extreme values of functions

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Section 4.1b EXTREME VALUES OF FUNCTIONS

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Extreme Values of Functions. Section 4.1b. Do Now. Find the extreme values of:. First, check the graph  What does it suggest?. What is the domain of the function?. Since there are no endpoints, all extreme values must occur at critical points. Find the derivative:. Do Now. - PowerPoint PPT Presentation

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Page 1: Extreme Values of Functions

Section 4.1b

EXTREME VALUES OF FUNCTIONS

Page 2: Extreme Values of Functions

Find the extreme values of:

2

1

4f x

x

1 224 x

Do Now

First, check the graph What does it suggest?

What is the domain of the function? : 2, 2D Since there are no endpoints, all extreme values must occurat critical points. Find the derivative:

3 221 4 22

f x x x

3 224

x

x

Page 3: Extreme Values of Functions

Find the extreme values of:

2

1

4f x

x

1 224 x

Do Now

No Maxima, Minimum of 1/2 at x = 0

3 224

xf xx

The only critical point in thedomain is at x = 0…

Check the original function:

2

104 0

f

12

As x moves away from 0 on eitherside denominator gets smallerValue of f increases the graphrises We have a minimum!!!

Page 4: Extreme Values of Functions

Extrema can occur at critical points and endpoints, butnot every critical point or endpoint automaticallysignals an extrema!!!

An Important Note

3 5( )k x x 2 3x

Ex: Find the extrema of the following function using bothanalytic and graphical methods:

2 53( )5

k x x

Start with the graph…

2 5

35x

Derivative is never zero,and is undefined at x = 0.

Page 5: Extreme Values of Functions

Extrema can occur at critical points and endpoints, butnot every critical point or endpoint automaticallysignals an extrema!!!

An Important Note

3 5( )k x x 2 3x

Ex: Find the extrema of the following function using bothanalytic and graphical methods:

Start with the graph…

Critical Point: 0x Endpoint: 3x But only the endpoint signals an extrema:

Maximum of at3 53 3x

Page 6: Extreme Values of Functions

More Practice Problems

3 2 4f x x x

36 6 62 43 3 3

f

Find the extreme values of the given function.

23 2f x x

Critical points:23

x Consider the graph! 6

3

2 6 2 6 49 3

4 6 369

5.089

Page 7: Extreme Values of Functions

More Practice Problems

3 2 4f x x x

36 6 62 43 3 3

f

Find the extreme values of the given function.

23 2f x x

Critical points:23

x Consider the graph! 6

3

2 6 2 6 49 3

4 6 369

2.911

Page 8: Extreme Values of Functions

More Practice Problems

3 2 4f x x x

Local Max of at

Find the extreme values of the given function.

23 2f x x

4 6 369 6

3x

Local Min of at4 6 369

63

x

Page 9: Extreme Values of Functions

More Practice ProblemsFind the extreme values of the given function.

25 2 ,

2,x

f xx

11

xx

First, sketch the graph…

It appears that the derivative is zero at x = 0, and doesnot exist at x = 1. There appears to be a local max of5 at x = 0 and a local min of 3 at x = 1.

Page 10: Extreme Values of Functions

More Practice ProblemsFind the extreme values of the given function.

25 2 ,

2,x

f xx

11

xx

Critical Points atx = 0 and x = 1

Local Max of 5 at x = 0,Local Min of 3 at x = 1

How do we confirm this result analytically?

4 , 11, 1x x

f xx

Derivative is zero at x = 0Left- and right-hand derivativesare not equal at x = 1

Page 11: Extreme Values of Functions

More Practice ProblemsFind the extreme values of the given function.

2 3y x x Start by checking the graph…

2 1 1 2 32 3

dy x x xdx x

2 4 32 3 2 3

x xxx x

25 122 3x x

x

Derivative is zero at x = 0 and x = 12/5

Derivative is undefined at x = 3

Page 12: Extreme Values of Functions

More Practice ProblemsFind the extreme values of the given function.

2 3y x x Start by checking the graph…25 12

2 3dy x xdx x

C.P. Derivative Extremum Value

x = 0x = 12/5x = 3

00

Und.

Min.Local Max.

Min.

0

04.462