introduction to mixture applications
DESCRIPTION
Introduction to Mixture Applications. The following is designed to help you understand the basics of one of the popular application problems in introductory algebra: mixture problems. Example 1:. Recall that percent means per hundred , so. Example 2:. - PowerPoint PPT PresentationTRANSCRIPT
Introduction to Mixture Applications
The following is designed to help you understand the basics of one of the popular application problems in introductory algebra: mixture problems.
40
10040%
85
10085%
Recall that percent means per hundred, so ...
Example 1:
The jar on the right is marked in 10 equal divisions.
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Fill the jar with acid up to the “2” mark …
Example 2:
The jar on the right is marked in 10 equal divisions.
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Fill the jar with acid up to the “2” mark …
… and add water to the top of the glass…
Example 2:
The jar on the right is marked in 10 equal divisions.
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Fill the jar with acid up to the “2” mark …
… and add water to the top of the glass…
Example 2:
The jar has 2 units of acid …
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… and 8 units of water.
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… for a total of 10 units of mixed solution.
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The acid represents 2 units …
… out of a total of 10 units, or …
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2
10
units acid
units total
2 10
10 10
20
100
20%
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This means that the acid represents 20% of the total liquid in the jar.
Figured another way, the amount of acid is
20% 10 units
0.20 10
units of d2 aci
% acid total
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Mix 2 units of acid with only 6 units of added water.
Example 3:
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6 units of water
Mix 2 units of acid with only 6 units of added water.
Example 3:
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2
8
units acid
units total
2
8
25
100
25%
1
4
1 25
4 25
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This means that the acid represents 25% of the total liquid in the jar.
Figured another way, the amount of acid is
25% 8 units
0.25 8
units of d2 aci
% acid total
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Mix acid and water again.
Example 4:
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Mix acid and water again.
Example 4:
3
9
units acid
units total
3
9
133 %
3
1
3
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133 % 9 units
3
19
3
units of d3 aci
% acid total
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Mix acid and water again.
Example 5:
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Mix acid and water again.
Example 5:
If the solution is 60% acid, determine the number of units of acid
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60% 8 units
0.6 8
units of 4.8 acid
% acid total
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Assume the jar has x units of solution that is 40% acid.
Example 6:
x
40% acid
Write an expression for the amount of acid in the jar.
% acid total
40% x
0.40x
