ibps po (ph-ii) mock test - 160 (solution) - amazon s3€¦ · centres at: mukherjee nagar munirka...

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

IBPS PO (PH-II) MOCK TEST - 160 (SOLUTION)

REASONING1. (3)2. (2)3. (3)4. (4) Letter have been coded as follows:

A is coded as F, while F is code asF, while F is coded as A. Similarly,B is coded as G and G is coded asB. W is coded as Z and Z is codedas W.

(5-8):

5. (1) Q is the wife of P.6. (2) From condition (vii), S is the sister

of P. Hence, QST are the females.7. (3) QT are the married ladies.8. (3) There is no information about the

colour of U's dress, hence it couldbe black or green.

(9-14):9. (3)10. (2)

11. (3) Here, after looking all thestatements we found that the term'books' have one 100% notation instatement IV and this term iscommon with statement IV andthis term is common withstatement I and II. So, two possibleconclusions are 'Some slates arepencils' and 'Some slates arenotebook'. So conclusion III follow.No conclusion can start with 'All'so others will be eliminated.

12. (3)13. (1)14. (3)(15-19):15. (3)Step 2:97 82 sun 50 moon night 36 72

eveningStep 3:97 82 sun night moon 50 36 72

eveningStep 4:97 82 sun night 72 50 36 moon

eveningStep 5:97 82 sun night 72 moon 36 50

eveningStep 6:97 82 sun night 72 moon evening

50 36Four more steps are required.

16. (1)Input: 86 92 fighter next 88 tire army

29 75Step 1:92 86 fighter next 88 tire army

29 75Step 2:92 88 fighter next 86 tire army

29 75Step 3:92 88 tire next 86 fighter army

29 75This step is step no. 3.

17. (4) "52 42 tag mug 36 hug 40 bag 21"is step 3 and finding step 1 is notpossible.

18. (3)Input: 94 hair fair 61 dare 69 share 57 32Step 1:94 69 fair 61 dare hair share 57 32Step 2:94 69 share 61 dare hair fair 57 32Step 3:94 69 share hair dare 61 fair 57 32Step 4:94 69 share hair 61 dare fair 57 32

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19. (2) 99 83 hate gate 64 rate 23 date 57After just 4 step (more) we willreach on final output.99 83 rate hate 64 gate date 57 23

(20-24): On the basis of informationgiven in the question. We can havethe following table.

20. (5) Limca21. (4)22. (3)23. (1)24. (2) P, Q and T(25-29):25. (4) M > N > P > R

So, M > R. So I does not follow.N > R & R < BN > R < BSo II also not follow.

26. (2) Z > X = YSo, Z > Y

27. (3) B < Z, Z = WSo, B > Wi.e. B > W or B = WEither I or II

28. (5) P > Q = XP > Xand X < Y < ZSo, X < Z

29. (5) G > A = BSo, G > BC > G > A > PSo, C > P

(30-35):30. (2)31. (3)32. (5)33. (5)34. (4)

35. (3)(36-40):36. (3) Either of the two statements is

sufficient.From I:If Vidyavati is older than Kokila,who is seven years old, thenVidyavati's age must be more thanseven years. Hene, our answer tothe question is 'No'.From II:Vidyavati's age is (6 + 2 =) 8 years.Once again our answer is 'No'.

37. (1) From I:We get the following table:-

From the above table R is theperson who teaches Geography.Obviously, T teaches Biology.From II:We get the following chart:

From the chart given above, wecan conclude that

But, still we do not know whoamong R and T teaches Biology.

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38. (5) The month March of 2012 haveFridays on following dates: 2, 9,16, 23, 30. Now, it is obvious thatMadhumita appeared for theinterview on 23th March becauseamong the given dates only 23 isa prime number.

39. (3)40. (2) From I:

There are various such centurieswhich have 25 leap years. Hence,I alone is not sufficient.From II:The end is not in sight!Because a little calculation willsoon show that the century dayin the year 2000 in Saturday.Then

This cycle of events continues sothat the century day never fallson Sunday, Tuesday or Thursday.Thus, the end is not sight!

(41-45):41. (4) The govt provides security to

tourists across the country. Thatis why the govt has sent a policeteam to nab the culprits.

42. (3)43. (3) Extreme action (complete ban) is

not a solution to the problem.44. (4)45. (4)(46-50):46. (2) Aviation is an example of

infrastructure.47. (1) The last two sentences clearly

state this.48. (3) Not clear from the passage.49. (1) That we are talking of achieving

true potential implies that thepotential exists.

50. (3) Nothing can be said about thepast.

ENGLISH56. (4) Use 'is' in place of 'are'. Words like

with, together with, along with,besides, as well as, including, inaddition to, etc, do not affect thenumber of the verb. If the subjectis singular, a singular verb isrequired: if plural, a plural verb.

57. (3) Use 'are' in place of 'is'. Plural verbsare required for many singularnouns that have no singular form,such as proceeds, goods, ashes,remains, credentials, premises, etc.

58. (2) Use 'that' in place of 'who'. Aftertwo antecedents, one of which isthe name of a person, and theother a name of some animal orthing, then, we use 'that' in placeof 'who' or 'which'.

59. (3) Use 'them' in place of 'same'.'Same' is not a pronoun and assuch it should not be used inplace of a noun.

60. (5) No error. 'One another' is used inreference to more than two.

MATHS91. (5) 9216 12544 ?

9216 12544 x

2 2(96) (112) x

96 + 112 = x208 = x

92. (1) (38 × 142) ÷ (4096)1/3 = ?(5396) ÷ (163)1/3 = x539616 = xx = 337.25

93. (2) [(24)2 + (27)2] ÷ ? = 9.0625[576 + 729] ÷ x = 9.0625

1305x = 9.0625

1305

9.0625 = x

130590625 × 10000 = x

261 16

29

= x

4176

29 = x x = 144

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94. (1) 33.5 × 212 × 422.5 ÷ 22.5 × 73.5 = 21?

3.5 2 2.5

2.5 3.5

3 (3 7) (3 14)2 7

= 21x

3.5 2.5 2.5

2.5 3.5

3 9 7 7 3 142 7

= 21x

6.0 2.5 2.5

2.5 3.5

3 9 7 7 2 72 7

= 21x

6.0 4.5

3.5

3 3 3 77

= 21x

38.0 × 74.5 × 7–3.5 = (3 × 7)x38.0 × 71.0 = (3 × 7)xx = 8

95. (4) (43% of 2750) – (38% of 2990) =?43 382750 2990

100 100

= x

43 55 19 2992 5

= x

2365 56812 5

= x

(1182.5) – (1136.2) = xx = 46.3

96. (4) 17 17 51 255 1785 16065 ?17 × 1 = 1717 × 3 = 5151 × 5 = 255255 × 7 = 17851785 × 9 = 160651605 × 11 = 176715

97. (2) 462 552 650 756 870 992 ? 552 – 462 = 90 650 – 552 = 98 756 – 650 = 106 870 – 756 = 114 992 – 870 = 122 112 – 992 = 130Their common difference is 8.

98. (5)104, 153, 189, 214, ?153 – 104 = 49189 – 153 = 36214 – 189 = 25230 – 214 = 16Their is square of (7)2, (6)2, (5)2, (4)2.

99. (5) 705, 720, 774, 843, 935, 1050, ?728 – 705 = 23774 – 728 = 46843 – 774 = 69935 – 843 = 921050 – 935 = 1151188 – 1050 = 1328Their are multiple of 23.

100. (1)12 × 1 + 2 = 1414 × 1 + 3 = 1717 × 1 – 4 = 1313 × 1 – 5 = 88 × 1 + 6 = 1414 × 1 + 7 = 2121 × 1 – 8 = 1313 × 1 – 9 = 44 × 1 + 10 = 14

101. (4)87.99 × 6413.012 = 8?88 × 6413 = 8x(8)8 × (82)13 = 8x(8)8 × (8)26 = 8x834 = 8xx = 34

102. (4)103. (3)(8423 + 3120 + 6543) ÷ (1536 + 377 +

189) = ? (18086) ÷ (2102) = x

180862102 = x

180852100 = x

3617420 = x

8.6 = x x = 9

104. (3) 2 1624.9995 (4.9989) ?4.9900865

2 1625 (5)

5x

2(25) + 25 = 5x 25 + 25 = 5x 50 = 5x

505 = x

x = 10

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105. (5)7 4 20 12 45 5 19 7

2.3× 0.8 × 4.12.3 × 0.8 × 4.1204 × 4.1 8 7

(106-110):106. (2) I. x = 81

II. y = 89Therefore, x < y.Note: x = 7921 gives only +vevalue.Do not confuse it with x2 = 7921.In this case, when we find valueof x, then x = +81.But x = 7921 means ony + vevalue is given.

107. (2)I. x2 + 9x + 20 (x + 4)(x + 5) = 0 x = –4, –5

II. y2 + 5y + 6 = (y + 2)(y + 3) = 0 y = –2, –3

Therefore, x < y.108. (1)I + II x = 2.5 and y = 2

Therefore, x > y.109. (3)I. (x + 5)(x + 6) = 0

x = –5, –6II. (y + 6)(y + 7) = 0 y = –6, –7Therefore, x > y.

110. (5)I. x2 + 29x + 210 = 0 (x + 14)(x + 15) = 0 x = –14, –15

II. y2 + 28y + 195 = 0 (y + 13)(y + 15) = 0 y = –13, –15

We cannot establish a relationship.111. (5)Required difference

= 2

100RP

= 214985

100

= 985 × 196

10000 = 19.306

112. (3)Radius of circular plot

= 798.5622

= 31.36 = 56

Length of fence

= 2 × 227

× 5.6 = 35.2 footRequired cost of fencing per foot= 35.2 × 614 = 21612.8

113. (5)Weight of water in the mixture of

60 g water = 60 × 75

100 = 45 gWeight of water in the mixture of45 g water = 45 + 15 = 60 g

Percentage of water = 60 100

75

= 80%114. (4)Cost price of 30 kg wheat

= 30 × 45 = ` 1350Cost price of 30 kg wheat + 25%profit = Selling price= 1350 × 1.25 = `1687.5040% of 30 kg wheat= 30 × 0.40 = 12 kgSelling price of 12 kg wheat= 12 × 50 = ` 600Remaining 18 kg wheat's selling price= 1687.50 – 600 = ` 1087.50

Selling price of 1 kg wheat

= 1087.50

18 = ` 60115. (1)Let the length of train-B = x m

then the length of train-A = 2x m

Speed of train-A = 2

25 = 50x

Speed of train-B = 75x

Ratio of speed = AB

= 50x

x

= 7550 = 3 : 2

116. (5)Total number of marbles in theurn = 4 + 5 + 2 + 3 = 14Total number of possibleoutcomes= Science of 2 marbles out of 14marbles= 2C2 + 2C1 + 12C1 = 1 + 2 × 12 = 25

required probability = 2591

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117. (3)Suppose first number = xand second number = yThen,

82 – y2 = 15 64 – y2 = 15 y2 = 49 y = 49 = 7Again,

x2 + y3 = 568(on putting value y = 7)

x2 + 73 = 568 x2 + 343 =568 x2 = 225 x = 225 = 15Hence, three-fifth of the first

number = 35 × 15 = 9

118. (4)Cannot be determined

119.(1) Distance 44 50 5560 60

x

120. (4)We cannot find the value withoutknowing any absolute value inrupees.

(121-125):121. (1)Required ratio

= 7 212 : 6

12 3 = 7 : 4

122. (3)Required difference

= (18 14)2500

100

= 100123. (4)Number of males in HR and

Marketing

= 2500 × 16100 ×

58 + 2500 ×

15100 ×

715

= 425Number of females in HR andMarketing

= 2500 × 16100 ×

38 + 2500 ×

15100 ×

815

= 350 Required ratio

= 425 : 350 = 17 : 14124. (4)Number of female employees in

HR department

= 2500 × 16

100 × 38 = 150

125. (2)Required difference

= 2500 × 11

100 × 611

– 2500 × 11

100 × 511

= 150 – 125= 25

(126-135):126. (2)Graduate male population in state A

= 2400000 × 16

100 × 7

12

= 224000XII Std. male population in state A

= 3200000 × 15100 ×

716

= 210000 Difference

= 224000 – 210000= 14000

127. (4)Graduate female population ofState E

= 2400000 × 20

100 × 7

16

= 210000Std XII female population of state D

= 3200000 × 12

100 × 7

12

= 224000 Ratio

= 210000 : 224000= 15 : 16

128. (3)Required percentage

415% of 24×9 100518% of 32×9

= 15 24 418 32 5

× 100

= 50

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18 432100 9 10032

= 32 18 4 100

32 100 9

= 8130. (5)Required ratio

= 920% of 24×

16

: 1019% of 32×19

= 20 24 9 19 32 10:100 16 100 9

= 270 : 320= 27 : 20


= 14% of 2415% of 32× 100=

14 24 10015 32

= 70


919% of 32×19 100320% of 32×5

= 32 9 1004 32 3

= 75133. (3)Total Graduate and Std. XII male

population of State A

= 24 × 16

100 × 7

12 + 32 × 15100 ×

716

= 2.24 + 2.1= 4.34Total Graduate and Std. XIIfemale population of State A

= 24 × 16

100 × 5

12 + 32 × 15100 ×

916

= 1.6 + 2.7= 4.3

Ratio = 4.34 : 4.3 = 217 : 215

134. (1)Required ratio

= 17 1224 : 32

100 100

= 24 × 17 : 32 × 12= 17 : 16


18 324100 8 10020 724

100 16

18 3 168 20 7

× 100

= 77 (approx)(136-140):136. (2)Number of defaualters

= 21

100 × 29565

= 6210 (approx.)137. (1)Required difference

= 9 26345 8 27456

100 100

= 175 (approx.)138. (3)In 2007 the number of defaulters

of banks R was the maximum.139. (1)In 2008 the difference in number

of people taking loan from bank Pfrom the previous year was thehighest.

140. (3)Required number of defaulters

= 19 36152 18 35463

100

= 13250 (approx.)

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1. (3)2. (2)3. (3)4. (4)5. (1)6. (2)7. (3)8. (3)9. (3)10. (2)11. (3)12. (1)13. (1)14. (3)15. (3)16. (1)17. (4)18. (3)19. (2)20. (5)21. (4)22. (3)23. (1)24. (2)25. (4)26. (2)27. (3)28. (5)29. (5)30. (2)31. (3)32. (5)33. (5)34. (4)35. (3)36. (3)37. (1)38. (5)39. (3)40. (2)

41. (4)42. (3)43. (3)44. (4)45. (4)46. (2)47. (1)48. (3)49. (1)50. (3)51. (4)52. (2)53. (4)54. (2)55. (4)56. (3)57. (4)58. (2)59. (3)60. (4)61. (4)62. (4)63. (4)64. (2)65. (4)66. (3)67. (2)68. (4)69. (3)70. (2)71. (4)72. (3)73. (4)74. (2)75. (2)76. (3)77. (4)78. (1)79. (1)80. (5)

IBPS PO (PH- II) MOCK TEST - 160 [ANSWER KEY]

81. (3)82. (4)83. (5)84. (2)85. (2)86. (3)87. (2)88. (1)89. (4)90. (1)91. (5)92. (1)93. (2)94. (1)95. (4)96. (4)97. (2)98. (5)99. (5)100. (1)101. (4)102. (4)103. (3)104. (3)105. (5)106. (2)107. (2)108. (1)109. (3)110. (5)111. (5)112. (3)113. (5)114. (4)115. (1)116. (5)117. (3)118. (4)119. (1)120. (4)

121. (1)122. (3)123. (4)124. (4)125. (2)126. (2)127. (4)128. (3)129. (1)130. (5)131. (5)132. (2)133. (3)134. (1)135. (3)136. (2)137. (1)138. (3)139. (1)140. (3)141. (4)142. (2)143. (3)144. (3)145. (4)146. (4)147. (3)148. (3)149. (2)150. (5)151. (2)152. (1)153. (3)154. (2)155. (4)156. (4)157. (3)158. (2)159. (4)160. (5)

161. (1)162. (3)163. (5)164. (1)165. (3)166. (2)167. (2)168. (2)169. (5)170. (3)171. (1)172. (4)173. (3)174. (5)175. (1)176. (3)177. (4)178. (2)179. (2)180. (4)181. (5)182. (2)183. (4)184. (5)185. (3)186. (4)187. (5)188. (4)189. (2)190. (2)191. (3)192. (5)193. (4)194. (3)195. (4)196. (4)197. (1)198. (4)199. (3)200. (2)

ibps po (ph-ii) mock test - 160 (solution) - amazon s3€¦ · centres at: mukherjee nagar munirka...

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