i
i
ix
u
xu
t
0
zw
yv
xu
z
w
y
v
x
u
t
i
ix
utDt
Dor
zw
yv
xu
tDt
D
000
Dt
D
x
u
Dt
D
z
w
y
v
x
u
Dt
D
i
i
00
i
i
x
uor
z
w
y
v
x
u
MECHANICAL ENGINEERING – FLUID MECHANICS
S
i
i
i
i
xu
x
u
tt
S
i
ix
ut
Momentum Balance Equation:
j
i
ij
j
jjjB
xB
xxxtermsourcedirectionjNet
3
3
2
2
1
1
3,1
jB
xx
uu
t
uj
i
ij
i
jij
For a Newtonian fluid, the stress, σij, is given by the following equation:
ij
i
j
j
i
ijijx
u
x
uP
)
3
2(
3,1)3
2(
jB
x
u
x
uP
xx
uu
t
ujij
i
j
j
i
ij
ii
jij
3,1)3
2(
jB
xx
u
x
u
xx
P
x
uu
t
uj
ji
j
j
i
iji
jij
x
u uu vu wuB
t x y z
2
2 ( )3
P u v u w u
x x x y x y z x z x
Energy Balance Equation:
This directional heat flux is given the symbol qi: i
ix
Tkq
x
qqzy
zyx
VolumeUnit
heatxDirectionNet xxxxxxxxxx
x
q
VolumeUnit
sourceheatxDirectionNet
x
Limitx
0
MECHANICAL ENGINEERING – FLUID MECHANICS
i
ixyx
x
q
x
q
y
q
x
qRateHeat
Body-force work rate = ρ(uBx + vBy + wBz) =ρuiBi
The work term on each face is given by the following equation:
y-face surface force work = (uσyx + vσyy + wσyz)Δx Δz =uiσiy Δx Δz
y
u
y
wvuWorkForceSurfaceyFaceNet
yiiyzyyyx
)(
j
jiiziiyiixii
x
u
z
u
y
u
x
uWorkForceSurfaceNet
Energy balance equation:
ii
j
jii
i
i
i
i Bux
u
x
q
x
eu
t
e
)2/()2/(22 VV
Substitutions for Stresses and Heat Flux:
Using only the Fourier Law heat transfer, the source term involving the heat flux in the energy
balance equation:
z
Tk
zy
Tk
yx
Tk
xx
Tk
xx
Tk
xx
q
iiiii
i
j
i
ij
i
j
j
i
ij
iii
i
x
u
x
u
x
uP
x
Tk
xx
eu
t
e
)
3
2(
j
j
j
i
ijx
u
x
u
2)3
2(
j
i
i
j
j
i
iii
i
x
u
x
u
x
uP
x
Tk
xx
eu
t
e
Dissipation to avoid confusion with the general quantity in a balance equation:
2)3
2(
j
i
i
j
j
i
x
u
x
u
x
uDΦ
MECHANICAL ENGINEERING – FLUID MECHANICS
DΦ
P
x
Tk
xx
eu
t
e
iii
i
The temperature gradient in the Fourier law conduction term may also be written as a gradient
of enthalpy or internal energy:
iT
P
vivi xP
T
cx
e
cx
T
2
111
ip
P
ipi x
P
c
T
x
h
cx
T
11
iT
P
viivii
i
xP
T
cxP
x
e
c
k
xx
eu
t
e
2
11DΦ
Dt
DP
x
P
c
T
xx
h
c
k
xx
hu
t
h
ip
P
iipii
i
1DΦ
Dt
DPT
x
Tk
xx
Tu
t
Tc P
iii
i
p
DΦ
MECHANICAL ENGINEERING – FLUID MECHANICS
General Balance Equations
φ c Γ(φ)
S(φ)
1 1 0 0
u = ux = u1 1 μ xB
xx
w
zx
v
yx
u
xx
P
)
3
2(
v = uy = u2 1 μ yB
yy
w
zy
v
yy
u
xy
P
)
3
2(
w = uz = u3 1 μ zB
zz
w
zz
v
yz
u
xz
P
)
3
2(
e 1 k/cv
iT
P
vi xP
T
cxP
2
11DΦ
h 1 k/cP
Dt
DP
x
P
c
T
x ip
P
i
1DΦ
T cP k
Dt
DPTPDΦ
T cv k
T
PT
DΦ
W(K)
1 ρDK,Mix r(K)
Momentum equation:
)()( * j
i
j
ii
j
i
j
ii
jijS
x
u
xx
PS
x
u
xx
uu
t
u
General Momentum Equations
φ c Γ(φ)
S*(φ)
1 1 0 0
u = ux = u1 1 μ xB
xx
w
zx
v
yx
u
x
)
3
2(
v = uy = u2 1 μ yB
yy
w
zy
v
yy
u
x
)
3
2(
w = uz = u3 1 μ zB
zz
w
zz
v
yz
u
x
)
3
2(
MECHANICAL ENGINEERING – FLUID MECHANICS
Bernoulli’s Equation: This equation has four variables: velocity ( ), elevation ( ), pressure ( ), and density ( ). It also
has a constant ( ), which is the acceleration due to gravity. Here is Bernoulli’s equation:
2
2
1vghP constant
g
vh
g
P
2
2
= constant; g
P
is called pressure head, h is called gravitational head and
g
v
2
2
is called velocity head.
Factors that influence head loss due to friction are:
Length of the pipe ( )
Effective diameter of the pipe ( )
Velocity of the water in the pipe ( )
Acceleration of gravity ( )
Friction from the surface roughness of the pipe ( )
The head loss due to the pipe is estimated by the following equation:
To estimate the total head loss in a piping system, one adds the head loss from the fittings
and the pipe:
Note that the summation symbol ( ) means to add up the losses from all the different
sources. A less compact-way to write this equation is:
Combining Bernoulli’s Equation With Head Loss:
MECHANICAL ENGINEERING – FLUID MECHANICS
Relation between coefficient of viscosity and temperature:
Andrade formula = 3/1
/
TCeA
Stoke's Law: F = 6rv
Terminal Velocity:
Weight of the body (W) = mg = (volume × density) × g gr 3
3
4
Upward thrust (T) = weight of the fluid displaced
= (volume × density) of the fluid × g = gr 3
3
4
Viscous force (F) = rv6
When the body attains terminal velocity the net force acting on the body is zero.
W–T–F =0 or F= W – T
grgrrv 33
3
4
3
46 gr )(
3
4 3
Terminal velocity
grv
)(
9
22
Terminal velocity depend on the radius of the sphere so if radius is made n - fold,
terminal velocity will become n2 times.
Greater the density of solid greater will be the terminal velocity
Greater the density and viscosity of the fluid lesser will be the terminal velocity.
If > then terminal velocity will be positive and hence the spherical body will attain
constant velocity in downward direction.
If < then terminal velocity will be negative and hence the spherical body will attain
constant velocity in upward direction.
Poiseuille’s Formula:
l
rPV
4
or l
rKPV
4
l
rPV
8
4
; where 8
K is the constant of proportionality.
Buoyant Force:
Buoyant force = Weight of fluid displaced by body
MECHANICAL ENGINEERING – FLUID MECHANICS
Buoyant force on cylinder =Weight of fluid displaced by cylinder
insV Value of immersed part of solid
FB = waterp g Volume of fluid displaced
FB= waterp g Volume of cylinder immersed inside the water
BF mg
FB =2
4wp g d
( w mg pVg )
ins s sV plg V p g
2 2
4 4w cylinderp g d x p g d h
w cylinderp x p h
Relation between B, G and M:
GM Bl
GV
; where l = Least moment of inertia of plane of body at water surface, G =
Centre of gravity, B = Centre of buoyancy, and M = Metacentre.
,min( ),xx yyl l l
3
,12
xx
bdl
3
12yy
bdl
V bdx
Energy Equations:
Fnet = Fg + Fp + Fv + Fc + Ft ; where Gravity force Fg, Pressure force Fp, Viscous force Fv ,
Compressibility force Fc , and Turbulent force Ft.
If fluid is incompressible, then Fc = 0
net g p v tF F F F F ; This is known as Reynolds equation of motion.
If fluid is incompressible and turbulence is negligible, then
0, 0c tF F net g p vF F F F ; This equation is called as Navier-Stokes equation.
If fluid flow is considered ideal then, viscous effect will also be negligible. Then
net g pF F F ; This equation is known as Euler’s equation.
Euler’s equation can be written as: 0dp
gdz vdv
MECHANICAL ENGINEERING – FLUID MECHANICS
Dimensional analysis:
Quantity Symbol Dimensions
Mass m M
Length l L
Time t T
Temperature T θ
Velocity u LT -1
Acceleration a LT -2
Momentum/Impulse mv MLT -1
Force F MLT -2
Energy - Work W ML 2T
-2
Power P ML 2T
-3
Moment of Force M ML 2T
-2
Angular momentum - ML 2T
-1
Angle η M 0L
0T
0
Angular Velocity ω T -1
Angular acceleration α T -2
Area A L 2
Volume V L 3
First Moment of Area Ar L 3
Second Moment of Area I L 4
Density ρ ML -3
Specific heat-
Constant Pressure
C p L 2 T
-2 θ
-1
Elastic Modulus E ML -1
T -2
Flexural Rigidity EI ML 3T
-2
Shear Modulus G ML -1
T -2
Torsional rigidity GJ ML 3T
-2
Stiffness k MT -2
MECHANICAL ENGINEERING – FLUID MECHANICS
Angular stiffness T/η ML 2T
-2
Flexibiity 1/k M -1
T 2
Vorticity - T -1
Circulation - L 2T
-1
Viscosity μ ML -1
T -1
Kinematic Viscosity τ L 2T
-1
Diffusivity - L 2T
-1
Friction coefficient f /μ M 0L
0T
0
Restitution coefficient M 0L
0T
0
Specific heat-
Constant volume
C v L 2 T
-2 θ
-1
Boundary layer:
Reynolds number (Re)x
v x v x
v
Displacement Thickness ( *):0
* 1u
dyU
Momentum Thickness ():0
1u u
dyU U
Energy Thickness ( **):2
**
201
u udy
U U
Boundary Conditions for the Velocity Profile: Boundary conditions are as
o (a) 0, 0, 0du
At y udy
; (b) , , 0du
At y u Udy
Turbulent flow:
Shear stress in turbulent flow: v t
du du
dy dy
Turbulent shear stress by Reynold: ' 'u v
Shear stress in turbulent flow due to Prndtle :
2
2 dul
dy
MECHANICAL ENGINEERING – FLUID MECHANICS