gróf andrea karinthy frigyes gimnázium,...
TRANSCRIPT
Gróf Andrea
Karinthy Frigyes Gimnázium, Budapest
Description of motions
PHYSICS
•Choice of referenceframe emphasized.•But inertial frames usedexclusively.•Students corrected byteacher if they talk aboutcentrifugal force.
GEOGRAPHY
•Idea of reference frame not addressed.•"Natural" reference frame is non-inertial.•Explanations refer tocentrifugaland Coriolis forces.
1. Survey on the understanding of
the physics behind geography
2. A possible introduction to inertial
forces:
merry-go-round example treated
quantitatively
3. Applications in physics and
geography
!
1. Survey on the physics (mechanics) behind
geography
MCQ questions on timekeeping, the shape of the Earth,
motions of air and the seas, tides, etc.
215 students (16 and 17-year olds)
Background: 1 year of physical geography
and 1 year of physics
A.Fcentrifugal << Fcentripetal for fast rotations 11%
B. Fcentrifugal only exists for astronomical sizes 10%
C. Observer does/does not rotate along 17%
D.Fcentrifugal always present, therefore not felt 49%
(no answer 13%)
Questions involving inertial forces
Q
A
Geography: oblate Earth explained in terms of the
centrifugal force.
Physics problems on rotating objects: such forces not
considered.
What is the difference?
N
?Q
S
??
Q
A.South clockwise, north counterclockwise 56%
B. North clockwise, south counterclockwise 21%
C. Same sense 8%
D.Anything may happen 10%
(no answer 5%)
A
https://www.youtube.com/watch?v=4llVfoDuVlw
s
m14.3
3
5.122
T
rv
2
2
2
s
m58.6 r
r
va
N13268.520 maF
A
B
2. Describing motions on a playground
roundabout
The motion of A as seen by B:
s
m64.35.014.3
N177.084.802.0merrynet
maFF
2
22
s
m84.8
5.1
64.3)(
r
uva
Tangential motion as described by the inertial observer B
For rotating observer A:
,s
m17.0
5.1
5.0
2
22
r
ua
0.177NN003.017.002.0net
maF
What other force is there?
FcfFcoriolis
Fmerry= 0.177N
N003.0net
F N132.0cfF
N 042.0
132.0177.0003.0
N177.0merry
F
(inwards)
(inwards)
(outwards)
needed:
(outwards)
r
uvmmaFF
2
merrynet
)(
r
mu
r
mvu
r
mv22
2
r
mvu
r
mvF
r
mu 22
merry
2
0.003 N = 0.177 N – 0.132 N – 0.042 N.
umur
vm
r
mvu 22
2
N042.05.1
5.014.302.02
maFnet
For B
For A
Algebraically:
Fcf
Fcoriolis
Fmerry= 0.177N
For B
a = 0
A
B
ω
The same motion as seen by A:
Radial speed constant
Tangential speed
increasest
rv
t t
trs
trta 2
)(2
1
vt
ra
22
t
t
t
Latitude of Budapest: φ = 47.5º
(a) Magnitude and direction of
the centrifugal acceleration
in Budapest.
(b) Magnitude and direction of the
acceleration of free fall in Budapest?
mgFgrav
Ω
Fcf
(local) verticalWhich way is "down"?
Sports events?
(a) Gravitational, centrifugal acceleration and free
fall acceleration at the Equator?
(b) Athlete can jump to 8 metres at the poles. How
far can he jump on the Equator?
3. Applications: Inertial forces
on the rotating Earth
Coriolis force at the Equator
Air moving at u = 20 m/s towards the west.
Magnitude of acceleration towards the centre of the Earth?
(a) according to an inertial observer?
(b) according to an Earth-based observer?
(c) What is the magnitude and direction of the Coriolis
acceleration?
6
2652
1038.6
20)1038.6)(1029.7()(
R
uRa
2m/s 0369.0
25
6
22
m/s 1027.61038.6
20
R
ua
down)y (verticallm/s 1092.220)1029.7(22235
uaC
PPA
2π·sinφ
Coriolis force elsewhereFoucault pendulum, Paris: φ = 48.8°
What is the local angular speed?
sin
vaC
sin2
φ
φ
A
P
Paris
http://enggar.net/page/12/?s/
3.11rad197.036001049.55
t
In Paris: φ = 48.8°
One period of the Panthéon pendulum is 16.4 sec.
(a) How much does it turn in an hour?
(b) Displacement between two successive swings
on a circle of radius 3 m?
rad1001.94.161049.545
t
mm7.231001.94
rt
s/1049.58.48sin1029.7sin55
r = 2 cm, v = 10 cm/s
(a) Find the acceleration towards
the centre.
(b) What is the contribution of the
Coriolis force to this?
2
22
m/s 5.002.0
1.0
r
va
sin2 vaC
255m/s1015.47sin)103.7(1.02
Is the Coriolis force important?
No
Find (a) radius of spot
1° corresponds to
≈ 9° means r ≈ 1.1·107 m
(b) acceleration of gas
(c) Coriolis acceleration
m102.1360
104.1
360
2 68
R
Jupiter: T = 9.8 hours,
R = 71 900 km (equatorial)
Great Red Spot φ = 22° (S),
wind v ≈ 100 m/s
2
4
s
m109
a
2
4
Cs
m103.1
a Ye
s
www.celestiamotherlode.net/catalog/jupiter.php
http://www.japantimes.co.jp/news/2014/06/18/national/shinkansen-tops-list-100-innovative-postwar-technologies/#.Va84VPkmHpE
Shinkansen train v = 200 km/h
Tokyo to Osaka, both N55°
35sin103.76.3
2002sin2
5va
C
g0005.0s
m0047.0
2
No
Golfer in Scotland (N55°)
can hit the ball to 300 m at 45° angle.
What is the deviation of the ball
owing to the Coriolis force?
g
vt
sin20
g
v
g
vv
cossin2sin2cos
2
000
m3008.98.9
2
1
2
12 2
0
2
0
v
v
,s
m548.9300
0v st 7.8
8.9
45sin542
cossin2 0C va
2
5
s
m0046.045cos5455sin103.72
cm177.80046.02
1
2
1 22
C tad No
Artillery missile, N50°,
v0 = 700 m/s towards the East, at 45° angle.
Deviation owing to the Coriolis force?
g
v
g
vv
cossin2sin2cosRange
2
00
0km50
8.9
2
1
2
17002
2
2
00
2
C
sin2)cossin2(
2
1
2
1
g
vvtad
cossin
sin4 23
02v
g
m28045cos45sin7008.9
50sin103.74 23
2
5
Ye
s
Frictionless and horizontal ice rink, 30 m wide,
Puck given an initial velocity.
Coriolis force only: circular motion
Find:
(a) speed needed in Budapest (N47.5°)
Note:
(b) What is the radius if the speed is 1 m/s?
At 10° latitude? At 80°?
vr
v sin2
2
local2sin2
r
v
s
mm61.0155.47sin103.72sin2
5
rv
km) 7.0 km, (39 km3.95.47sin103.72
1
sin25
vr
An interesting kind of motion
Buoy in the Baltic Sea,
SE of Stockholm, N57°
Design a space station:
• Cylindrical shape
• Artificial gravity is provided
by centrifugal force owing to
spinning about the axis.
• Coriolis force on crew walking
at 1 m/s is no greater than
0.05mg .
gr 2
2s
m1005.0
s
m12
s
125.0
m16025.0
10
22
gr
http://www.astronautix.com/craft/span1984.htm
Both forces to consider
References
Anders O. Persson The Coriolis Effect: Four centuries of conflict between common sense and mathematics, History of Meteorology 2 (2005)
THE END
Thank you for yourattention