half cycle pairs method
TRANSCRIPT
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Half Cycle Pairs Method for
Harmonic Analysis ofCycloconverter Voltage Waveform
Naveed Ashraf, Athar Hanif, Umar
Farooq, Muhammad Usman Asad,
Faiqa Rafiq
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Abstract
A new scheme to determine the harmonic
components of a single-phase cyclo-conveter Computes the Fourier coefficients of the resultant
positive and negative half cycle pairs of the outputvoltage waveform and adds them as one by theprinciple of superposition to determine the Fouriercoefficients of the complete output voltagewaveform.
This broad scheme can be easily extended to theother types of the single-phase and three-phase ac-
ac controllers including the on-off control andphase angle control.
The presented method is theoretically proved usingMATLAB and PSPICE soft wares.
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Cycloconverter
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Proposed Scheme
0 0
1
( ) cos( ) sin( )2 2
n n
n
n t n t v t a a b
=
= + +
1
0
0
o
n
a
a
=
=
/2
1
0
4sin( ).sin( ) ( )
2 2
T
n m
n tb V t d t
T
=
1 2
4 sin( )2
(4 )
m
n
nV
bn
=
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Proposed Scheme (Contd.)
2
/ 2
4sin( ).sin( ) ( )
2 2
T
n m
T
n tb V t d t
T
= 2 2
4 sin( )2
(4 )
m
n
nV
bn
=
1 2n n nb b b= +
2
8 sin( )2
(4 )
m
n
nV
bn
=
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Proposed Scheme (Contd.)
0 0
1
( ) cos( ) sin( )
2 2
n n
n
n t n t v t a a b
=
= + +
0 21,3,5
8 sin( )2( ) sin( )
(4 ) 2
m
n
nV
n tv t
n
=
=
0
if
mf
=0 2 2
1,3,5
8 sin( )2( ) sin( )
( ) 2
m
n
nV
n tv t
m n
=
=
01 2
8 sin( )2( ) sin( )
( 1) 2
mV
tv t
m
=
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Proposed Scheme (Contd.)
1n =
0 2 21,5,73
24 sin( )
3( ) sin( ) sin( )3 ( ) 3
m
m
nn
nV
V n tv t tm n
=
= +
01 224 sin( )
3( ) sin( )( 1) 3
mV
tv tm
=
0 2 21,3,5
32 sin( )[1 cos( )]
4 4( ) sin( )( ) 4
m
n
n nV
n tv t m n
=
+
=
01 2
32 sin( )[1 cos( )]4 4
( ) sin( )( 1) 4
mV t
v t m
+
=
1n =
0 ( ) sin( )
5
mVv t t = +
2 21,3,75
40 sin( )[1 2 cos( )]5 5 sin( )( ) 5
m
nn
n nV
n t
m n
=
+
01 2
40 sin( )[1 2 cos( )]5 5( ) sin( )( 1) 5
m
Vtv t
m
+
=
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Simulation Results
0 5 10 15 20 25 30 350
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
m = 2
Normalize
dAmplitude
Harmonic Order
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Simulation Results (Contd.)
0 5 10 15 20 25 30 350
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
m = 3
NormalizedAmplitude
Harmonic Order
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Simulation Results (Contd.)
0 5 10 15 20 25 30 350
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
m = 4
Normalized
Amplitude
Harmonic Order
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Simulation Results (Contd.)
0 5 10 15 20 25 30 350
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
m = 5
Normalized
Amplitude
Harmonic Order
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Simulation Results (Contd.)
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Conclusions This paper illustrates an easy and simple
approach to find the harmonic componentsof a single phase cycloconverter. Thepresented method for harmonics analysisdescribes that the output voltage wave-form
is formed by summation of half cycle pairs.The harmonic coefficients of the outputvoltage are computed by computing theharmonic coefficients of each individual half
cycle pair. The harmonic coefficients of theoutput voltage are computed with the helpof superposition.
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Questions?