frenet eq in physics
TRANSCRIPT
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x = x(s) s
e1, e2 e3
de1ds
= (s)e2 ,
de2ds
= (s)e1 + (s)e3 ,
de3ds
= (s)e2 ,
(s) (s)
(s) (s)e1
dx
ds= e1 ,
dxds = 1
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e2 e3
e3 = [e1e2].
s
d2x
ds2= (s)e2 ,
d3x
ds3=
d(s)
dse2
2(s)e1 + (s)(s)e3 ,
,,e1
dx
ds= cos cos sin sin cos,
dy
ds= sin cos + cos sin cos,
dz
ds= sin sin.
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d
ds=
sin
sin,
d
ds= sin ctg,
dds
= cos.
(s) (s)
x1, x2, x3, 1, 2, 3
x1, x2, x3 xa a = 1, 2, 3
eA, A = 1, 2, 3,
A
d
O
d = de,
ee O
e d
deA = [deA].
ds
deAds
= [d
dseA] = [, eA],
= d/ds
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a) eAeB =
AB =
1 A = B0 A = B
,
b) eA
e
A
=
[] = 1 = 0 =
,
A,B... = 1, 2, 3, , , = 1, 2, 3,
,,... A,B...
deA = de
A or d
= T
dx
,
deAds
=d
dseA or
deAds
= Tdx
dseA,
T = eAe
A, = e
Ae
A,, , =
x.
TAB = eAT
e
B ,
deAds
= TA Bdx
dseB .
e(1), e(2)
e(3)
e(1)
(s) = T(1) (2)dx
ds, (s) = T(2) (3)
dx
ds.
dx
ds= e(1) and e
(1)e
(1) = 1 .
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T[] = ..,
.. = 1
2eA(e
A, e
A,),
0g= ABe
Ae
b, AB =
AB = diag(1, 1, 1),
ds2 =0g dx
dx = ABeAe
bdx
dx .
=
+ T
= eA
eA,
,
=1
2
0g (
0g, +
0g,
0g,)
T = ..+
0g (
0g
..+
0g
..)
..
1, 2, 3
d = dx
,
= eAe
A, = e
Ae
A,.
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=2x
xxx
x+
x
xx
xx
x.
S = 2[,] + 2[||] = 0.
d = 0, dx = 0
d2x
ds2=
dx
ds
dx
ds T
dx
ds
dx
ds.
a)deAds
= dx
dseA + T
dx
dseA, or b)
deAds
= dx
dseA T
dx
dseA,
e (1) = dx/ds,
x1, . . . , xn
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ja = ja(x
k),
a , b , c . . . = 1 . . . n
i , j , k . . . = 1 . . . n
det(ja) = 0
ja
jakb,j
ibka,j = C
..fab
kf,
C..fab
C..fab = C..fba ,
C..afb C..fcd + C
..afc C
..fdb + C
..afdC
..fbc = 0.
n TnC..fab
jbeja
det(eja) = 0.
eja(xk0) =
ja(x
k0),
xk0eja(x
k0)
ejaekb,j e
jbeka,j = C
..fab e
kf.
eaieja =
ji , e
aieib =
ab
C..ijk = 2eiae
a[k,j] = e
iaC
..abce
bje
ck.
..ijk =1
2C..ijk ,
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k[ij] = ..kij = T
k[ij] =
1
2C..ijk .
Sijk
ijk= ijk + (Sijk Sjki Skij),
ijk Sijk
Sijk..ijk
..ijk = ..ikj , S
..ijk = S
..ikj .
..i
jk = ..ijk
xj
xjxk
xkxi
xi, S..i
jk = S..ijk
xj
xjxk
xkxi
xi.
Tijk = ..ijk + g
im(gjs..smk + gks
..smj), K
ijk = S
..ijk + g
im(gjsS..smk + gksS
..smj)
Tijk = Tjik , Kijk = Kjik .
i.jk =2
3i[kj] +
1
3njks
s + i
.jk , Si.jk =
2
3i[kSj] +
1
3njks S
s + Si
.jk ,
i.jk = gimgks
..smj, S
i.jk = g
imgksS..smj
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j = i.ji , Sj = S
i.ji ,
j =1
2jins
ins, Sj =1
2jinsS
ins,
s
.js = 0, ijs + jsi + sij = 0, Ss
.js = 0, Sijs + Sjsi + Ssij = 0.
..ijk
..ijk = 1
2eia(e
aj,k e
ak,j), i, j, i... = 0, 1, 2, 3, a, b, c... = 0, 1, 2, 3,
S..ijk xi
..ijkS..ijk
..ijk
d2 = TabkTbandx
kdxn,
S..ijk
..ijk..ijk
..ijk
..ijk S
..ijk
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x = x(s).
= 0 = 0 = 0 = 0
= 0 = 0
a)de1ds
= (s)e2 , b)de2ds
= (s)e1 , c)de3ds
= 0 ,
a)d2x
ds2= (s)e2 , b)
d3x
ds3=
(s)
dse2
2(s)e1 .
dx
dt= v,
t
v =dx
dt=
dx
ds
ds
dt= e1
ds
dt.
e1
|v| =ds
dt= v.
w = d2x/dt2
w =d2x
ds2
ds
dt2
+ e1d2s
dt2
.
w = e2
ds
dt
2+ e1
d2s
dt2= e2v
2 + e1dv
dt.
m J
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w = e1dv
dt,
wn = e2v2
= 0 = 0
de1ds
= 0 ,de2ds
= (s)e3 ,de3ds
= (s)e2 ,
d2x
ds2= 0 ,
d3x
ds3= 0 .
e1e2
e3 e1ds/dt = v
de1dt
= 0 , de2dt
= e3 , de3
dt= e2 ,
= v
p = mdx
dt,
= v
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= 0 = 0
m
Finer = m(W + [r] + [[r]] + 2[v]) .
F1 = mW
F2 = m[r]
F3 = m[[r]]
F4 = 2m[
v]
r = 0
Finer = mW 2m[v]) .
= v = 0
Finer = mW.
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W = e2v2 + e1
dv
dt.
dv/dt = 0
xi
1, 2 and 3
De(0)
kds =
1e(1)k ,
De(1)k
ds= 1e
(0)k + 2e
(2)k ,
De(2)k
ds= 2e
(1)k + 3e
(3)k ,
De(3)k
ds= 3e
(2)k .
e(0)k , e
(1)k , e
(2)k and e
(3)k D
ijk =1
2gim(gjm , k + gkm, j gjk , m)
e(a)k
d2
xi
ds2= ijk dx
j
dsdx
k
ds Tijk dx
j
dsdx
k
ds.
ijk = ijk + T
ijk = e
iae
aj,k = e
aje
ia,k.
Tijk = eiake
aj = e
ajke
ia,
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keai (e
ja)
eaieja =
ji , e
aieib =
ab ,
ji
a) keaj = T
abke
bj or b) ke
ia = T
ijke
ja.
dxk/ds
Deajds
= Tabkebj
dxk
ds.
Deiads
= Tijkeja
dxk
ds.
ei (0) = dxi/ds
Deakds
= Tabjebk
dxj
ds.
De(0)k
ds= T
(0)(1)je
(1)k
dxj
ds,
De(1)k
ds= T
(1)(0)je
(0)k
dxj
ds+ T
(1)(2)je
(2)k
dxj
ds,
De(2)k
ds= T
(2)(1)je
(1)k
dxj
ds+ T
(2)(3)je
(3)k
dxj
ds,
De(3)k
ds= T
(3)(2)je
(2)k
dxj
ds.
1 = T(0)(1)j
dxj
ds, 2 = T
(1)(2)j
dxj
ds, 3 = T
(2)(3)j
dxj
ds.
Tikj
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[keam] e
b[kT
a|b|m] = 0, (A)
Rabkm + 2[kTa|b|m] + 2T
ac[kT
c|b|m] = 0, (B)
[keaj] + T
i[kj]e
ai = 0, (A)
Rjm 1
2gjmR = Tjm, (B.1)
Cijkm + 2[kTi,|j|m] + 2T
is[kT
s,|j|m] = J
ijkm , (B.2)
Tjm = 2
{([iT
i|j|m] + T
is[iT
s|j|m])
1
2gjmgpn
([iTi
|p|n] + Ti
s[iTs
|p|n])}
Jijkm = 2g[k(iTj)m] 1
3T gi[mgk]j .
(A) (B)
Rik = 0
(B.1)
(A) (B)
CDiAB AB
iCD = (TCD)
PA
iPB +
iAR(T
+DC
) RB
(TAB)P
C iPD
iCR(T
+BA
) RD , (+
A s)
2ABCD + ABCD = TACBD , (+B s+.1)
CABCD CDTAB + ABTCD + (TCD)F
A TFB + (T+DC
) FBTAF
(TAB)F
C TFD (T+BA
) FDTCF [TAB , TCD] = JABCD , (+
B s+.2)
A, C... = 0, 1 , B, D... = 0, 1 .
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ds2 =
1
20
r
c2dt2
1
20
r
1dr2 r2(d2 + sin2 d2),
0 = MG/c2,
u, r, x2 and x3
i00 = (0, 1, 0, 0), i11 = (1, U, 0, 0),
i01 = (0, 0,P,iP),
00i = (1, 0, 0, 0), 11i = (U, 1, 0, 0),
01i =
1
2P(0, 0, 1, i),
U = 1/2 + 0
/r, P = (2)1/2
(1 + /4), = x2
+ ix3
,0 = .
= 1/r, = = 0/r, = 0/2r,
= 0/r + 20/r2, = /4.
= 0/r3.
(ijk)(Tijk)
ds2 = (1 2MG
rc2)c2dt2 (1 +
2MG
rc2)(dx2 + dy2 + dz2) .
eai
e(0)
0 = (1 +2
c2)1/2 ,
e(1)
1 = e(2)
2 = e(3)
3 = (1 2
c2)1/2 ,
= MG/r
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gik = abeaiebk , ab =
ab = diag(1 1 1 1).
2
c2
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mx = eE+e
c[xH] +
2e2
3c3...x ,
2e2
3c3...x
t
x = ve1, x = ae1 + kv2e2
...x= (a 2v3)e1 + (3va + v
2)e2 + v3e3,
x = dx/dt, ds = vdt, a = v, a = d3/dt3 = d/dt.
Frad =2e2
3c3{(a 2v3)e1 + (3va + v
2)e2 + v3e3}.
=h
mc= 3, 6 1011sm.
s = J = Jv =h
2,
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J
J =2
5m2,
= v
1021rad/s.
(E 108 V/sm) Fe Fg
|Fe| = eE = mihte = mv
2e =e2
r20 4, 8 102 ,
|Fg| = mG = mintg = mv
2g =mMn
r
2
0
0, 6 1042 din.
|F| =2e2
3c3int.
int = v2 1025 sm/s2
F 2, 9 104 din.
(A) (B)
[iTi|j|m] + T
is[iT
s|j|m] = 0,
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(A) (B)
E =
Tjmgjm(g)1
2 dV 0.
Tijk
d2xi
ds2+ ijk
dxj
ds
dxk
ds+ Tijk
dxj
ds
dxk
ds= 0,
Rijkm
M
s = MGrr2 + r2scos
2,
rsr rs
r rs
(s) = T(2) (3)dx
ds
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