fermion masses and unification
DESCRIPTION
Fermion Masses and Unification. Steve King University of Southampton. Lecture III Family Symmetry and Unification. 1.Introduction to family symmetry 2.Froggatt-Nielsen mechanism 3.Gauged U(1) family symmetry and its shortcomings - PowerPoint PPT PresentationTRANSCRIPT
Fermion Masses and Unification
Steve King
University of Southampton
Lecture III Family Symmetry and Unification
1.Introduction to family symmetry2.Froggatt-Nielsen mechanism3.Gauged U(1) family symmetry and its shortcomings4.Gauged SO(3) family symmetry and vacuum alignment 5.A4 and vacuum alignment6. A4 Pati-Salam Theory
Appendix A. A4
Appendix B. Finite Groups
3 3
3 2 2
3 2
0
1
uY
• Universal form for mass matrices, with Georgi-Jarlskog factors
• Texture zero in 11 position
Recall Symmetric Yukawa textures
3 3
3 2 2
3 2
0
1
dY
3 3
3 2 2
3 2
0
3 3
3 1
eY
0.05, 0.15
1( ) , ( ) 3
3s d
GUT GUTe
m mM M
m m
1. Introduction to Family Symmetry
To account for the fermion mass hierarchies we introduce a spontaneously broken family symmetry
It must be spontaneously broken since we do not observe massless gauge bosons which mediate family transitions
The Higgs which break family symmetry are called flavons
The flavon VEVs introduce an expansion parameter = < >/M where M is a high energy mass scale
The idea is to use the expansion parameter to derive fermion textures by the Froggatt-Nielsen mechanism (see later)
In SM the largest family symmetry possible is the symmetry of the kinetic terms
36
1
, , , , , , (3)c c c ci i
i
D Q L U D E N U
In SO(10) , = 16, so the family largest symmetry is U(3)
Candidate continuous symmetries are U(1), SU(2), SU(3) or SO(3) etc
If these are gauged and broken at high energies then no direct low energy signatures
U(1)
SU(2)
SU(3) SO(3)
S(3)Nothing
(3) (3)L RO O
(3) (3)L RS S27
GFamily
4 12A
Simplest example is U(1) family symmetry spontaneously broken by a flavon vev
For D-flatness we use a pair of flavons with opposite U(1) charges
0 ( ) ( )Q Q
Example: U(1) charges as Q (3 )=0, Q (2 )=1, Q (1 )=3, Q(H)=0, Q( )=-1,Q()=1
Then at tree level the only allowed Yukawa coupling is H 3 3 !
0 0 0
0 0 0
0 0 1
Y
The other Yukawa couplings are generated from higher order operators which respect U(1) family symmetry due to flavon insertions:
2 3 4 6
2 3 2 2 1 3 1 2 1 1H H H H HM M M M M
M
When the flavon gets its VEV it generates small effective Yukawa couplings in terms
of the expansion parameter
6 4 3
4 2
3 1
Y
1 0 1 0 0
2.Froggatt-Nielsen Mechanism
What is the origin of the higher order operators?
To answer this Froggat and Nielsen took their inspiration from the see-saw mechanism
2
R
L L
H
M
2 3HM
Where are heavy fermion messengers c.f. heavy RH neutrinos
L LR R
M
H H
RM
2M
H
3
M
There may be Higgs messengers or fermion messengers
2
M
0H
30
1
0
2 3
1
0H
1H1H HM
Fermion messengers may be SU(2)L doublets or singlets
2QQ
M
0H
3cU0
Q
1
0Q 2Q
cU
M
0H
3cU1
cU
1
1cU
3. Gauged U(1) Family SymmetryProblem: anomaly cancellation of SU(3)C
2U(1), SU(2)L2U(1) and U(1)Y
2U(1) anomalies implies that U(1) is linear combination of Y and B-L (only anomaly free U(1)’s available) but these symmetries are family independent
Solution: use Green-Schwartz anomaly cancellation mechanism by which anomalies cancel if they appear in the ratio:
Suppose we restrict the sums of charges to satisfy
Then A1, A2, A3 anomalies are cancelled a’ la GS for any values of x,y,z,u,v
But we still need to satisfy the A1’=0 anomaly cancellation condition.
The simplest example is for u=0 and v=0 which is automatic in SU(5)GUT
since10=(Q,Uc,Ec) and 5*=(L,Dc) qi=ui=ei and di=li so only two independent ei, li.
In this case it turns out that A1’=0 so all anomalies are cancelled.
Assuming for a large top Yukawa we then have:
SO(10) further implies qi=ui=ei=di=li
F=(Q,L) and Fc=(Uc,Dc,Ec,Nc)
In this case it turns out that A1’=0. PS implies x+u=y and x=x+2u=y+v.
So all anomalies are cancelled with u=v=0, x=y. Also h=(hu, hd)
The only anomaly cancellation constraint on the charges is x=y which implies
Note that Y is invariant under the transformations
This means that in practice it is trivial to satisfy
A Problem with U(1) Models is that it is impossible to obtain
3 3
3 2 2
3 2
0
1
Y
For example consider Pati-Salam where there are effectively no constraints on the charges from anomaly cancellation
There is no choice of li and ei that can give the desired texture6 4 3
4 2
3 1
Y
e.g. previous example l1=e1=3, l2=e2=1, l3=e3=hf=0 gave:
Shortcomings of U(1) Family Symmetry
The desired texture can be achieved with non-Abelian family symmetry. Another motivation for non-Abelian family symmetry comes from neutrino physics.
columns
SFKSequential dominance can account for large neutrino mixing
T T T
LL
AA BB CCm
X Y Z See-saw
Sequential dominance Dominant
m3
Subdominant m2
Decoupled m1
Diagonal RH nu basis
Tri-bimaximal
†LV
Constrained SD
Large lepton mixing motivates non-Abelian family symmetry
1
2 2
3 3
0
LR
B
Y A B
A B
Need
Suitable non-Abelian family symmetries must span all three families e.g.
2$ 3 symmetry (from maximal atmospheric mixing)
1$ 2 $ 3 symmetry (from tri-maximal solar mixing)
SFK, Ross; Velasco-Sevilla; Varzelias
SFK, Malinsky
with CSD
27
4
(3)
(3)
SU
SO A
4. Gauged SO(3) family symmetry
Antusch, SFK 04
Left handed quarks and leptons are triplets under SO(3) family symmetryRight handed quarks and leptons are singlets under SO(3) family symmetry
123
a
b
c
23
0
e
f
3
0
0
h
Real vacuum alignment
(a,b,c,e,f,h real)Barbieri, Hall, Kane,
Ross
To break the family symmetry introduce three flavons 3, 23, 123
But this is not sufficient to account
for tri-bimaximal neutrino mixing
2
2
2 3
1
1
0
0
0 i
iLR
i
i
i i
ee
fe
Y
he
ae
be
ce
123
a
b
c
23
0
e
f
3
0
0
h
123. RF h 2
123. RF h 13. RF h
If each flavon is associated with a particular right-handed neutrino
then the following Yukawa matrix results
1 2 323 123 3
1 1 1i i ii R i R i RHL HL HL
M M M
2
2
1
3
2
1
0
0
0 i
Li
iR
i
i i
ve
v
ve
ve
ve
Y
e Ve
123
v
v
v
23
0
v
v
3
0
0
V
123. RF h 2
123. RF h 33. RF h
1
M
For tri-bimaximal neutrino mixing we need
The motivation for 123 is to give the second column required by tri-bimaximal neutrino mixing
How do we achieve such a vacuum alignment of the flavon vevs?
Vacuum Alignment in SO(3)
First set up an orthonormal basis:
1
23
FA=0 flatness <1>=1
FB=0 flatness <2>=2
FC=0 flatness <3>=3
FD=0 flatness 1 .2 =0FE=0 flatness 1 .3 =0FF=0 flatness 2 .3 =0
SFK ‘05
1
1
0
0
2
0
1
0
3
0
0
1
1
23
Then align 23 and 123 relative to 1 , 2 , 3 using additional terms:
FR=0 <23> gets vevs in the (2,3) directions FT=0 <123> gets vevs in the (1,2,3) directions
(vevs of equal magnitude are required to minimize soft mass terms)
23
0
1
1
123
1
1
1
Finally 23 is orthogonal to 123 due to 123
. 23
=0
1
3
223
123
De M.Varzielas, SFK, Ross
We can replace SO(3) by a discrete A4 subgroup:
4 (3)A SO
A4 is similar to the semi-direct product
Same invariants as A4
2=12+2
2+32 ,
3 =1 2 3
The main advantage of using discrete family symmetry groups is that vacuum alignment is simplified…
5. A4 and Vacuum Alignment
The Diamond (A4) Crystal Structure
0,1,1
1,1,1
Radiative Vacuum AlignmentVarzielas, SFK, Ross, Malinsky
0
(s)top loops drive negative
A nice feature of MSSM is radiative EWSB Ibanez-Ross
ZM GUTM
2 2
uHm
2
uHm
H H3LQ
Rt
Similar mechanism can be used to drive flavon vevs using D-terms
Leads to desired vacuum alignment with discrete family symmetry A4
negative
for negative
for positive
23 (0,1, 1)T v
3123
for positive 123
Symmetry group of the tetrahedron
Discrete set of possible vacua
Ma; Altarelli, Feruglio; Varzeilas, Ross, SFK, Malinsky
4A
Comparison of SO(3) and A4
(3,4,2,1)i
L
L
u
e
uF
u
dd d
(1,4,1,2)i
i iR
R
uuF
u
ed d d
SFK, Malinsky
4 (4) (2) (2)PS L RA SU SU SU
6. A4 Pati-Salam Theory
Dirac Operators:
Further Dirac Operators required for quarks:
Dirac Operators: Dirac Neutrino matrix:
. .
. .
Majorana Operators
223 2
2123
0 0
0 0
0 0 1RR
HM
M
•CSD in neutrino sector due to vacuum alignment of flavons
• m3 » m2 » 1/ and m1» 1 is much smaller since ¿ 1
•See-saw mechanism naturally gives m2» m3 since the cancel
Dirac Neutrino matrix:
Majorana Neutrino matrix:
The Messenger Sector
Majorana:
Dirac:
Including details of the messenger sector:
Messenger masses:
Appendix A. A4SFK, Malinsky hep-ph/0610250
Appendix B. Finite Groups Ma 0705.0327