ibps po (ph-ii) mock test - 161 (solution)...ibps po (ph-ii) mock test - 161 (solution) reasoning...

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

IBPS PO (PH-II) MOCK TEST - 161 (SOLUTION)

REASONING(1-4): Let us first solve the seating

arrangment.

Now, come to the year of birth Land J were born before 1980. Nis the eldest. J is younger than L.Hence N – 1971, L – 1975, J –1979. R is older than only M.Hence R – 1984, M – 1990. Thatleaves us with K, O and P. Theone sitting between J and K wasborn in 1984. Hence P was alsoborn in – 1984. K was born beforeO. The years left are 1980, 1981.Hence, K – 1980, O – 1981.

1. (2) 2. (1) 3. (5) 4. (5)(5-10):5. (4) Some books are pages (I) + All pages

are papers (A) = I + A = I = Somebooks are papers. Now, All pens arebooks (A) + Some books are papers(I) = A + I = No conclusion. Henceconclusion I does not follow. Again,All pens are books (A) + Some booksare pages (I) = A + O = No conclusion.Hence conculsion II does not follow.

6. (2) Some books are pages (I) + All pagesare papers (A) = I + A = I = Somebooks are papers. Hence conclusionII follows. But I does not follow.

7. (5) All Gs are Ks (A) + All Ks are Ls(A) = A + A = A = All Gs are Ls.Hence conclusion II follows.Again, Some Ds are Gs (I) + All Gsare Ls (A) = I + A = I = Some Ds areLs. Hence, conclusion I follows.

8. (1) Some Ds are Gs (I) + All Gs are Ks (A) = I + A= I = Some Ds are Ks conversion SomeKs are Ds. Hence conclusion I follows.Again, Some Ds are Ks (I) + All Ks areLs (A) = I + A = I = Some Ds are Ls.Hence conclusion II does not follow.

9. (4) Some files are folders (I) + All folders arepockets (A) = I + A = I = Some files arepockets. Hence conclusion I does notfollow. Again, Some files are pockets(I) + No pocket is a bag (E) = I + E =O = Some files are not bags. Henceconclusion II does not follow.

10. (4) All folders are pockets (A) + No pocket isa bag (E) = A + E = E = No folders arebags. Hence conclusion I does not follow.Again, from first statement conclusionII does not follow.

(11-14): The machine rearranges the words onthe right in English alphabetical order.

Step I: kite metal blue offer arranged (E)Step II: kite metal offer arrange blue (C)Step III: metal offer arrange blue kite (A)Step IV: offer arrange blue kite metal (D)Step V: arrange blue kite metal offer (B)11. (1) 12. (4) 13. (2) 14. (4)(15-19): hope to see you re so na di ... (i)

please come to see the party fi ge na di ke zo ... (ii)hope to come di so ge ... (iii)see you the party re fi zo na ... (iv)From (i), (ii) and (iii),to di ... (v)From (i), (iii) and (v),hope so ... (vi)From (ii), (iii) and (v),come ge ... (vii)From (i), (ii) and (iv),see na ... (viii)From (ii), (iv), (viii) and (ix),the/party fi/zoFrom (ii), (v), (vii), (viii) and (x),please ke ... (xi)

15. (2) 16. (1)17. (3) Either fi or zo18. (1) ke, na, ra19. (5)(20-24):20. (4) Given statements:

A > B = C ... (i)B < D < E ... (ii)Combining both statements, weget A > B < D < EThus, we can't compare A and D.Hence conclusion I (D > A) is nottrue. Again, B = C < D < E. Thus,C < E or E > C. Hence, conclusionII is also not true.

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21. (5) Given statements:L > U > K ... (i)Z < U < R ... (ii)Combining both statements, weget L > U > ZThus, L > Z is true. Henceconclusion I is true. Again, K < U <R. Thus K < R is true. Henceconclusion II is true.

22. (1) Given statements:Y < J = P > R > IThus, J > I is true. Henceconclusion I is true. Again, wecan't compare Y and R. Hence, IIis not true.

23. (4) Given statements:V > K > M = N ... (i)M > S ... (ii)T < K ... (iii)Combining (i) and (iii), we getT < K > M = NWe can't compare T and N.Hence conclusion I (T < N) is nottrue. Again, combining (i) and (ii)V > K > M > S. Thus, conclusion II(V = S) is not true.

24. (5) A > B < C > FE > D > C > ZI. A > Z is true.II. F < E is true.

(25-29):25. (2) From I:

Hece, J is either Niece or Nephewof K. Thus, I is not sufficient toanswer the question becausegender of J is not given.From II:

Hence J is Nephew of K.Only II is sufficient to answer thequestion.

26. (1) From I:G occupied even-numbered floor.So, G stays either on floor 2 or on floor 4.But G does not stay on the second floor.So, G stays on the fourth floor. Thus, onlyI is sufficient to answer the question.From II:G stays either on 2nd or on 4th floor.Hence, II alone is not sufficient toanswer the question.

27. (5) From I:According to Mohit, the possibledays for Raju to complete hisassignment are 4 days, 5 days, 6days, 7 days or 8 days.From II:According to the Meena, possible daysfor Raju to complete his assignmentare 8 days, 9 days or 8 days.From I and II:8 is common in both the statement.Hence Raju completes his assignmentin 8 days.

28. (3) From I:

Similarly.

So,

Hece, I is sufficient to answer thequestion.From II:

Similarly,

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So,

Th us, either I or II is sufficientto answer the question.

29. (4) From I:D > AFrom II:D > CFrom I and II:School D has more students than A andC, but nothing has be said about B.So, we can't determine the schoolwith the highest number ofstudents A, B, C and D.

(30-34):

30. (3) 31. (2) 32. (3)33. (2) In all other pairs, the first person

is second to the left of the second.

34. (1)

There is only one person C whoseposition remains unchanged.

(35-39): From the information given inthe questions, we can have thefollowing table.

35. (1) 36. (3) 37. (4) 38. (1) 39. (2)(40-45):40. (2)41. (3) Since small brands are tying up with

supermarkets to pull their businessout of troubled water, it can be inferredthat small brands are of the perceptionthat sale in a supermarket is higherthan that of small grocery stores.

42. (5) As small brands are in troubledwater, it can be a validassumption that smaller brandsare currently making substaintiallosses in their business.

43. (3) 44. (5) 45. (1)(46-50):46. (1) All these assumptions are in

directions are in directions contraryto what the statement says.

47. (3) Whenever such a decision istaken, the assumptions are thatit woujld be welcome and allowedto implement.

48. (3) The urging of the govt makessense only when (A) and (B) areimplicit.

49. (2) The decision to auction assumesreponse to it. Hence (A) is notimplicit. Unless the private entitiesare capable, the decision wouldmake no sense. Hence (B) isimplicit. (C) is implicit as withoutfinancial benefit, private entitieswould not turn up for the auction.

50. (2) (A) must be implicit to make therequest meaningful. The govt isout of picture here. Hence (B) isnot implicit. (C) is not implicit asthe case may be only of delay, notof cancellation of flight.

ENGLISH156. (3)Use 'file electronic' in place of

'electronic file'.157. (5)No error. The sentence is correct.158. (3)Use 'leads' in place of 'lead'.159. (3)Use 'before' in place of 'to'.160. (1)Delete 'of '. The verb 'comprise'

doesn't take any preposition.MATHS

91. (3)1 92 24 650 85 ?6 100 23

104 = 85 + ? ? = 104 – 85 = 19

92. (3) 92 576 2 1296

= 3(?) 49 92 × 576 ÷ 2 × 36 = (?)3 + 7 (?)3 = 92 × 8 – 7 (?)3 = 729 ? = 9

93. (5)21 1 5 (?) 53 2 1 1

4 2 6 10 12

213 5 11 17 (?)

4 2 6 12 10

39 30 22 17

12

2(?)

10 (?)2 =30 10

12

= 25 ? = 5

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94. (1)1 12 2( 8 8) (9)

= 3(?) 8 340

(?)3 = 2 2 3 2 2 340 (?)3 = 343 ? = 7

95. (2) (15 × 0.40)4 ÷ (1080 ÷ 30)4×(27× 8)4= (3 × 2)? + 5

(6)4 ÷ (6)8 × (6)12 = (6)? + 5

? + 5 = 4 – 8 + 12 ? = 8 – 5 = 3

96. (4) Given .1

1No

, . 22

No , . 3

3No

, .4

4No

,. 5

5No

, . 6

6No

Wrong number is 154.97. (2)Given

No. × 2 + 22, No. × 3 + 32, No. × 4+ 42,

No. × 5 + 52, No. × 6 + 62, No. × 7+ 72,

Wrong number is 42.98. (1)

Hence, wrong number is 8.99. (5) No. × 0.5, No. × 1.5, No. × 2.5,

No. × 3.5No. × 4.5, No. × 5.5

Wrong number is 65.100. (4)7, 13, 25, 49, 97, 94, 385

(Given number × 2) –1 gives nextnumber7 × 2 – 1 = 14 – 1 = 1313 × 2 – 1 = 26 – 1 = 2525 × 2 – 1 = 50 – 1 = 4949 × 2 – 1 = 98 – 1 = 9797 × 2 – 1 = 194 – 1 = 193193 × 2 – 1 = 386 – 1 = 385

Wrong number is 194.(101-105):101. (4)3065 ÷ 15 204

1548 + 204 = 1752 1750102. (5)2398.59 2400

248.65 250Then, 32 250 2?

5 2400 3

103. (1)39% = (40 – 1)%

40% of 695 = 25 × 695 = 278

39% 278 – 7 = 271

? = 27110 × 100 = 2710 2800

104. (3)6 2 6 1.414 8.484 8.5 14.275 14.3Also,8.5 + 14.3 228196.35 196

22.8 1?196 8

105. (3)1524.79 1525, 19.92 20,495.25 495Then,1525 × 20 + 495 = 30500 + 495= 30995 31000

(106-110):106. (3)107. (5)I. p2 + 2P – 8 = 0

p2 + 4P – 2P – 8 = 0 (P + 4)(P – 2) = 0 P = 2, – 4II. Q2 –5Q + 6 = 0 (Q – 3)(Q – 2) = 0 Q = 2, – 3

108. (4)I. 21P2 – 17P + 2 = 0 21P2 – 14P – 3P + 2 = 0 (7P – 1)(3P – 2) = 0

P = 1 2,7 3

II. 56Q2 – 15Q + 1 = 90 (7Q – 1)(8Q – 1) = 0

Q = 1 1,7 8

109. (1)P = 52 , 3; Q =

32 , –3

110. (1)P = 4, 72 ; Q = +3

111. (2)Booking amount= 40% of (3850 × 715)

= 2850 715 40

100

= ` 1101100112. (1)Suppose that cost price of the

Television is ` x.According to the question,x + 16% of x = 16588

or, x + 16

100x

= 16588

or, x116100

= 16588

x = 16588 100

116

= ` 14300

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113. (2)Third number= 5 × 213 – 2 × 233.5 – 2 × 271= 1065 – 467 – 542= 56

114. (1)Let the population of village X andY be x and y respectively.

x : y = 5 : 7or, 5y = 7xor, 25y= 35x ... (i) and

( 25000)x

y = 2536

or, 36x = 25y + 625000= 35x + 625000

x = 625000

115. (2)Amount = P 1100

tr

= ` 25000281

100

= ` 25000 × 27 2725 25

= 40 × 729 = ` 29160

116. (2)Let the original two-digit numberbe 10x + y.Now, according to the question,10y + x – 10x – y = 18or, y – x = 2 ... (i)

x + y = 6 ... (ii)On solving the above equations,x = 2 and y = 4

required two-digit number = 24117. (1)Let the ages of father and his son

four years ago be 19x and 6x yrsrespectively.Their present ages= (19x + 4) and (6x + 4) yrsNow according to the question(19x + 4) – (6x + 4) = 26

x = 2Ratio of their present ages= 19x + 4 : 6x + 4 = 42 : 16 = 21 : 8

118.(1) 18 w's one day's work = 1

12 ... (i)

12m's one day's work = 19 ... (ii)

Now dividing equation (i) byequation (ii), we have1812

ww =

112 × 9

1 =

912

or, 18 × 12 w = 12 × 9 mor, 2w = 1 mor, 1 man = 2 womenor, 8 men = 16 women

8 men and 8 women = (16 + 8 =) 24 women

14 women can complete the workin 12 days

24 women can complete the work

in 12 18

24

= 9 days119. (2)Fare of one adult = ` 114

Fare of one child = 114

6 = ` 19Fare of 4 adults and 5 children= 4 × 114 + 5 × 19= 456 + 95= ` 551

120. (3)Speed of the truck = 3688 = 46 kmph

Speed of the car = 46 + 18 = 64 kmphDistance travelled by the car= 368 + 16 = 84

Time = 36864 = 6 hours

(121-125):121. (4)The total number of unemployed

youth in State A in 2006= (7 + 8 =) 15% of 35 lac

= 3500000 15

100

= 525000122. (2)Number of unemployed female

youth in State D in 2005= 6% of 24 lac

= 2400000 6

100

= 144000123. (3)Number of unemployed male

youth in State A in 2005= 12% of 32 lac

= 3200000 12

100

= 384000Number of unemployed maleyouth in State E in 2006= 6% of 32 lac

= 3200000 6

100

= 192000

Required percentage

= 384000192000 × 100 = 200%

124. (5)Number of unemployed maleyouth in State F in 2005= 7% of 28 lac

= 2800000 7

100

= 196000Number of unemployed maleyouth in State A in 2006

= 7% of 35 lac = 3500000 7

100

= 245000Required difference= 245000 – 196000 = 49000

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125. (1)Number of unemployed maleyouth in State D in 2005= 10% of 24 lacNumber of unemployed maleyouth in State D in 2006= 8% of 30 lac

Required ratio= 10% of 24 lac : 8% of 30 lac= 24 × 10 : 30 × 8= 1 : 1

126.(1) The area irrigated by governmentcanals in the year 1950-51 = 7000hectares. The area irrigated byprivate canals in year 1950-51 =1000 hectares.Hence, the required ratio

= 10007000

= 7 : 1

127.(1) Total irrigated area in year 1980-81= 1000 + 3200 + 8000 + 8500 +

14000 = 37700 (approx.)Total irrigated area in the year

1990-91 = 500 + 2500 + 2500+ 9000+ 14000 + 16000= 44500 (approx.)Hence, the difference= 44500 – 37700 = 6800 hectares

128.(3) Irrigated area by tanks in 1990-91= 2500 hectaresIrrigated area by private canals in1950-51 = 1000 hectaresHence the required percentage

= 2500)10002500( × 100 = 60%

129.(1) The area irrigated by tubewells inthe year 1960-61 = 100 hectares.The area irrigated by tubewells inthe year 1970-71 = 5000 hectares.The percent increases

= 100)10005000( × 100= 4900%

130.(1) The area irrigated by tubewells= 100 hectaresThe area irrigated by privatecanals = 1000 hectaresHence, required ratio

= 1000100

= 101

= 1 : 10

(131-135):131. (3)Total number of mobiles sold in

the month of July

= 45000 × 17100 = 7650

Mobile phones sold by CompanyB in the month of July

= 7650 ×7

15 = 3570

Total number of mobile phonessold in the month of December

= 45000 × 16

100 = 7200

Mobile phones sold by CompanyB in the month of December

= 7200 × 9

16 = 4050

Reqd ratio3570 357 119 119 :1354050 405 135

132. (3)Number of mobile phones sold inthe month of Novemeber

= 45000 × 12

100 = 5400

Number of mobile phones sold byCompany A in the month of November

= 5400 × 7

15 = 2520

Number of mobile phones withoutdiscount in the month of November

by Company A = 2520 × 65

100 =

2520 × 0.65 = 1638133. (4)Number of mobile phones sold in

the month of October

= 45000 × 8

100 = 3600

Number of mobile phones sold byCompany B in the month of October

= 3600 × 5

12 = 1500

Total profit earned by CompanyB in the month of October= 1500 × 433 = 649500

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134. (5)Number of mobile phones sold inthe month of July

= 45000 ×17100 = 7650

Number of mobile phones sold byCompany A in the month of July

= 7650 × 8

15 = 4080Number of mobile phones sold inthe month of December

= 45000 ×16100 = 7200

Number of mobile phones sold byCompany A in the month of

December = 7200 × 7

16 = 3150

Reqd % = 40803150 × 100 = 129.52 130

135. (1)Number of mobile phone sold inthe month of August

= 22

100 × 45000 = 9900Number of mobile phones sold inthe month of September

= 25

100 × 45000 = 14

× 45000 = 11250Number of mobile phones sold byCompany B in the month of August

= 9900 × 59 = 5500

Number of mobile phones sold byCompany B in September

= 11250 × 25 = 4500

Total number of mobile phones soldin August and September byCompany B = 5500 + 4500 = 10000Quicker Method:Total number of mobile phones sold byCompany B in August and September

= 22 5 25 245000 4500

100 9 100 5

= 10000136. (5)Let the no. of students studying in

Institute B be x. From II & III, thenumber of students who got placed

from Institute A is 54

× x × 65

.Using the condition of statement Ialso. We can't ascertain therequired number.

137. (5)By dispensing with any one ofthe three statement, we can getthe required answer. From I & III,we get 15% of Income = 4500

100% = 154500

× 100From I & III, we get 85% of

Income = 54

× 20,400From II & III, we get

Income = 4500 + 20,400

45

138. (1)From I,x = 2y,x age of Suchitray age of her sonz age of mother

From II, x = 32

zFrom III, 13x – 24y = 44I & III together give the value ofx.Hence II can be dispensed with.

139. (5) As the amount of profit is notgiven, we cannot find Neeta'sshare out of the profit.Rememberthat we can get only the ratio oftheir shares in the profit.

140. (4) By II alone, we get the answeras Labelled price

= 608

95100

= 640So, I and III together can bedispensed with.By I & III together, we get theanswer as:

Labelled price = 500

100128

= 640So, II can be dispensed with.Therefore, the suitable answeris either II alone or I & IIItogether can be dispensed with.But as per our given choices,the correct answer is (4); only I& II.

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1. (2)2. (1)3. (5)4. (5)5. (4)6. (2)7. (5)8. (1)9. (4)10. (4)11. (1)12. (4)13. (2)14. (4)15. (5)16. (1)17. (3)18. (1)19. (5)20. (4)21. (5)22. (1)23. (4)24. (5)25. (2)26. (1)27. (5)28. (3)29. (4)30. (3)31. (2)32. (3)33. (2)34. (1)35. (1)36. (3)37. (4)38. (1)39. (2)40. (2)

41. (3)42. (5)43. (3)44. (5)45. (1)46. (1)47. (3)48. (3)49. (2)50. (2)51. (2)52. (2)53. (3)54. (3)55. (4)56. (3)57. (2)58. (2)59. (4)60. (2)61. (3)62. (2)63. (1)64. (2)65. (3)66. (2)67. (4)68. (3)69. (2)70. (3)71. (2)72. (3)73. (3)74. (3)75. (2)76. (2)77. (2)78. (4)79. (1)80. (2)

IBPS PO (PH- II) MOCK TEST - 161 [ANSWER KEY]

81. (5)82. (3)83. (1)84. (5)85. (2)86. (3)87. (3)88. (3)89. (4)90. (1)91. (3)92. (3)93. (5)94. (1)95. (2)96. (4)97. (2)98. (1)99. (5)100. (4)101. (4)102. (5)103. (1)104. (3)105. (3)106. (3)107. (5)108. (4)109. (1)110. (1)111. (2)112. (1)113. (2)114. (1)115. (2)116. (2)117. (1)118. (1)119. (2)120. (3)

121. (4)122. (2)123. (3)124. (5)125. (1)126. (1)127. (1)128. (3)129. (1)130. (1)131. (3)132. (3)133. (4)134. (5)135. (1)136. (5)137. (5)138. (1)139. (5)140. (4)141. (1)142. (5)143. (2)144. (5)145. (2)146. (3)147. (5)148. (1)149. (4)150. (1)151. (5)152. (2)153. (3)154. (5)155. (3)156. (5)157. (3)158. (3)159. (1)160. (5)

161. (3)162. (5)163. (2)164. (2)165. (3)166. (2)167. (3)168. (1)169. (2)170. (2)171. (3)172. (2)173. (1)174. (2)175. (2)176. (3)177. (1)178. (4)179. (5)180. (1)181. (4)182. (4)183. (1)184. (2)185. (4)186. (5)187. (3)188. (4)189. (5)190. (1)191. (1)192. (2)193. (1)194. (3)195. (1)196. (1)197. (2)198. (2)199. (2)200. (3)

ibps po (ph-ii) mock test - 161 (solution)...ibps po (ph-ii) mock test - 161 (solution) reasoning...

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