lab reprot heat capacity
TRANSCRIPT
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Table of Contents
Table of Contents......................................................................................................................2
Theoretical background...........................................................................................................3
Experimental Setup..................................................................................................................4
Experiment................................................................................................................................6Results........................................................................................................................................8
References ...............................................................................................................................11
Apendix ....................................................................................................................................12
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Theoretical background
First, we can define the specific heat capacity of a material as the quantity of energy
needed to raise the temperature of one gram of a substance by one degree Kelvin. For a
substance with mass m heated with energy dQ with temperature change of dT has a specific
heat capacity with the following relation:
Knowing this relation from thermodynamics: dU=dQ-pdv; and assuming that our
sample is supplied with heat energy with no volume change. Therefore the heat energy supplied
is assumed to be equal the internal energy of the sample.
There are two main contributions for the internal energy term U:
Phonons: phonons can be described as lattice vibrations. This contribution is
temperature dependent but for T>1K.
o The Debye model approximation states that the contribution for phonons for
different temperature ranges as:
At sufficiently high temperatures: The specific heat capacity contribution
is almost equals to 3R 25J/mol/k.
At low temperatures: The specific heat capacity contribution is almost
observed as T3 dependence.
Conduction Electrons: only in metals, the conduction electrons which are thermally
excited contribute to the electrical conductivity. This contribution dominates at T
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So we can express the total specific heat capacity of a metal due to the contributions of
both the phonons and the conduction electrons which is related to the following equation:
Where ; R is the gas constant equals to 8.314 and is the Debye
temperature.
If we plot a relation between and , we can calculate A from the slope so we can
determine the Debye temperature for the material and the sommerfeld constant form the
intercept.
Experimental Setup
The following instrument was used as the main apparatus for the experiment:
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Fig. 1: Schematic representation of the equipment used for determining the molar heat
capacity of the copper sample at low temperatures.
In the centre of the equipment is the object of interest the sample: copper cylinder with
a relatively large mass (424 g in this case). The wires (made of thermo-insulating material) are
holding the sample placed in a relatively high vacuum ( 4 510 10P = mbar). A carbon resistor
is in contact with the sample and is used to measure the sample temperature. Carbon is used for
this purpose because it is not a metal (resistance of the metals decreases when decreasing
temperature thus they would not be accurate thermometers at very low temperatures). For the
case of carbon the resistivity increases with decreasing temperature, but unlike typical
semiconductors, carbon still remains a relatively good conductor at low temperatures. A heater
made of a thin wire is wound around the sample. Electrical energy from the power source is
used to heat the sample. Surrounding the metal container where the sample is situated is a
Dewar vessel filled with liquid helium. The helium containing Dewar vessel is situated in
another Dewar vessel filled with liquid nitrogen. A system of pipes and pumps is incorporated
in the apparatus in order to provide vacuum and for introducing heat exchange gas.
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Experiment
First, the Dewar vessels were filled with liquid nitrogen and liquid helium. Then Pump1
(see Fig. 1) was used to obtain vacuum in the sample container to thermally insulate the sample.
Pump2 provided a vacuum in the Dewar vessel containing the liquid helium in order to lower itstemperature (evaporating liquid helium is an endothermic process, thus a temperature in the
order of 2 K can be reached). The next step was to introduce the exchange gas; helium gas from
the inner Dewar vessel was moved into the sample container by opening the valve which
connects Pump1 to Pump2 (Fig. 1). The exchange gas is necessary to transport heat away from
the sample towards the liquid helium.
After the sample had been cooled down to approximately 2 K the exchange gas was
evacuated from the container, and the sample was thermally insulated. That gave us the
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possibility to measure the heat capacity. First, the temperature was measured indirectly by the
computer software from the resistance.
The sample was being heated by the electrical heater. In our case, constant voltage was
applied for a determined time interval. The voltage, the current and the heating time were
recorded. Assuming constant (average) values for the voltage and current, the energy supplied
by the heater was calculated using the following formula:
Q I U t =
All these steps were performed many times in the temperature range from 2 K until 26
K.
Below we can see the temperature vs. time graph, which was constructed from the
obtained data. From the ramps on this graph the temperature values for each heating can be
determined.
0 500 1000 1500 2000 2500 3000 3500
0
5
10
15
20
25
Temperature,
K
Time, s
Fig. 2: Temperature vs. Time
On the graph, in the approximate region of 750-800s we can see quite big decrease of
temperature before to consequent heatings. That is an experimental error, which was caused by
a long pause between the heatings.
The molar heat capacity of the sample is defined by:
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( ) ( )moldQ Q
c T c T n dT n T
= =
Knowing the mass of the sample (Cu, 424g), the number of moles can be determined by
( )
( )
m Cun
A Cu= . Thus all the parameters necessary are known, and the molar heat capacity of
copper corresponding to different temperatures can be calculated. The acquired data are
presented in and Table 2 in the appendix.
Results
The graph obtained from the experimental data, showing the relation of the molar heat
capacity versus temperature is presented in the following figure:
0 5 10 15 20 25
0,0
0,5
1,0
1,5
2,0
2,5
3,0
Molar Heat Capacity
MolarHeatCapacity(J*K-1*mol-1)
Temperature (K)
Fig. 3:Dependence of the molar heat capacity of copper on temperature
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According to free electron theory, the shape of the curve near very low temperatures is dictated
by the linear term of the equation. On the contrary, at higher temperatures
the cubic term would dominate. A characteristic of the obtained graph is that the molar heat
capacity of the metal approaches zero at very low temperatures. This is in agreement with the
theory.
We see from the figure 3 one point at 9.731 K and 0.1818 J*K-1*mol-1, which deviates
from the total behavior. Most probably data for this particular value was either measured or
written dawn wrongly.
Next, if we divide this equation by T we obtain:
2( )c TAT
T= +
If we plot( )c T
Tas a function of 2T we should obtain a straight line with a slope A and
an intercept . However, our results plotted on Fig. 4 do not correspond to the theoretical
prediction of equation for C(T). We obtained a nonlinear relationship. Applying the least square
fitting method, we constructed a linear trend line. These results are shown in the following
figure:
0 100 200 300 400 500 600 700
0,00
0,02
0,04
0,06
0,08
0,10
0,12
Cmol/T
Linear Fit of Cmol/T
Cmol/T
(J*K-2*mol-1)
T 2 (K2)
Equation y =a +
Adj. R-Squ 0,9650
Value Standard E
Cmol/T Intercep -0,00366 0,00119
Cmol/T Slope 1,73983 5,1677E-6
Fig. 4: Dependence of the quotient of the molar heat capacity and temperaturec
Tversus
the square of the temperature 2T
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Note that the slope of the fitting is A=1.73983*10^-4 JK-4mol-1 and the intercept is at =-
0,00366 J*K-2*mol-1. The Debye temperature can be readily calculated using the slope A by the
equation4
312
5D
R
A
= . The following result was obtained D =223.4K.
The theory predicts a line intersecting at some positive intercept ( ). Our results,however, display a negative intercept. This indicates that a systematic error might be present.
We might have some preliminary assumptions concerning the origin of this error. One of the
reasons might be the slow heating rate. If we have a look again at the figure 1, we see that the
slope of the temperature curve at higher values changes several times and if we come back to
the last graph we see that the dots at the temperatures higher than 15K, where we used 1K
heating step, are shifted upwards, which results in negative intercept. For that purposes we
decided to neglected the points at lower temperature and we found that in that case
A=9,524*10^5 JK-3mol-1 and =0,0135 J*K-1*mol-1 (fig. 5)
0 100 200 300 400 500 600 700
0,00
0,02
0,04
0,06
0,08
0,10
0,12
Cmol/T
Linear Fit of Cmol/T
Cmol/T(J*K-2*mol-1)
T 2 (K2)
Equation y =a +
Adj. R-Squ 0,9288
Value Standard E
Cmol/T Interce 0,00135 4,45977E-
Cmol/T Slope 9,52374 4,7291E-6
Fig. 5: Dependence of the quotient of the molar heat capacity and temperaturec
Tversus
the square of the temperature2
T
In this case the Debye temperature will be 273K, which is much closer to the theoretical
value for copper of 343.5K [1].
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References
1. Charles Kittel, Introduction to Solid State Physics, John Wiley & Sons; 8th international
edition edition (2004)
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Appendix
Table 1:
Results obtained directly by measurement. U (V) is the applied voltage, I is the applied
electrical current and t is the time interval of heating. The current is expressed as Volts
applied to a resistance equal to 10 Ohms, which is the resistance of the heater wire.
U I t
V A s
0,1526 0,00167 19,1
0,1536 0,0018 22,58
0,1533 0,00155 27,22
0,1546 0,00182 40,760,1538 0,00161 55,02
0,2301 0,00275 23,8
0,2325 0,00255 24,15
0,291 0,00349 15,98
0,2941 0,00348 20,07
0,2922 0,0035 22,34
0,2944 0,0035 101,5
0,2949 0,00347 41,03
0,441 0,00501 13,27
0,446 0,00524 34,540,4438 0,00515 39,78
0,5905 0,00699 26,35
0,5906 0,00679 31,14
0,7325 0,00855 22,39
0,7413 0,0086 31,1
0,7418 0,00885 25,06
0,7409 0,00888 51,29
0,7456 0,00893 30,99
0,7503 0,00955 104,9
1,086 0,01281 29,921,00772 0,01284 33,92
1,3451 0,01553 24,11
1,3584 0,01603 24,56
1,3587 0,01614 21,87
1,3667 0,01584 36,62
1,781 0,0202 47,61
1,7438 0,02029 52,03
1,7467 0,02063 24,98
1,7475 0,02059 117,39
1,7782 0,02108 128,691,8071 0,02124 148,03
2,435 0,0281 123,37
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2,458 0,0281 110,19
2,447 0,029 134,41
2,488 0,0291 149,79
2,505 0,029 206,47
2,533 0,0299 223,65
2,54 0,0302 249,98
Table 2:
Calculated parameters necessary for solving the problem. Taverage is the mean ofTstart and Tfinish,
which are the temperatures of the sample correspondingly before and after heating, Q is the
portion of heat supplied to the sample Cmol is the molar heat capacity of the copper sample.
Additionally, T2is the square of the Taverageand Cmol/Tis quotient of the molar heat capacity and
average temperature.
Tstart Tfinish T Taverage T2
K K K K K 2
2,478 2,69 0,212
2,584 6,67706
2,679 2,883
0,204
2,781 7,73396
2,864 3,065
0,201
2,9645 8,78826
3,009 3,26
4
0,25
5
3,1365 9,83763
3,195 3,46 0,265
3,3275 11,07226
3,387 3,676
0,289
3,5315 12,47149
3,643 3,874
0,231
3,7585 14,12632
3,796 4,044
0,248
3,92 15,3664
3,953 4,225
0,272
4,089 16,71992
4,164 4,42
3
0,25
9
4,2935 18,4341
43,877 4,61
90,74
24,248 18,0455
4,507 4,835
0,328
4,671 21,81824
4,739 5,012
0,273
4,8755 23,7705
4,909 5,542
0,633
5,2255 27,30585
5,514 6,034
0,52 5,774 33,33908
5,971 6,537 0,566 6,254 39,112526,51 7,04 0,53 6,777 45,9277
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4 4 3
6,914 7,46 0,546
7,187 51,65297
7,424 8,046
0,622
7,735 59,83022
8,043 8,44 0,397
8,2415 67,92232
8,439 9,127
0,688
8,783 77,14109
9,111 9,441
0,33 9,276 86,04418
9,425 10,037
0,612
9,731 94,69236
10,015
10,574
0,559
10,2945
105,97673
10,544
11,092
0,548
10,818 117,02912
11,035
11,557
0,522
11,296 127,59962
11,579
12,034
0,455
11,8065
139,39344
12,075
12,451
0,376
12,263 150,38117
12,472
13,05
0,578
12,761 162,84312
13,025
14,06
1,035
13,5425
183,39931
14,103
15,062
0,959
14,5825
212,64931
15,086
15,445
0,359
15,2655
233,03549
15,432
16,456
1,024
15,944 254,21114
16,462
17,443
0,981
16,9525
287,38726
17,445
18,438
0,993
17,9415
321,89742
18,439
19,598
1,159
19,0185
361,70334
19,605
20,481
0,876
20,043 401,72185
20,49
2
21,4
56
0,96
4
20,974 439,908
6821,464
22,441
0,977
21,9525
481,91226
22,45 23,436
0,986
22,943 526,38125
23,436
24,439
1,003
23,9375
573,00391
24,442
25,436
0,994
24,939 621,95372
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Q P Cmol Cmol/T
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J watt J*K-1*mol-1
J*K-2*mol-1
0,00487 2,55*10-4
0,00344 0,00133
0,00624 2,76*10-4
0,00458 0,00165
0,00647 2,38*10-4
0,00482 0,00163
0,01147 2,81*10-4
0,00674 0,00215
0,01362 2,48*10-4
0,0077 0,00231
0,01506 6,33*10-4
0,0078 0,00221
0,01432 5,93*10-4
0,00928 0,00247
0,01623 0,00102 0,0098 0,0025
0,02054 0,00102 0,01131 0,00277
0,02285 0,00102 0,01321 0,003080,10459 0,00103 0,02111 0,00497
0,04199 0,00102 0,01917 0,0041
0,02932 0,00221 0,01608 0,0033
0,08072 0,00234 0,0191 0,00365
0,09092 0,00229 0,02619 0,00454
0,10876 0,00413 0,02878 0,0046
0,12488 0,00401 0,03502 0,00517
0,14023 0,00626 0,03846 0,00535
0,19827 0,00638 0,04774 0,00617
0,16452 0,00656 0,06206 0,00753
0,33745 0,00658 0,07346 0,00836
0,20634 0,00666 0,09364 0,0101
0,75165 0,00717 0,18394 0,0189
0,41624 0,01391 0,11152 0,01083
0,4389 0,01294 0,11995 0,01109
0,50364 0,02089 0,1445 0,01279
0,5348 0,02178 0,17603 0,01491
0,4796 0,02193 0,19103 0,01558
0,79277 0,02165 0,20541 0,0161
1,71283 0,03598 0,24785 0,0183
1,84091 0,03538 0,28749 0,01971
0,90014 0,03603 0,37551 0,0246
4,22381 0,03598 0,61775 0,03874
4,82387 0,03748 0,73644 0,04344
5,68181 0,03838 0,85693 0,04776
8,44141 0,06842 1,09078 0,05735
7,6108 0,06907 1,30117 0,06492
9,53814 0,07096 1,48181 0,07065
10,84492
0,0724 1,66241 0,07573
14,99901
0,07264 2,27821 0,0993
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16,93851
0,07574 2,52919 0,10566
19,17547
0,07671 2,88913 0,11585
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