lecture 3 regression analysis

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Prepared by Suwardo Regression Analysis Mathmatics and Statistics INTRODUCTION TO CHAPTER 11 REGRESSION ANALYSIS EGRESSION ANALYSIS NOTION SIMPLE LINEAR REGRESSION MODEL Model Estima ting Model Parameters Err or and Coefficient of Determination Prediction REGRESSION WITH TRANSFORMED V ARIABLES MULTIPLE LINEAR REGRESSION ANALYSIS Lecture 3

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7/28/2019 Lecture 3 Regression Analysis

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Prepared by SuwardoRegression Analysis

Mathmatics and Statistics

INTRODUCTION TO CHAPTER 11

REGRESSION ANALYSISEGRESSION ANALYSIS

NOTION

SIMPLE LINEAR REGRESSION MODEL

Model

Estimating Model Parameters

Error and Coefficient of Determination

Prediction

REGRESSION WITH TRANSFORMED VARIABLES

MULTIPLE LINEAR REGRESSION ANALYSIS

Lecture 3

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Prepared by SuwardoRegression Analysis

Mathmatics and Statistics

NOTIONOTION Determine the random relationship between

 Y (Dependent Variable, response, r.v.) andX (Independent Variables, regressor, not r.v.)

on the base of n  observations (x1, y1),…, (xn, yn)

The Model Parameters are estimated by

Least Squares Method (LSM).

From the Model we can get Predictions for Y,

or E(Y)

Use the Analysis of Variance (ANOVA) to test

about the parameters and the goodness of fit of 

the model

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Prepared by SuwardoRegression Analysis

Mathmatics and Statistics

7/28/2019 Lecture 3 Regression Analysis

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Prepared by SuwardoRegression Analysis

Mathmatics and Statistics

ESTIMATING MODEL PARAMETERSSTIMATING MODEL PARAMETERS

Using the Least Squares Method, are estimated

by a, b, and we get , the Estimated

Regression Line

bxay ˆ

 

  

  

  

 

 

 

 

 

n

1i

i

n

1i

i

n

1i

i

n

1i

iixy

n

1i

i

2n

1i

i

n

1i

2

ixx

xx

xy

n

1i

2

ii

2

i

n

1i

i

yn

1y,yx

n

1)y(xS

x

n

1x,x

n

1)(xS

where,xbyaand,SSbThen

min!)bxa(y)y(ySSE ˆ

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Prepared by SuwardoRegression Analysis

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ERROR AND ESTIMATING sRROR AND ESTIMATING s2

Sum of Squares of Errors (SSE)

Estimating 2 by

This is an unbiased estimator for  2

The smaller SSE the more successful is the

Linear Regression Model in explaining y

XX

2

xy

yy

n

1i

2

ii

2

i

n

1i

iS

)(SS)xba(y)y(ySSE

ˆ

2n

SSES2

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Example 1 (Continued) :

1 5 85 25 425

2 4 103 16 412

3 6 70 36 420

4 5 82 25 410

5 5 89 25 445

6 5 98 25 4907 6 66 36 396

8 6 95 36 570

9 2 169 4 338

10 7 70 49 49011 7 48 49 336

Sum 58 975 326 4732

94.16 83.9

114.42 130.5

73.90 15.2

94.16 147.9

94.16 26.6

94.16 14.773.90 62.4

73.90 445.2

154.95 197.5

53.64 267.753.64 31.8

iy2

ii )yy(

 1423.5

x20.26195.47y ˆ

  Table? Computations? 

SSE? Estimate s2? 

1423.52

yySSEn

1i

2

ii

ˆ

Estimate 2 by

158.17

1423.52/9

2n

SSES

2

i xi yi xi2 xiyi

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COEFFICIENT OF DETERMINATIONOEFFICIENT OF DETERMI NATION

Coefficient of Determination (R-Sq):

 R 2 = r 2 = SSR/SST = 1 - (SSE/SST); (0 ≤ R2 ≤1)

The greater r 2 the more successful is the

2i

n

1i

2i

n

1i

i2

n

1i

i )yy()y(y)y(ySST

ˆˆ

2n

1i

i )yy(SSR 

ˆ

Total Sum of Squares (SST )

SST = SSE + SSR 

Regression Sum of Squares:Amount of Variation in y  explained by the Model

SSR = SST - SSE

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Prepared by SuwardoRegression Analysis

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Example 1 (Continued) :

1 5 85 25 425

2 4 103 16 412

3 6 70 36 420

4 5 82 25 410

5 5 89 25 445

6 5 98 25 4907 6 66 36 396

8 6 95 36 570

9 2 169 4 338

10 7 70 49 49011 7 48 49 336

Sum 58 975 326 4732

94.16 83.9

114.42 130.5

73.90 15.2

94.16 147.9

94.16 26.6

94.16 14.773.90 62.4

73.90 445.2

154.95 197.5

53.64 267.753.64 31.8

iy2

ii )yy(

  1423.5

7225

10609

4900

6724

7921

96044356

9025

28561

49002304

96129

yi2 i xi yi xi

2 xiyiTable? Compute

SST and r 2 ?

9708.54 

(975)2/11-96129

yn

1y

SSST

22

YY

r2 = 1-SSE/SST

=1-1423.52/9708.54

= 0.8534High Value !

SSE = SYY  – (SXY)2/SXX =9708.54-(-408.9091)2/20.1818=1423.52

SSE other way

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Confidence Interval on the Slope

 A 100(1-α)% CI for the parameter β in the linear regression is

 xxn

S  st 

bb

/ where 2,2/

 

  

Hypothesis Testing on the Significance of Regression (on

the Slope)

Test the hypothesis

H0 :  β = 0 ( there is no relationship between x and Y)

H1:  β  ≠ 0 (the straight-line model is adequate)

Test Statistic: T   – distribution.

Critical Region: |T | > tα/2, n-2 .  xxS S 

bT 

/

  

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Example 1 (Continued) :

x20.26195.47y ˆ

332.6

17.158;1818.20

262.2;05.0

9,025.0

2

9,025.02,2/

 

 

 

 

 xx

 xx

n

S t 

S S 

t t   

Estimated Regression Line ,

 A 95% Confidence Interval on the Slope:

592.26928.13

592.26;928.13

  

bb

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PREDICTION OF E(Y0)=E(Y/x0)

E(Y0)= E(Y/x0)= + x0 can be estimated by:

a + bx0

The (1- ) Confidence Interval for E(Y/x0)

2n

SSES,

S

)x(x

n

1.S.tΔ

,bxaywhere,Δ]y,Δy[

2

xx

2

02n,

0000

ˆˆˆ

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  An estimate for the mean price of 3-year-old

Nissan Z:

Estimated Regression Line , x20.26195.47y ˆ134.69(3)20.26195.47y ˆ

  90% Confidence Interval

148.27],[121.1113.58]134.69,13.58[134.69

13.5888)1.833(7.40(7.4088)t

20.1818

5.2727)(3

11

1

(12.58)tS

)x(x

n

1

StΔ

158.179

1423.52

2n

SSES

Δ]134.69,Δ[134.69

9,0.05

2

9,0.05

xx

2

0

2n,

2

)(

Example 1 (Continued) :

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Regression Analysis

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PREDICTION OF Y0 = Y(x0)

A value of  Y0 = Y(x0) can be estimatedby: a + bx0

The (1- ) Confidence Interval for Y0 = Y(x0) :

2n

SSE

S,S

)xx(

n

1

1.S.t

,bxaywhere,]y,y[

2

xx

2

0

2n,

0000

2

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Regression Analysis

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 An estimate for the price of 3-year-old Nissan Z:

Estimated Regression Line ,  x20.26195.47y ˆ

134.69(3)20.26195.47y ˆ

  90% Confidence Interval

161.45],[107.9326.76]134.69,26.76[134.69

26.76995)1.833(14.5(14.5995)t

20.1818

5.2727)(3

11

11(12.58)tS

)x(x

n

11StΔ

158.179

1423.52

2n

SSES

Δ]134.69,Δ[134.69

9,0.05

2

9,0.05

xx

2

0

2n,

2

)(

Example 1 (Continued) :

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Regression Analysis

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Source of Sum of Degrees of Mean Computed F

Variance Squares freedom Square

Regression 8285.02 1 8285.02 52.380

Error 1423.52 9 158.17

Total 9708.54 10

Example 1 (Continued) :

Testing H0 : = 0, H1 :   0

Taking the significance = 1% = 0.01 

10.5652.380F10.56(1,9)f 2)n(1,f  0.01α

Decision : Reject H0, Accept H1 The linear model is fitted 

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The regression equation is price = 195 - 20.3 age

Predictor Coef SE Coef T P

Constant 195.47 15.24 12.83 0.000

age -20.261 2.800 -7.24 0.000

S = 12.58 R-Sq = 85.3%

 Analysis of Variance

Source DF SS MS F PRegression 1 8285.0 8285.0 52.38 0.000

Residual Error 9 1423.5 158.2

Total 10 9708.5

Statistical output from Minitab

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REGRESSION WITH

TRANSFORMED VARIABLESBy transformation on x or/and on y, certain Non-linear 

Regression Functions become Linear Regression Function.

Then we can apply all the previous method and results.

x1x,

y1yby,xbay

xbax

y1

baxxy

)x(hxby,xbay)x(hbay

)xln(x),yln(yby,xb)aln(yxay

)yln(yby,xb)aln(yeay

****

**

****b

**bx

Examples:

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Regression Analysis

Mathmatics and Statistics

SUMMARY OF CHAPTER 11

REGRESSION ANALYSISEGRESSION ANALYSIS

NOTION

SIMPLE LINEAR REGRESSION MODEL

Model

Estimating Model Parameters

Error and Coefficient of Determination

Prediction

REGRESSION WITH TRANSFORMED VARIABLES MULTIPLE LINEAR REGRESSION ANALYSIS