lecture 8: traffic signal transportation engineering

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Lecture 8: Traffic Signal Transportation Engineering

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Page 1: Lecture 8: Traffic Signal Transportation Engineering

Lecture 8: Traffic Signal

Transportation Engineering

Page 2: Lecture 8: Traffic Signal Transportation Engineering

2

Critical LaneThis concept is used for the allocation of the 3600

seconds in the hour to lost time and to productive movement.

The amount of time required for each signal phase is determined by the most intensely used lane which is permitted to move during the phase.

All other lane movement in the phase require less time than the critical lane.

The timings of any signal phase is based on the flow and lost times of the critical lane.

Each signal phase has one and only one critical lane.

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Page 3: Lecture 8: Traffic Signal Transportation Engineering

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Capacity (using critical Lane volume)Capacity can be maximum sum of critical lane volumes

that a signal can accommodate.the max. total volume that can be handled on all

critical lanes for a given time budget (within an hour),

tL total lost time per phaseN is total number of phases in a cycle C is cycle length

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1 36003600 ( )( )( )c LV N t

h C

Page 4: Lecture 8: Traffic Signal Transportation Engineering

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Capacity (using critical Lane volume)

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•the effect of number of phases and cycle time on Vc

•Lost time remains constant through out (h= 2.15s, lost time = 3s/phase)

Page 5: Lecture 8: Traffic Signal Transportation Engineering

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ExampleThe cycle length is 40 sec, 2 phase cycle and saturation headway 2.3sec. What should be the lane numbers for each approach?

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Solution1 3600

3600 (2)(3)( )2.3 40cV

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Adding consideration of v/c ratio and PHF

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(volume-to-capacity) V/C ratio:

flow rate in a period expressed as an hourly equivalent over capacity (saturation flow rate)

the proportion of capacity being utilized

A measure of sufficiency of existing or proposed capacity

V/C ratio = 1.00 is not desirable

Page 8: Lecture 8: Traffic Signal Transportation Engineering

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Adding consideration of v/c ratio and PHF

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Peak Hour Factor (PHF) :

To account for flow variation within an hour

PHF

For 15 min. aggregate volume, PHF =

The lower the value, the greater degree of variation in flow during an hour.

hourly volume (vph)

maximum rate of flow (vph)

V

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Adding consideration of v/c ratio and PHF

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Page 10: Lecture 8: Traffic Signal Transportation Engineering

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Adding consideration of v/c ratio and PHF

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Min. cycle length,

Considering desired v/c ratio,Considering peaking within hour,

Desirable cycle length,

min

13600

L

c

NtC

Vh

min

1PHF 3600

L

c

NtC

Vv c h

Page 11: Lecture 8: Traffic Signal Transportation Engineering

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Adding consideration of v/c ratio and PHF

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Page 12: Lecture 8: Traffic Signal Transportation Engineering

12Effects of right-turning vehicles Right turns can be made from a

Shared lane operation Exclusive lane operation

Traffic signals may allow permitted or protected right turn

Right-turning vehicles look for a gap in the opposing traffic on a permitted turning movement, which is made through a conflicting pedestrian or an opposing vehicle flow.

Right-turning vehicles consume more effective green time than through vehicles.

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Page 13: Lecture 8: Traffic Signal Transportation Engineering

13Effects of right-turning vehicles

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Page 14: Lecture 8: Traffic Signal Transportation Engineering

14Effects of right-turning vehiclesThrough Car Equivalent

Example: with an opposing flow of 700 vph which has no platoon structure, it is observed that the right lane of the figure processes two RT vehicles and three TH vehicles in the same time that the left lane processes 17 TH vehicles. What is the “THcar” equivalent of one right-turning vehicle (RT equivalent) in this case?

3 + 2 ERT = 17 or ERT = 7In this situation, 1 RT vehicle is equivalent to 7 TH vehicles in terms of headway.

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Page 15: Lecture 8: Traffic Signal Transportation Engineering

15Effects of right-turning vehiclesThrough Car Equivalent

depends on the opposingflows, and the number of opposing lanes

The right turn adjustment factor is related to the fraction of RT vehicles and the TH equivalency

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RTf

Page 16: Lecture 8: Traffic Signal Transportation Engineering

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ffec

t o

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urn

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Veh

icle

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Page 17: Lecture 8: Traffic Signal Transportation Engineering

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ExampleExample: consider an approach with 10% RT, two

lanes, permitted RT phasing, a RT equivalency factor of 5, and an ideal saturation headway of 2 sec per veh. Determine

(1) the equivalent saturation headway for this case,(2) the saturation flow rate for approach, and (3) the adjustment factor for the sat. flow rate? (adj.

flow rate / sat flow rate of TH vehicles)

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Page 18: Lecture 8: Traffic Signal Transportation Engineering

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Performance measures

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Delay

Queuing

Stops

Delay most directly affects driver experience.

Page 19: Lecture 8: Traffic Signal Transportation Engineering

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Performance measures

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Stopped Time Delay: time a vehicle stopped waiting to pass the intersection.

Approach Delay:

stopped time + acceleration + deceleration

Travel Time Delay: (actual travel time-desired travel time)

Time-in-queue Delay: Total time from joining a queue to passing the stop line

Page 20: Lecture 8: Traffic Signal Transportation Engineering

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Delay

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Page 21: Lecture 8: Traffic Signal Transportation Engineering

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Webster’s uniform delay (UD) formula

Webster’s Delay Model

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Page 22: Lecture 8: Traffic Signal Transportation Engineering

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Webster’s Delay Model Webster’s uniform delay (UD) formula

Red time,

Height of the triangle,

Area of the triangle, (UD)

Average delay per vehicle,

21

UD=2 1

C g c

v s

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Page 23: Lecture 8: Traffic Signal Transportation Engineering

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Webster’s optimum cycle length

developed based on minimization of overall delay at intersection

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Page 24: Lecture 8: Traffic Signal Transportation Engineering

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Webster’s optimum cycle length D

elay

Page 25: Lecture 8: Traffic Signal Transportation Engineering

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Notes on cycle length

Optimum cycle length is min. delay point of the suitable curve

Unnecessarily long cycle lengths cause substantial delays; short cycle lengths may cause congestion or violate the pedestrian crossing times.

Cycle lengths between 45 and 180 s are used in the field. All cycle lengths typically end in 0 or 5; thus, if the cycle length estimate is 52s, a cycle equal to 50 or 55s should be selected.D

elay

Page 26: Lecture 8: Traffic Signal Transportation Engineering

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Notes on cycle length Optimum cycle length is min. delay point of the

suitable curve

Unnecessarily long cycle lengths cause substantial delays; short cycle lengths may cause congestion or violate the pedestrian crossing times.

Cycle lengths between 45 and 180 s are used in the field. All cycle lengths typically end in 0 or 5; thus, if the cycle length estimate is 52s, a cycle equal to 50 or 55s should be selected.

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Page 27: Lecture 8: Traffic Signal Transportation Engineering

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ExampleConsider an approach volume of 1000 vph, saturation flow rate of 800vphg, cycle length 90 s and g/C ratio 0.55.What average approach delay per vehicle is expected?

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