lecture 1 january 17, 2006. sudhir k. jain, iit kanpur e-course on seismic design of tanks/ january...
TRANSCRIPT
Lecture 1
January 17, 2006
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 2
In this lecture
Types of tanks IS codes on tanks Modeling of liquid
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 3
Types of tanks
Two categories Ground supported tanks
Also called at-grade tanks; Ground Service Reservoirs (GSR)
Elevated tanks Also called overhead tanks; Elevated Service Reservoirs
(ESR)
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 4
Types of tanks
Ground supported tanks Shape: Circular or Rectangular Material : RC, Prestressed Concrete, Steel
These are ground supported vertical tanks Horizontal tanks are not considered in this
course
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 5
Types of tanks
Elevated tanks
Two parts: Container Staging (Supporting tower)
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 6
Types of tanks
Elevated tanks
Container: Material: RC, Steel, Polymer Shape : Circular, Rectangular, Intze, Funnel, etc.
Staging: RC or Steel frame RC shaft Brick or masonry shafts
Railways often use elevated tanks with steel frame staging
Now-a-days, tanks on brick or stone masonry shafts are not constructed
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 7
Use of tanks
Water distribution systems use ground supported and elevated tanks of RC & steel
Petrochemical industries use ground supported steel tanks
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 8
Indian Codes on Tanks
IS 3370:1965/1967 (Parts I to IV) For concrete (reinforced and prestressed)
tanks Gives design forces for container due to
hydrostatic loads Based on working stress design BIS is considering its revision
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 9
Indian Codes on Tanks
IS 11682:1985 For RC staging of overhead tanks Gives guidelines for layout & analysis of
staging More about this code later
IS 803:1976 For circular steel oil storage tanks
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 10
Indian Codes on Tanks
IS 1893:1984 Gives seismic design provisions Covers elevated tanks only Is under revision More about other limitations, later
IS 1893 (Part 1):2002 is for buildings only Can not be used for tanks
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 11
Hydrodynamic Pressure
Under static condition, liquid applies pressure on container. This is hydrostatic pressure
During base excitation, liquid exerts additional pressure on wall and base. This is hydrodynamic pressure This is in additional to the hydrostatic pressure
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 12
Hydrodynamic pressure
Hydrostatic pressure Varies linearly with depth of liquid Acts normal to the surface of the container At depth h from liquid top, hydrostatic
pressure = h
Hydrostatic pressure
h
h
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 13
Hydrodynamic pressure
Hydrodynamic pressure Has curvilinear variation along wall height Its direction is opposite to base motion
Base motion
Hydrodynamic pressure
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 14
Hydrodynamic pressure
Summation of pressure along entire wall surface gives total force caused by liquid pressure Net hydrostatic force on container wall is zero Net hydrodynamic force is not zero
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 15
Hydrodynamic pressure
Hydrostatic pressure
Hydrodynamic pressure
Base motion
Circular tanks (Plan View)
Net resultant force = zero
Net resultant force ≠ zero
Note:- Hydrostatic pressure is axisymmetric; hydrodynamic is asymmetric
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 16
Hydrodynamic pressure
Hydrostatic pressure
Hydrodynamic pressure
Base motion
Net resultant force = zero
Net resultant force ≠ zero
Rectangular tanks (Plan View)
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 17
Hydrodynamic pressure
Static design: Hydrostatic pressure is considered Hydrostatic pressure induces hoop forces and
bending moments in wall IS 3370 gives design forces for circular and
rectangular tanks Net hydrostatic force is zero on container wall Hence, causes no overturning moment on
foundation or staging Thus, hydrostatic pressure affects container
design only and not the staging or the foundation
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 18
Hydrodynamic pressure
Seismic design: Hydrodynamic pressure is considered Net hydrodynamic force on the container is not
zero Affects design of container, staging and
foundation
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 19
Hydrodynamic pressure
Procedure for hydrodynamic pressure & force:
Very simple and elegant Based on classical work of Housner (1963a)
Housner, G. W., 1963a, “Dynamic analysis of fluids in containers subjected to acceleration”, Nuclear Reactors and Earthquakes, Report No. TID 7024, U. S. Atomic Energy Commission, Washington D.C.
We need not go in all the details Only basics and procedural aspects are
explained in next few slides
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 20
Modeling of liquid Liquid in bottom portion of the container moves
with wall This is called impulsive liquid
Liquid in top portion undergoes sloshing and moves relative to wall
This is called convective liquid or sloshing liquid
Convective liquid(moves relative to tank wall)
Impulsive liquid(moves with tank wall)
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 21
Modeling of liquid
Impulsive liquid Moves with wall; rigidly attached Has same acceleration as wall
Convective liquid Also called sloshing liquid Moves relative to wall Has different acceleration than wall
Impulsive & convective liquid exert pressure on wall Nature of pressure is different See next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 22
Modeling of liquid
Impulsive Convective
Hydrodynamic pressure
Base motion
Base motion
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 23
Modeling of liquid
At this point, we will not go into details of hydrodynamic pressure distribution Rather, we will first find hydrodynamic forces Impulsive force is summation of impulsive
pressure on entire wall surface Similarly, convective force is summation of
convective pressure on entire wall surface
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 24
Modeling of liquid
Total liquid mass, m, gets divided into two parts: Impulsive liquid mass, mi
Convective liquid mass, mc
Impulsive force = mi x acceleration Convective force = mc x acceleration
mi & mc experience different accelerations Value of accelerations will be discussed later First we will find mi and mc
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 25
Modeling of liquid
Housner suggested graphs for mi and mc
mi and mc depend on aspect ratio of tanks Such graphs are available for circular &
rectangular tanks See Fig. 2a and 3a of Guidelines Also see next slide
For taller tanks (h/D or h/L higher), mi as fraction of m is more
For short tanks, mc as fraction of m is more
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 26
Modeling of liquid
0
0.5
1
0 0.5 1 1.5 2h/D
0
0.5
1
0 0.5 1 1.5 2h/L
For circular tanks
For rectangular tanks
mi/m
mc /m
mi/m
mc /m
See next slide for definition of h, D, and L
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 27
Modeling of liquid
D
L
Base motion
L
Base motion
Elevation
Plan of Circular tank
Plan of Rectangular tank
h
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 28
Modeling of liquid
Example 1: A circular tank with internal diameter of 8 m, stores 3 m
height of water. Find impulsive and convective water mass.
Solution:Total volume of liquid = /4 x 82 x 3 = 150.8 m3
Total liquid mass, m = 150.8 x 1.0 = 150.8 t
Note:- mass density of water is 1000 kg/m3; weight density of water is 9.81 x 1000 = 9810 N/m3.
D = 8 m, h = 3 m h/D = 3/8 = 0.375.
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 29
0
0.5
1
0 0.5 1 1.5 2h/D
mi/m
mc /m
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 30
Modeling of liquid
From graph, for h/D = 0.375 mi/m = 0.42 and mc/m = 0.56
mi = 0.42 x 150.8 = 63.3 t and
mc = 0.56 x 150.8 = 84.5 t
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 31
Modeling of liquid
Impulsive liquid is rigidly attached to wall Convective liquid moves relative to wall
As if, attached to wall with springs
Rigid
mc
Kc/2Kc/2
mi
Convective liquid(moves relative to wall)
Impulsive liquid(moves with wall)
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 32
Modeling of liquid
Stiffness associated with convective mass, Kc Kc depends on aspect ratio of tank Can be obtained from graph
Refer Fig. 2a, 3a of guidelines See next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 33
Modeling of liquid
mi/m
mc/m
Kch/mg
0
0.5
1
0 0.5 1 1.5 2h/D
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 34
Modeling of liquid
Example 2: A circular tank with internal diameter of 8 m, stores 3 m
height of water. Find Kc.
Solution:Total liquid mass, m = 150.8 t (from Example 1)
= 150.8 x 1000 = 150800 kg g = acceleration due to gravity = 9.81 m/sec2
D = 8 m, h = 3m h/D = 3/8 = 0.375. From graph, for h/D = 0.375; Kc h/mg = 0.65
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 35
Modeling of liquid
Kc = 0.65 mg/h
Kc = 0.65 x150800 x 9.81/3.0 = 320,525.4 N/m
Note: - Unit of m is kg, hence unit of Kc is N/m. If we take m in ton, then unit of Kc will be kN/m.
mi/m
mc/m
Kch/mg
0
0.5
1
0 0.5 1 1.5 2h/D
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 36
Modeling of liquid
Now, we know liquid masses mi and mc
Next, we need to know where these are attached with the wall Like floor mass in building acts at centre of
gravity (or mass center) of floor Location of mi and mc is needed to obtain
overturning effects Impulsive mass acts at centroid of
impulsive pressure diagram Similarly, convective mass
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 37
Modeling of liquid
Impulsive mass acts at centroid of impulsive pressure diagram
Location of centroid: Obtained by dividing the moment due to
pressure distribution by the magnitude of impulsive force
Similarly, location of convective mass is obtained See next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 38
Modeling of liquid
hi
hi, hc can be obtained from graphs They also depend on aspect ratio, h/D or h/L Refer Fig. 2b, 3b of guidelines See next slide
hc
Resultant of impulsive pressure on wall
Resultant of convective pressure on wall
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 39
Modeling of liquid
0
0.2
0.4
0.6
0.8
1
0 0.5 1 1.5 2h/L
hc/h
hi/h
For circular tanks
For rectangular tanks
0
0.2
0.4
0.6
0.8
1
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2h/D
hc/h
hi/h
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 40
Modeling of liquid
Example 3: A circular tank with internal diameter of 8 m, stores 3
m height of water. Find hi and hc.
Solution:
D = 8 m, h = 3m
h/D = 3/8 = 0.375.
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 41
0
0.2
0.4
0.6
0.8
1
0 0.5 1 1.5 2h/D
hc/h
hi/h
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 42
Modeling of liquid
From graph, for h/D = 0.375;
hi/h = 0.375
hi = 0.375 x 3 = 1.125 mand hc/h = 0.55
hc = 0.55 x 3 = 1.65 m
Note :- Since convective pressure is more in top portion, hc > hi.
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 43
Modeling of liquid
Hydrodynamic pressure also acts on base Under static condition, base is subjected to
uniformly distributed pressure Due to base motion, liquid exerts nonuniform
pressure on base This is in addition to the hydrostatic pressure on the
base See next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 44
Modeling of liquid
Hydrostatic pressure on base
Base motion
Hydrodynamic pressure on base
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 45
Modeling of liquid
Impulsive as well as convective liquid cause nonuniform pressure on base Nonuniform pressure on base causes
overturning effect This will be in addition to overturning effect of
hydrodynamic pressure on wall See next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 46
Modeling of liquid
Overturning effect due to wall
pressure
Overturning effect due to base
pressure
hi
Note:- Both the overturning effects are in the same direction
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 47
Modeling of liquid
Total overturning effect of wall and base pressure is obtained by applying resultant of wall pressure at height, hi
* and hc*.
• In place of hi and hc discussed earlier For overturning effect due to wall pressure
alone, resultant was applied at hi For hi and hi
*, see next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 48
Modeling of liquid
hi
h*i
Location of resultant of wall pressure when effect of base pressure is not included
Location of Resultant of wall pressure when effect of base pressure is also included
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 49
Modeling of liquid
Similarly, hc and hc* are defined
hc
h*c
Location of resultant of wall pressure when effect of base pressure is not included
Location of Resultant of wall pressure when effect of base pressure is also included
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 50
Modeling of liquid
hi and hi* are such that
Moment due to impulsive pressure on walls only = Impulsive force x hi
Moment due to impulsive pressure on walls and base = Impulsive force x hi
*
hc and hc* are such that
Moment due to convective pressure on walls only = Convective force x hc
Moment due to convective pressure on walls and base = Convective force x hc
*
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 51
Modeling of liquid
hi* is greater than hi
hc* is greater than hc
Refer Fig. C-1 of the Guidelines hi
* & hc* depend on aspect ratio
Graphs to obtain hi, hc, hi*, hc
* are provided Refer Fig. 2b & 3b of guidelines Also see next slide Please note, hi
* and hc* can be greater than h
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 52
Modeling of liquid
hi/h
hi*/hhc/h
hc*/h
0
0.5
1
1.5
2
2.5
0 0.5 1 1.5 2h/D
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 53
Modeling of liquid
Example 4: A circular tank with internal diameter of 8 m, stores 3 m height of
water. Find hi* and hc
*.
Solution: D = 8 m, h = 3m h/D = 3/8 = 0.375. From graph, for h/D = 0.375;
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 54
Modeling of liquid
hi*/h = 1.1
Hence hi* = 1.1 x 3 = 3.3 m
Similarly, hc*/h = 1.0
Hence, hc* = 1.0 x 3 = 3.0 m
hi/h
hi*/hhc/h
hc*/h
0
0.5
1
1.5
2
2.5
0 0.5 1 1.5 2h/D
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 55
Modeling of liquid
This completes modeling of liquid Liquid is replaced by two masses, mi & mc
This is called mechanical analogue or spring mass model for tank
See next slide
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 56
Modeling of liquid
Rigid
mc
Kc/2Kc/2
mi
hi (hi
*)
hc (hc
*)
mi = Impulsive liquid mass
mc = Convective liquid mass
Kc = Convective spring stiffness
hi = Location of impulsive mass (without considering overturning caused by base pressure)
hc = Location of convective mass (without considering overturning caused by base pressure)
hi* = Location of impulsive mass
(including base pressure effect on overturning)
hc* = Location of convective mass
(including base pressure effect on overturning)
Mechanical analogue or
spring mass model of tank
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 57
Modeling of liquid
mi, mc, Kc, hi, hc, hi* and hc
* can also be obtained from mathematical expressions: These are given in Table C 1 of Guidelines These are reproduced in next two slides
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 58
h
Dh
D
m
mi
866.0
866.0tanh
D
h
h
mgK c 68.3tanh836.0 2
D
hD
h
m
mc
68.3tanh
23.0
375.0h
hi
Dh /
09375.05.0
for 75.0/ Dh
75.0/ Dhfor
D
h
D
h
D
h
h
hc
68.3sinh68.3
0.168.3cosh
1
For circular tanks
1250 -86602
8660.
hD
.tanh
hD
.
h
*hi
for
33.1/ Dh
45.0 33.1/ Dh
for
D
h
D
h
D
h
h
hc
68.3sinh68.3
01.268.3cosh
1*
Modeling of liquid
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 59
For rectangular tanks
125.0
866.0tanh2
866.0*
h
Lh
L
h
hi
for
33.1/ Lh
45.0 33.1/ Lh
for
L
h
L
h
L
h
h
hc
16.3sinh16.3
01.216.3cosh
1*
375.0h
hi for 75.0/ Lh
Lh /
09375.05.0 75.0/ Lhfor
L
h
L
h
L
h
h
hc
16.3sinh16.3
0.116.3cosh
1
L
h
h
mgK c 16.3tanh833.0 2
h
Lh
L
m
mi
866.0
866.0tanh
L
hL
h
m
mc
16.3tanh
264.0
Modeling of liquid
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 60
Modeling of liquid
Note, in Table C-1 of the Guideline, there are two typographical errors in these expressions For circular tank, first expression for hi/h shall
have limit as “for h/D 0.75” For circular tank, in the expression for hi
*/h, there shall be minus sign before 0.125
These two errors have been corrected in the expressions given in previous two slides
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 61
Modeling of liquid
mi and mc are needed to find impulsive and convective forces Impulsive force, Vi = mi x acceleration Convective force, Vc = mc x acceleration
Rigid
mc
Kc/2Kc/2
mi Vi
Vc
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 62
Modeling of liquid
Vi and Vc will cause Bending Moment (BM) in wall
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 63
Modeling of liquid
BM at bottom of wall BM due to Vi = Vi x hi
BM due to Vc = Vc x hc
Total BM is not necessarily Vi X hi+ Vc X hc
More about this, later
Rigid
mc
Kc/2Kc/2
mi Vi
Vc
hi
hc
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 64
Modeling of liquid
Overturning of the container is due to pressure on wall and base Pressure on base does not cause BM in wall
Overturning Moment (OM) at tank bottom OM is at bottom of base slab Hence, includes effect of pressure on base Note the difference between bottom of wall
and bottom of base slab
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 65
Modeling of liquid
OM at bottom of base slab OM due to Vi = Vi x hi
*
BM due to Vc = Vc x hc*
Vi
Vc
Rigid
mc
Kc/2Kc/2
mi
hi*
hc*
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 66
Modeling of liquid
mi and mc will have different accelerations We yet do not know these accelerations
ai = acceleration of mi
ac = acceleration of mc
Procedure to find acceleration, later
Use of mi, mc, hi, hc, hi* and hc
* in next example Acceleration values are assumed
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 67
Modeling of liquid
Example 5:
A circular tank with internal diameter of 8 m, stores 3 m height of water. Assuming impulsive mass acceleration of 0.3g and convective mass acceleration of 0.1g, find seismic forces on tank. Solution:Geometry of tank is same as in previous examples. D = 8 m, h = 3mFrom previous examples:mi = 63.3 t mc = 84.5 t
hi = 1.125 m hc = 1.65 m
hi* = 3.3 m hc
* = 3.0 m
Impulsive acceleration, ai = 0.3g = 0.3 x 9.81 = 2.94 m/sec2
Convective acceleration, ac = 0.1g = 0.1 x 9.81 = 0.98 m/sec2
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 68
Modeling of liquid
Example 5 (Contd..)
Impulsive force, Vi = mi x ai = 63.3 x 2.94 = 186.1 kN
Convective force, Vc = mc x ac = 84.5 x 0.98 = 82.8 kN
Bending moment at bottom of wall due to Vi = Vi x hi
= 186.1 x 1.125 = 209.4 kN-mBending moment at bottom of wall due to Vc = Vc x hc
= 82.8 x 1.65 = 136.6 kN-mOverturning moment at bottom of base due to V i = Vi x hi
*
= 186.1 x 3.3 = 614.1 kN-mOverturning moment at bottom of base due to Vc = Vc x hc
*
= 82.8 x 3.0 = 248.4 kN-m
Sudhir K. Jain, IIT Kanpur E-Course on Seismic Design of Tanks/ January 2006 Lecture 1 / Slide 69
At the end of Lecture 1
In seismic design, mechanical analogue of tanks are used, wherein, liquid is replaced by impulsive & convective masses
These masses and their points of application depend on aspect ratio
Graphs and expressions are available to find all these quantities These are based on work of Housner (1963a)