EUROPEAN UNIVERSITY OF LEFKE

FACULTY OF ENGINEERING

DEPARTMENT OF CIVIL ENGINEERING

CE 306

FOUNDATION ENGINERING

WEEK 8: PROJECT

Submitted by:

HALL OZKAN :125680. BRKAN UGURLU :125368M. ABDULLAH YILMAZ:125670FIRAT ISIK :HARUN DEMRKAYA :135075CHAN OZCELK :ARAM AHMET ISMAIL :131069

LEFKE2015

HOTEL PROJECT

6 STOREY

RAFT FOUNDATON

B=15

L=30

DL=6000 TON

LL=890 TON

REAL LFE EXAMPLE

Insitu testing

SPT

LAB TESTNG

SPECIFIC GRAVITY

LL/PL

SIEVE

1D CONSOLIDATION

.Structural enginering assumed a raft foundation..Lets check bearing capacity for a rectangular foundation first.Assume 15x30 rectangular footing B=15 L=30.we are assuming the depth of footing DF=2m inorder to pass soft organic top soil.

0 Nc Nq Ny

0 5.7 1.0 0.05 7.3 1.6 0.1410 9.6 2.7 1.215 12.9 4.4 1.820 17.7 7.4 5.025 25.1 12.7 9.730 37.2 22.5 19.735 57.8 41.1 42.4440 95.7 81.3 100.445 172.3 173.3 360.050 347.5 415.1 1072.8

C: cohesion from laboratory testing (0,93kg/cm3): 91,22kN/m2

:unit weight of soil at foundation level from laboratory test:20.11kN/m3

Nc, Nq and N are the bearing capacity factors. They are functions of the angle of friction .

Nc:41 Nq:25 and Ny:25

Nc:41 Nq:25 and Ny:25

DEAD LOAD:6000 TON=58860 KNLVE LOAD:890 TON =8730.9KNAssume 3x4 rectangular footing selected B=2m L=4m

Df=1.5m C=0,93kgf/cm2=91,22kn/m2

Qu=cNc (1+0,3x+DfNy+

Week 7 slick 18 terzagi bearing capacity

=20,11kN/m3

Nc=41 Nq(25) N(25)

qu=91,22x41(1+0,3x+20,11x1.5x25+x20,11x25(1-0,2x

qu=5281.4

qnu=5281.4-

qna=qnu/Fs =1747.05 kN/m2 Fs:3

) 22809,84 q= - = -40.22 A=(3x4)=8cm 8 6

q=12043.96 kN/m2

qna(1747.05 kN/m2)kN/m2) NOT ACCEPTABLE!!!TRY RAFT FOUNDATON

Df=2m q=91,22kN/m2

B=15m Nc=41 Nq=25 N

L=30m

Qu=91,22x41x1++4818,3kN/m2

Area=15x30=450cm2

Fd=7429,88kN q= -

Df=42,22kN q=223,9432kN/m2Wf=22500kN

4 center of the found H=2m

=7.5m Es=36488kN/m2

s=0.3

If=0,96 Df/B=2/15=0,133

L/B= 30/15=2

m=2n=0,27

interpolition

x=0,013

Xr=0,055=F2

Is=F1xF2

Is=0,0447Se=qx+x=7,19mm

ScMu H=2m Z=2m

Mz=15/2 = 7,5/2 m:3,75 IR=0,23Nz=7,5/2 = 3.75/2 n=1,875

=0,23x4x223,94=206,02

Sc=0,42x206,02x2=173,06mm

St=173,06+7,2=180,26mm=18cm