lampiran b gliserol be1lum fix

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  • 7/25/2019 Lampiran b Gliserol Be1lum Fix

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    LAMPIRAN B

    PERHITUNGAN NERACA PANAS

    Basis perhitungan : 1 jam operasi

    Satuan operasi : kJ/jam

    Temperatur referensi : 25 C = 29815 !

    "eru#ahan panas pa$a peran%angan ini terja$i pa$a pera&atan :

    1' Heater ()*+1,

    2' !o&om -i$ro&isa (!-*+1,

    .' Flash Tank sam 0emak (T*+1,

    ' Cooler3 ()*+2,

    5' Flash Tank 4&isero& (T*+2,

    ' )6aporator 3 ()7*+1,

    ' )6aporator 33 ()7*+2,

    8' Cooler33 ()*+.,

    era%a panas ini menggunakan rumus*rumus perhitungan se#agai #erikut:

    * "erhitungan panas ang masuk $an ke&uar (Smith $kk' 2++5,

    =

    ==T

    !15298Tref

    $T'Cp'n-;

    * "erhitungan panas penguapan (Smith $kk' 2++5,

    70-'n;=

    * "erhitungan panas untuk sistem ang me&i#atkan peru#ahan fasa (

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    Ta#e& 0B'1 >ata !onstanta Cp (J/mo&'!, Be#erapa Sena?a

    Sena?a a B C $ e

    -2@ (&, 1829 2118'1+*1 *1..88'1+*. 1.12'1+* *

    -2@ (g, .+1 *95+'1+

    *.

    .2998.'1+

    *5

    *2+'1+

    *8

    .+228'1+

    *12

    Sum#er:

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    = (21, 1 (2+92, (.+.8, . (.82, . (+,

    = 1'8+ J/mo&'!

    Cp Trig&iseri$a = &Cp'

    = ++51 (1'2895, ++9.9 (1'5+11, +12+ (1'8.2.9,

    +18+. (1'8+,

    = 1'.. J/mo&'!

    LB.1.$ Perhitungan Esti!asi Cp Asa! Le!a%

    sam 0ino&eat (C18-.2@2,

    Cp& = (*C-=, 12 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = (21, 12 (.+.8, 1 (.82, 1 (991,

    = 58.. J/mo&'!

    sam "a&mitat (C1-.2@2,

    Cp& = 1 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 1 (.+.8, 1 (.82, 1 (991,

    = 52+5 J/mo&'!

    sam Stearat (C18-.@2,

    Cp& = 1 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 1 (.+.8, 1 (.82, 1 (991,

    = +.81 J/mo&'!

    sam @&eat (C18-.@2,

    Cp& = 2 (*C-=, 1 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 2 (21, 1 (.+.8, 1 (.82, 1 (991,

    = 5855 J/mo&'!

    Cp sam 0emak = &Cp'

    = ++51 (58.., ++9.9 (52+5,

    +12+ (+.81, +18+. (5855,

    = 5.25 J/mo&'!

    LB.1.& Perhitungan Esti!asi Cp G"iser'"

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    Cp g&isero& = 1 (*C-*, 2 (*C-2*, . (*@-,

    = 1 (2+92, 2 (.+.8, . (,

    = 21599 J/mo&'!

    LB.$ Perhitungan Esti!asi H')($*+(%,-!'"

    "erhitungan estimasi A-of(kJ/mo&, $engan menggunakan meto$e Jo#a%k $apat

    $ipero&eh $ari Ta#e& 2*.88 "err (1999,' "ersamaan ang $igunakan a$a&ah se#agai

    #erikut:

    A-of= 829 ii -'

    Ta#e& 0B'. !ontri#usi 4ugus untuk )stimasi A-of 298

    4ugus (kJ/mo&,

    *C-= *9.

    *C-* 2989

    *C-2* *2+

    *C-.* *5

    *@- *2+8+

    *C@@* *..92

    *C@@- *22

    Sum#er: "err (1999,

    LB.$.1Perhitungan Esti!asi H') ($*+ Trig"iseri#a

    Tri 0ino&eat (C5-98@, : +51

    A-of = 82912(*C-=,1(*C-*,.8(*C-2*,.(*C-.*,.(*C@@*,

    = 82912(*9.,1(2989,.8(*2+,.(*5,.(*..92,

    = *2'+81 kJ/mo&

    Tri "a&mitat (C51-98@2, : 9.9

    A-of = 829 1 (*C-*, (*C-2*, . (*C-.*, . (*C@@*,

    = 829 1 (2989, (*2+, . (*5, . (*..92,

    = *1'5.+9 kJ/mo&

    Tri Stearat (C5-11+@, : 12+

    A-of = 829 1 (*C-*, 5+ (*C-2*, . (*C-.*, . (*C@@*,

    = 829 1 (2989, 5+ (*2+, . (*5, . (*..92,

    = *2'19. kJ/mo&

    Tri @&eat (C5-1+@, : 18+.

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    A-of = 829(*C-=,1(*C-*,(*C-2*,.(*C-.*,.(*C@@*,

    = 829(*9.,1(2989,(*2+,.(*5,.(*..92,

    = *2'11+8 kJ/mo&

    A-ofTrig&iseri$a = fo-'

    = ++51 (*1'2895, ++9.9 (*1'5+11,

    +12+ (*1'8.2.9, +18+. (*1'8+,

    = *2'+.J/mo&'!

    LB.$.$ Perhitungan Esti!asi H') ($*+Asa! Le!a%

    sam 0ino&eat (C18-.2@2,

    A-of = 829 (*C-=, 12 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 829 (*9., 12 (*2+, 1 (*5, 1 (*22,

    = *21+8 kJ/mo&

    sam "a&mitat (C1-.2@2,

    A-of = 829 1 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 829 1 (*2+, 1 (*5, 1 (*22,

    = *2.8 kJ/mo&

    sam Stearat (C18-.@2,

    A-of = 829 1 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 829 1 (*2+, 1 (*5, 1 (*22,

    = *12 kJ/mo&

    sam @&eat (C18-.@2,

    A-of = 829 2 (*C-=, 1 (*C-2*, 1 (*C-.*, 1 (*C@@-*,

    = 829 2 (*9., 1 (*2+, 1 (*5, 1 (*22,

    = *.1+ kJ/mo&

    A-ofsam 0emak = f-'

    = ++51 (*21+8, ++9.9 (*2.8,

    +12+ (*12, +18+. (*.1+,

    = *.221 kJ/mo&

    LB.$.& Perhitungan Esti!asi H')G"iser'"

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    A-ofg&isero& = 1 (*C-*, 2 (*C-2*, . (*@-,

    = 1 (2989, 2 (*2+, . (*2+8+,

    = *522 kJ/mo&

    LB.& Neraa Panas pa#aHeater (E/01

    Temperatur #ahan masuk = .+ C = .+.15 !

    Temperatur #ahan ke&uar = 1++ C = ..15 !

    Neraa Panas T'ta"

    "anas masuk "anassteam= "anas !e&uar

    ;1 ;Steam = ;2

    Ta#e& 0B' !omposisi Trig&iseri$a

    Trig"iseri#a K'!p'sisiMassa Trig"iseri#a

    (%g-a!

    !

    (%g-a!

    BM

    (%g-%!'"

    n

    (%!'"-a!Tri 0ino&eat ++51

    5'9928+

    +'12. 891 5.

    Tri "a&mitat ++9.9 5'1.2 8+.5 +8

    Tri Stearat +12+ 8'11.8+ 89151 91+

    Tri @&eat +18+. 12'+.8+5 885 1.+

    T'ta" 23450

    a' "anas ang masuk (;1, pa$a suhu .+ C

    ; = n ' Cp ' DT

    &ur 1

    ;1T4 = n1

    T4E Cp T4E T

    HEATER

    Trig&iseri$a

    ir

    T = .+ C

    1 2

    Steam

    T = 12+ C

    Trig&iseri$a

    ir

    T = 1++ C

    !on$ensat

    T = 1++ C

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    = 8+ kmo&/jam ' 1'..kJ/kmo&'! ' (.+.15 F 29815, !

    = 52'+18 kJ/jam

    ;1air = =

    =

    !15.+.T

    !15298Tref

    &air1 $TCpEn

    = 1 kmo&/jam E .1 kJ/kmo&

    = 2'8+9 kJ/jam

    #' "anas ang ke&uar (;out, pa$a suhu 1++ C

    &ur 2

    ;2T4 = n1

    T4E CpT4E T

    = 8+ kmo&/jam E 1'..kJ/kmo&'!' (..15 F 29815, !

    = 9'8+'2812 kJ/jam

    ;2air = =

    =

    KT

    KTref

    lair dTCpn15..

    15298

    2 E

    = 1 kmo&/jam E .1kJ/kmo&

    = .+'2.kJ/jam

    ;Steam = ;outF ;in

    = (9'8+'2812 F .+'2., kJ/Jam

    = 9'+8'1+51. kJ/Jam

    Steamang $igunakan pa$a heater a$a&ah superheated steamang $ia&irkan

    $ari e6aporator 3 $engan suhu 12+ C (.9.15 !, $an ke&uar se#agai kon$ensat pa$a

    suhu 1++ C (..15 !,' >ari Ta#e& '2 untuksuperheated steamSmith $kk' (2++5,

    $iketahui $ata #erikut:

    - (12+ C, = 2'1.2 kJ/kg

    -7(1++ C, = 2'++ kJ/kg

    -0(1++ C, = 19+ kJ/kg

    !an$ungan panassteam:

    G = H- (12+ C, F - (1++ C,I H-7(1++ C, F -0(1++ C,I

    = 2'52 kJ/kg

    Banaknasteamang $iper&ukan :

    m =G

    ;

    =kJ/jam2'52

    kJ/jam1.9'+8'1+5= .'8.+29 kg/jam

    Ta#e& 0B'5 era%a "anas pa$aHeater()*+1,

    K'!p'nenMasu% (%,-a! Ke"uar (%,-a!

    1 $

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    Trig&iseri$a 52'+18 9'8+'2812

    ir 2'8+9 .+'2.

    Steam 9'+8'1+51.

    T'ta" 1+'+8'9+8 1+'+8'9+8

    LB.5 Neraa Panas pa#a K'"'! Hi#r'"isa (KH/01

    Temperatur #ahan masuk = 1++ C = ..15 !

    Temperatur #ahan ke&uar = 255 C = 52815 !

    Neraa Panas T'ta"

    "anas masuk "anassteam "anas

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    Ta#e& 0B' !omposisi Trig&iseri$a ang !e&uar $ari !o&om -i$ro&isa(!-*+1, &ur

    Trig"iseri#a K'!p'sisiMassa Trig"iseri#a

    (%g-a!

    !

    (%g-a!

    BM

    (%g-%!'"

    n

    (%!'"-a!Tri 0ino&eat ++51

    1.199

    98 891 ++9

    Tri "a&mitat ++9.9 12.9 8+.5 ++2

    Tri Stearat +12+ 159. 89151 ++2

    Tri @&eat +18+. 2.8+ 885 ++.

    T'ta" 0413

    Ta#e& 0B'8 !omposisi sam 0emak ang !e&uar $ari !o&om -i$ro&isa(!-*+1,

    Asa! Le!a% K'!p'sisiMassa Asa!

    Le!a%

    !

    (%g-a!

    BM

    (%g-%!'"

    n

    (%!'"-a!

    sam 0ino&eat ++51

    2'925.

    .812. 28+5 1.8.

    sam "a&mitat ++9.9 588+5 25. 2288

    sam Stearat +12+ 882 289 258

    sam @&eat +18+. 11188 282 19

    T'ta" $$642+

    a' "anas ang masuk (;in,; = n E Cp E DT

    &ur 2

    ;2T4 = 9'8+'2812 kJ/jam

    ;2ir = .+'2. kJ/jam

    &ur 19

    ;19T4 = n19

    T4CpT4DT

    = ++ kmo&/jam 1'..kJ/kmo&'! (..15 * 29815, !

    = 8'8.2 kJ/jam

    &ur .

    ir proses masuk pa$a suhu .+ C

    ;.air = =

    =

    !15.+.T

    !15298Tref

    &air. $T'CpEn

    = 1 kmo&/jam .1 kJ/kmo&

    = .+'2. kJ/jam

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    ;in = ;2T4 ;

    2ir ;19T4 ;

    .air

    = (9'8+'2812 .+'2. 8'8.2 .+'2., kJ/jam,

    = 88'9'2.1kJ/Jam

    #' "anas ang ke&uar (;out, pa$a suhu 25+ C

    &ur

    ;T4 = nT4Cp T4DT

    = +22 kmo&/jam 1'..kJ/kmo&'! (52.15 * 29815, !

    = 8'2.8 kJ/jam

    ;4&isero& = n4&isero&Cp 4&isero&DT

    = 215 kmo&/jam 21599 kJ/kmo&'! (52.15 * 29815, !

    = 1'.19'2++1 kJ/jam

    ;ir =

    ++

    !1552.

    !15..

    670

    !15..

    !15.+.

    &air

    $TCp-$TCpEn

    = [ ]kmo&

    kJ+15+'1+2+5'+129'5E

    jam

    kmo&51 ++

    = 2'+1'88 kJ/jam

    &ur 5

    ;5T4 = n5T4Cp T4DT

    = ++5 kmo&/jam 1'..kJ/kmo&'! (52.15 * 29815, !

    = 2+'858. kJ/jam

    ;5

    sam 0emak = n5

    sam 0emak

    Cp sam 0emak

    DT= 81 kmo&/jam 5.59 kJ/kmo&'! (52.15 * 29815, !

    = 1+'.2'2.1+ kJ/jam

    ;5ir =

    ++

    !1552.

    !15..

    670

    !15..

    !15.+.

    &air5 $TCp-$TCpn

    = [ ]kmo&

    kJ+15+'1+2+5'+129'5

    jam

    kmo&+ ++

    = '9..'52+8. kJ/jam

    ;out = ;T4 ;

    4&isero& ;ir ;

    5T4 ;5sam 0emak ;

    5ir

    = (8'2.8 1'.19'2++1 2'+1'88 2+'858.1+'.2'2.1+ '9..'52+8., kJ/jam

    = 81'+8'12. kJ/Jam

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    r = 215 kmo&/jam

    D-

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    = H*11'11'9. 8'9..'51.11I kJ/jam

    = *2'181'1.25 kJ/jam

    ;Steam = ;out*$t

    $;F ;in

    = H81'+8'12. F (*2'181'1.25, F 2'88'8.I kJ/jam

    = 8+'..1'198.2 kJ/Jam

    nvcc

    Steamang $igunakan a$a&ahsuperheated steampa$a suhu 28+ C (55.15 !,

    $an ke&uar se#agaisuperheated steampa$a suhu 2+ C (5..15 !,' >ari Ta#e& '2

    untuksuperheated steamSmith $kk' (2++5, $iketahui $ata #erikut:

    - (28+ C, = .'+. kJ/kg

    - (2+ C, = 2'998 kJ/kg!an$ungan panassteam:

    D- = - (28+ C, F - (2+ C,

    = (.'+. * 2'998, kJ/kg = .99 kJ/kg

    Banaknasteamang $iper&ukan :

    m =-

    ;

    =kJ/kg.99

    kJ/jam.28+'..1'198= 2'+1+'29+25 kg/jam

    Ta#e& 0B'9 era%a "anas pa$a !o&om -i$ro&isa (!-*+1,

    K'!p'nen Masu% (%,-a! Ke"uar (%,-a!

    $ & 1* 5 3

    C"@ 9'8+'2812 8'8.2 21'89. 18'+.

    ir .+'2. 58'8982. 9'92.'.+8.8 5'5'+.2

    sam 0emak 29'52'2.182

    4&isero& .'+8'181

    Steam +'595'2+

    "anas

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    Temperatur #ahan masuk = 25+ C = 52.15 !

    Temperatur #ahan ke&uar = 11+ C = .8.15 !

    Neraa Panas T'ta"

    "anas masuk = "anas !e&uar

    ;5 = ; ;

    a' "anas ang masuk (;in, pa$a suhu 25+ C

    &ur 5

    ;5T4 = 2+'858. kJ/jam

    ;5sam 0emak = 1+'.2'2.1+ kJ/jam

    ;5ir = '9..'52+8. kJ/jam

    ;in = ;5T4 ;

    5sam 0emak ;5ir

    = 1'28+'929 kJ/jam

    #' "anas ang ke&uar (;out, pa$a suhu 11+ C

    &ur

    ;ir = =

    =

    !15.8.T

    !15298Tref

    6air $TCpn

    = .'8 kmo&/jam E .5'29 kJ/kmo&

    = 1'299'85+8 kJ/jam

    &ur

    ;ir = =

    =

    !15.8.T

    !15298Tref

    6air $TCpn

    = 921 kmo&/jam E .5'29 kJ/kmo&

    = .2'9.52 kJ/jam;T4 = n

    T4E Cp T4E DT

    = ++5 kmo&/jam E 1'..kJ/kmo&'! E (.8.15 * 29815, !

    = '99225 kJ/jam

    ;sam 0emak = nsam 0emakE Cp sam 0emakE DT

    = 81 kmo&/jam E 5.59 kJ/kmo&'! E (.8.15 * 29815, !

    = .'9+1'2+51 kJ/jam

    ;out = ;ir ;

    ir ;T4 ;

    sam 0emak

    = 5'5.'+1. kJ/jam

    ;&oss = ;inF ;out

    = (1'28+'929 * 5'5.'+1., kJ/jam

    FLASH TANK

    S 0)!

    5

    sam 0emak

    Trig&iseri$a

    ir

    T = 25+ C

    sam 0emak

    Trig&iseri$a

    ir

    T = 11+ C

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    = 11''91.1 kJ/jam

    Ta#e& 0B'1+ era%a "anas pa$aFlash Tanksam 0emak (T*+1,

    K'!p'nenMasu% (%,-a! Ke"uar (%,-a!

    3 6 2

    sam 0emak 1+'.2'2.1+ .'9+1'2+51

    ir '9..'52+8. 1'299'85+8 .2'9.52

    Trig&iseri$a 2+'858. '99225

    ;&oss 11''91.1

    Su7 T'ta" 12.$+0.*$*426 1$.62$.156415 5.$13.2504*2

    T'ta" 12.$+0.*$*426 12.$+0.*$*426

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    LB.6 Neraa Panas pa#a Cooler(E/0$

    Temperatur #ahan masuk = 11+ C = .8.15 !

    Temperatur #ahan ke&uar = .+ C = .+.15 !

    Neraa Panas T'ta"

    "anas masuk = "anas ang $iserap ir "en$ingin "anas !e&uar

    ; = ;air pen$ingin ;8

    a' "anas ang masuk (;in, pa$a suhu 11+ C

    ; = n E Cp E DT

    &ur

    ;ir = .2'9.52 kJ/jam

    ;T4 = '99225 kJ/jam

    ;sam 0emak = .'9+1'2+51 kJ/jam

    ;in = ;T4 ;

    sam 0emak ;ir

    = '2.'1228 kJ/jam

    #' "anas ang ke&uar (;out, pa$a suhu .+ C&ur 8

    ;8ir = =

    =

    !15.+.T

    !15298Tref

    &air8 $T'CpEn

    = 921 kmo&/jam E .1 kJ/kmo&

    = .'528 kJ/jam

    ;8T4 = n8T4E Cp T4E DT

    = ++5 kmo&/jam E 1'..kJ/kmo&'! E (.+.15 * 29815, !

    = 2'82+8+ kJ/jam

    ;8sam 0emak = n8sam 0emakE Cp sam 0emakE DT

    = 81 kmo&/jam E 5.59 kJ/kmo&'! E (.+.15 * 29815, !

    ir "en$ingin Bekas

    CLER

    5+ oC

    8

    sam 0emakir

    Trig&iseri$a

    T = 11+ C

    sam 0emak

    ir

    Trig&iseri$a

    T = .+ C

    ir "en$ingin

    25

    o

    C

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    = 1'.'891 kJ/jam

    ;out = ;8T4 ;

    8sam 0emak ;8ir

    = 2.'2+22 kJ/jam

    "anas ang $iserap air pen$ingin :

    ;s = ;in* ;out

    = ('215'+9 F 1'.8.'1989, kJ/jam

    = 2'85+'992.9kJ/jam

    ir pen$ingin ang $igunakan a$a&ah air $engan suhu .+ C $an ke&uar

    se#agai air pen$ingin #ekas pa$a suhu 5+ C' >ari Ta#e& '1 Smith $kk' (2++5,

    $iketahui $ata #erikut:

    - (25C, = $T(&,Cp29815

    29815 = 1+89 kJ/kg

    - (5+C, = $T(&,Cp.2.15

    29815

    = 2+9.+ kJ/kg

    D- = - (5+ C, F - (.+ C,

    = 2+9.+ kJ/kg F 1+89 kJ/kg

    = 1+1 kJ/kg

    Jum&ah air pen$ingin ang $iper&ukan :

    m = -

    ;

    =kJ/kg1+1

    kJ/jam.92'85+'992

    = 2'.+5 kg/jam

    Ta#e& 0B'11 era%a "anas pa$a Cooler()*+2,

    K'!p'nenMasu% (%,-a! Ke"uar (%,-a!

    2 +

    ir .2'9.52 .'528

    sam 0emak .'9+1'2+51 1'.'891

    Trig&iseri$a '9925 2'82+8+

    ir "en$ingin 2'85+'992.9

    T'ta" 5.$13.2504*2 5.$13.2504*2

    LB. 2 Neraa Panas Pa#a Flash TankG"iser'" (8T 9 0$

    4&isero&

    ir

    Trig&iseri$a

    T = 11+ oC

    " = 1 atm

    FLASH TANK403S)

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    Temperatur #ahan masuk = 25+ C = 52.15 !

    Temperatur #ahan ke&uar = 11+ C = .8.15 !

    Neraa Panas T'ta"

    "anas masuk = "anas ke&uar

    ; = ;9 ;1+

    a' "anas ang masuk (;in, pa$a suhu 25+ C

    &ur

    ;T4 = 8'2.8 kJ/jam

    ;g&isero& = 1'.19'2++1 kJ/jam

    ;ir = 2'+1'88 kJ/jam

    Tota& "anas masuk

    ; = .'8+5'511 kJ/jam

    #' "anas ang ke&uar (;out, pa$a suhu 11+ C

    &ur 9

    ;9ir = =

    =

    !15.8.T

    !15298Tref

    6air9 $T'CpEn

    = (5'9'5 kg/jam / 18+2 kg/kmo&, E .2'29 kJ/kmo&

    = ..12 kmo&/jam E .2'29 kJ/kmo&

    = 11'98'82 kJ/jam

    &ur 1+o& Trig&iseri$a ke&uar :

    Tri 0ino&eat = 1929 kg/jam / 28+5 kg/kmo& = ++2 kmo&/jam

    Tri iristat = .5 kg/jam / 228.8 kg/kmo& = ++1 kmo&/jam

    Tri "a&mitat = 15 kg/jam / 25. kg/kmo& = ++9 kmo&/jam

    Tri Stearat = 919 kg/jam / 289 kg/kmo& = ++1 kmo&/jam

    Tri @&eat = 9 kg/jam / 282 kg/kmo& = ++9 kmo&/jam

    Tota& mo& Trig&iseri$a = +22 kmo&/jam

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    ;1+T4 = n1+T4E Cp T4E DT

    = +22 kmo&/jamE1'..kJ/kmo&'!E(.8.15 ! F 29815 !,

    = 1'.1 kJ/jam

    ;1+ir = =

    =

    !15.8.T

    !15298Tref

    6air1+ $TCpEn

    = (1'9.9 kg/jam / 18+2 kg/kmo&, E .2'29 kJ/kmo&

    = 829. kmo&/jam E .2'29 kJ/kmo&

    = 2'92'18 kJ/jam

    ;1+4&isero& = n1+4&isero&E Cp 4&isero&E DT

    = (25++ kg/jam / 92+9 kg/kmo& , E 21599 kJ/kmo&'! E

    (.8.15 ! F 29815 !,

    = 98'.5+ kJ/jam

    Tota& "anas !e&uar = ;9 ;1+

    = 11'98'82 kJ/jam .'2.'+.18 kJ/jam

    = 15'121'229+ kJ/jam

    "anas ang hi&ang ke &ingkungan

    ;&oss = ;in* ;out

    = .'8+5'511 kJ/jam * 15'121'229+ kJ/jam

    = 8'8.'885 kJ/jam

    Ta#e& 0B'12 era%a "anas &ash Tank 4&isero& (T*+2,

    K'!p'nenMasu% (%,-a! Ke"uar (%,-a!

    5 * 10

    ir 2'+1'88 11'98'82 2'92'18

    4&isero& 1'.19'2++1 98'.5+

    Trig&iseri$a 8'2.8 1'.1

    ; &oss 8'8.'885

    Su7 T'ta" 6&.+03.311452 11.6*+.6+642$ 3$.15+.1*6451

    T'ta" 6&.+03.311452 6&.+03.311452

    LB. + Neraa Panas Pa#a E:ap'rat'r I (E;/01

    )7"@

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    Temperatur #ahan masuk = 8+ C = .5.15 !

    Temperatur #ahan ke&uar = 1++ C = ..15 !

    Neraa Panas T'ta"

    "anas masuk = "anas ke&uar

    ;1. ;Steam = ;1 ;15

    a' "anas ang masuk (;in, pa$a suhu 8+ C

    &ur 1.

    ;1.g&isero& = n1.4&isero&E Cp 4&isero&E DT

    = 115 kmo&/jam E 21599 kJ/kmo&'! E (.5.15 ! F 29815 !,

    = 1.'5++++ kJ/jam

    ;1.air = =

    =

    !15.5.T

    !15298Tref

    6air1. $TCpEn

    = 829. kmo&/jam E '1918 kJ/kmo&

    = .'+891 kJ/jam

    Tota& "anas masuk

    ;1. = ;1.g&isero& ;1.air

    = 81'5891 kJ/jam

    #' "anas ang ke&uar (;out, pa$a suhu 1++ C

    &ur 1

    ;1air = =

    =

    !15..T

    !15298Tref

    6air1 $TCpEn

    = (1'1.19 kg/jam / 18+2 kg/kmo&, E .+'252. kJ/kmo&

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    = 281 kmo&/jam E .+'252. kJ/kmo&

    = 1'9++'.5+8 kJ/jam

    &ur 15

    ;15air = =

    =

    !15..T

    !15298Tref

    6air15 $TCpEn

    = (28 kg/jam / 18+2 kg/kmo&, E .+'252. kJ/kmo&

    = '.8+2 kJ/jam

    ;15g&isero& = n154&isero&E Cp 4&isero&E DT

    = 215 kmo&/jam E 21599 kJ/kmo&' ! E (..15 F 29815 !,

    = 55'9951 kJ/jam

    Tota& "anas !e&uar = ;1air ;15air ;15g&isero&

    = .'+5'92'9+ kJ/jam

    ;Steam = ;outF ;in

    = .'+5'92'9+ kJ/jam * 81'5891 kJ/jam

    = 2'58'..5 kJ/jam

    Steam ang $igunakan a$a&ah superheated steam ang $ia&irkan $ari ko&om

    hi$ro&isa $engan suhu 2+ C (5..15 !, $an ke&uar se#agai superheated steampa$a

    suhu 12+ C (.9.15 !,' >ari Ta#e& '2 untuksuperheated steamSmith $kk' (2++5,

    $iketahui $ata #erikut:

    - (2+ C, = 2'998 kJ/kg

    - (12+ C, = 2'1.2 kJ/kg

    !an$ungan panassteam:

    D- = - (2+ C, F - (12+ C,

    = (2'998 F 2'1.2, kJ/kg = 281 kJ/kg

    Banaknasteamang $iper&ukan :

    m =-

    ;

    =kJ/kg281

    kJ/jam52'58'..= 9'29+9 kg/jam

    Ta#e& 0B'1. era%a "anas )6aporator 3 ()7*+1,

    K'!p'nen

    Masu% (%,-a! Ke"uar (%,-a!

    1& 15 13

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    ir .'+891 2'+2'5992 '.8+2

    4&isero& 1.'5++++ 55'9951

    Steam 2'58'..5

    Su7 T'ta" $.05$.3**4$2 1.0$&.&6&465T'ta" &.063.*6$.*0 &.063.*6$.*0

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    LB. * Neraa Panas Pa#a E:ap'rat'r II (E;/0$

    Temperatur #ahan masuk = 1++ C = ..15 !

    Temperatur #ahan ke&uar = 12+ C = .9.15 !

    Neraa Panas T'ta"

    "anas masuk = "anas ke&uar

    ;15 ;Steam = ;1 ;1

    a' "anas ang masuk (;in, pa$a suhu 1++ C&ur 15

    ;15g&isero& = .9'...8 kJ/jam

    ;15air = '.15 kJ/jam

    Tota& "anas masuk

    ;15 = 1'+2.'.. kJ/jam

    #' "anas ang ke&uar (;out, pa$a suhu 12+ C

    &ur 1

    ;1air = =

    =

    !15.9.T

    !15298Tref

    6air1 $TCpEn

    = 1+1 kmo&/jam E +'5.+81 kJ/kmo&

    = 5'98.+. kJ/jam

    &ur 1

    )7"@

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    ;1air = =

    =

    !15.9.T

    !15298Tref

    6air1 $TCpEn

    = 1+ kmo&/jam E .+'252. kJ/kmo&

    = 5'98.+ kJ/jam

    ;1g&isero& = n1

    4&isero&E Cp 4&isero&E DT

    = 215 kmo&/jam E 21599 kJ/kmo&' ! E (.9.15 F 29815 !,

    = .9'...8 kJ/jam

    Tota& "anas !e&uar = ;1air ;1air ;

    1g&isero&

    = 1'+'511 kJ/jam

    ;Steam = ;outF ;in

    = 1'+'511 kJ/jam F 1'+.'.. kJ/jam

    = 1'151+8 kJ/jam

    Steam ang $igunakan a$a&ah superheated steam ang $ia&irkan $ari ko&om

    hi$ro&isa $engan suhu 2+ C (5..15 !, $an ke&uar se#agai superheated steampa$a

    suhu 15+ C (2.15 !,' >ari Ta#e& '2 untuksuperheated steamSmith $kk' (2++5,

    $iketahui $ata #erikut:

    - (2+ C, = 2'998 kJ/kg

    - (15+ C, = 2'2+ kJ/kg

    !an$ungan panassteam:

    D- = - (2+ C, F - (15+ C,

    = (2'998 F 2'2+, kJ/kg = 21828 kJ/kg

    Banaknasteamang $iper&ukan :

    m =-

    ;

    =kJ/kg21828

    kJ/jam1'151+8= 18852 kg/jam

    Ta#e& 0B'1 era%a "anas )6aporator 33 ()7*+2,

    K'!p'nenMasu% (%,-a! Ke"uar (%,-a!

    1& 15 13

    ir '.8+2 5'98.+. 5'98.+

    4&isero& 55'9951 .9'...8

    Steam 1'151+8

    Su7 T'ta" 1.065.315421 362.*+&40& 5*6.3&146+

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    T'ta" 1.065.315421 1.065.315421

    LB. 10 Neraa Panas pa#a C''"er (E/0&

    Temperatur #ahan masuk = 12+ C = .9.15 !

    Temperatur #ahan ke&uar = .+ C = .+.15 !

    Neraa Panas T'ta"

    "anas masuk = "anas ang $iserap ir "en$ingin "anas !e&uar;1 = ;air pen$ingin ;

    18

    a' "anas ang masuk pa$a suhu 12+ C

    &ur 1

    ;1air = 5'98.+ kJ/jam

    ;1g&isero& = .9'...8 kJ/jam

    era%a "anas asuk

    ;1 = 9'5.18 kJ/jam

    #' "anas ang ke&uar pa$a suhu .+ C

    &ur 18

    ;18ir= =

    =

    !15.+.T

    !15298Tref

    &air18 $TCpEn

    = 1+ kmo&/jam E .1 kJ/kmo&

    = 5251+ kJ/jam

    ;

    18

    g&isero& = n

    18

    4&isero&E Cp 4&isero&E DT

    ir "en$ingin

    T = .+ oC

    " = 1 atm

    4&isero&

    ir

    T = 12+ oC

    " = 1 atm

    4&isero&

    ir

    T = .+ oC

    " = 1 atm

    CLER1 18+

    ir "en$ingin

    T = 5+ oC" = 1 atm

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    = 215 kmo&/jam E 1'..kJ/kmo&'! E (.+.15 * 29815, !

    = 29'.155 kJ/jam

    era%a "anas !e&uar

    ;18 = ;18ir ;18g&isero&

    = 29'8+ kJ/jam

    "anas ang $iserap air pen$ingin :

    ;s = ;in* ;out

    = (9'5.18 F 29'8+, kJ/jam

    = '5.18 kJ/jam

    ir pen$ingin ang $igunakan a$a&ah air $engan suhu .+ C $an ke&uar

    se#agai air pen$ingin #ekas pa$a suhu 5+ C' >ari Ta#e& '1 Smith $kk' (2++5,

    $iketahui $ata #erikut:

    - (25C, = $T(&,Cp29815

    29815

    = 1+89 kJ/kg

    - (5+C, = $T(&,Cp.2.15

    29815

    = 2+9.+ kJ/kg

    D- = - (5+ C, F - (.+ C,

    = 2+9.+ kJ/kg F 1+89 kJ/kg

    = 1+1 kJ/kg

    Jum&ah air pen$ingin ang $iper&ukan :

    m =-

    ;

    =kJ/kg1+1

    kJ/jam'5.18

    = '99 kg/jam

    Ta#e& 0B'15 era%a "anas pa$a Cooler ()*+.,

    K'!p'nenMasu% (%,-a! Ke"uar (%,-a!

    12 1+

    ir 5'98.+ 5251+

    4&isero& .9'...8 29'.155

    ir "en$ingin '91+.

    T'ta" 5*6.3&146+ 5*6.3&146+

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