lesson 18: i can use basic facts to estimate quotients with two-digit divisors. 5th grade module 2...
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5th Grade Module 2 – Lesson 18
Lesson 18: I can use basic facts to estimate quotients with two-
digit divisors.
5th Grade Module 2 – Lesson 18
Divide By Multiples of 10
360,000 ÷ 6,000 360,000 ÷ 1,000 ÷ 6 360 ÷ 6
60
5th Grade Module 2 – Lesson 18
Divide By Multiples of 10
490,000 ÷ 700
490,000 ÷ 100 ÷ 7 4,900 ÷ 7
700
5th Grade Module 2 – Lesson 18
Divide By Multiples of 10
640,000 ÷ 80
640,000 ÷ 10 ÷ 8
64,000 ÷ 8
8,000
5th Grade Module 2 – Lesson 18
Estimate and Divide
812 ÷ 39 Say the divisor rounded to the nearest ten…÷ 40
Name the multiple of 40 that’s closest
to 812…800
Estimate the value…
20
5th Grade Module 2 – Lesson 18
Estimate and Divide
183 ÷ 31 Say the divisor rounded to the nearest ten…÷ 30
Name the multiple of 30 that’s closest
to 183…180
Estimate the value…
6
5th Grade Module 2 – Lesson 18
Estimate and Divide
437 ÷ 72 Say the divisor rounded to the nearest ten…÷ 70
Name the multiple of 70 that’s closest
to 420…420
Estimate the value…
6
5th Grade Module 2 – Lesson 18
Estimate and Divide
823 ÷ 97 Say the divisor rounded to the nearest ten…÷ 10
0
Name the multiple of 100 that’s closest to
800…800
Estimate the value…
8
5th Grade Module 2 – Lesson 18
Estimate and Divide
8,191 ÷ 92 Say the divisor rounded to the nearest ten…÷ 90
Name the multiple of 90 that’s closest
to 8,100…8,100
Estimate the value…
90
5th Grade Module 2 – Lesson 18
Application Problem
Sandra bought 38 DVD movies for $874. Give an
estimate of the cost of each DVD movie.
Solution on next slide…
5th Grade Module 2 – Lesson 18
Concept Development
8,095 ÷ 23
What’s the whole (or dividend) in this problem?
8,095
What’s the divisor? 23
Let’s use rounding to find an estimated quotient!
First, let’s round the divisor to the nearest ten!
23 ≈ 20Let’s record our estimation
below.
8,095 ÷ 23≈ ____ ÷ 20
We need to round our whole, 8095, to a number that can easily be divided
by 20. Turn and share your ideas to your partner.
We can round 8095 to 8000 since I can use
mental math to divide 8000 by 20.
Now let’s solve.Remember to take out the
10 to help you.
80008000 ÷ 10 ÷ 2 800 ÷ 2 400
5th Grade Module 2 – Lesson 18
2,691 ÷ 48
Take out your journal. Let’s estimate the quotient. What do we do first?
1st – Round the Divisor 48 ≈ 50 2,691 ÷ 48≈ ____ ÷ 502nd – Round the Whole (dividend)
Think…When we round for division we want to make sure our dividend is a multiple of the divisor. We
have to think of the nearest multiple of 50.
2700
Let’s solve.Taking out the 10 in 50.
2700 ÷ 10 ÷ 5 270 ÷ 5
2,691 ÷ 48 ≈ 54
= 54
Problem 2
5th Grade Module 2 – Lesson 18
Problem 3
5,484 ÷ 71Work with your partner and solve the estimated quotient.
Remember we are finding the estimated quotient!
1. Round the Divisor2. List the multiples of the
rounded divisor to find the one that is closest to 70
3. Use the closest multiple as your rounded whole number.
4. Divide using the rounded digits.
5. Check to see if your estimated quotient makes sense.
Volunteer to Share Solution:
Solution on next slide…
5th Grade Module 2 – Lesson 18
Solution 5,484 ÷ 71 ≈ 5,600 ÷ 705,600 ÷ 10 ÷ 7 560 ÷ 7 ≈ 80
5,484 ÷ 71 ≈ 80
5th Grade Module 2 – Lesson 18
Work independently to estimate the quotient. Check your work with your partner.
Solution (use ink tools):
9,215 ÷ 95
5th Grade Module 2 – Lesson 18
Get Ready to Complete theProblem Set on Your Own!
Complete Pages 2.E.33 & 2.E.34You will have 15 minutes to work.
Try your Best!
5th Grade Module 2 – Lesson 18
LET’S DEBRIEF• When estimating Problem 1(g), what did you choose for
your unit, 70 or 80? Why? How did it affect the way you estimated the whole?
• Look back at Problem 2 and 4. How was your approach similar in solving? How was it different?
• When solving Problem 3(b), could a mental math approach have been used? (14 apps x $2 – 14 cents) Explain.