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Higher Mathematics Exam Revision 4(non-calculator) 1. [SQA] Part Marks Level Calc. Content Answer U1 OC1 (a) 3 C CN G5, G3 1994 P2 Q2 (b) 2 C CN G1 (c) 2 C CN G1 hsn .uk.net Page 1 Questions marked ‘[SQA]’ c SQA All others c Higher Still Notes

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Page 1: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

Exam Revision 4(non-calculator)

1.[SQA]

Part Marks Level Calc. Content Answer U1 OC1

(a) 3 C CN G5, G3 1994 P2 Q2

(b) 2 C CN G1

(c) 2 C CN G1

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Page 2: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

2.[SQA] P, Q and R have coordinates (1,−2) , (6, 3) and (9, 14) respectively and are threevertices of a kite PQRS.

(a) Find the equations of the diagonals of this kite and the coordinates of the pointwhere they intersect. 7

(b) Find the coordinates of the fourth vertex S. 2

Part Marks Level Calc. Content Answer U1 OC1

(a) 7 C CN G8, G3, G5 1990 P2 Q2

(b) 2 C CN G8

3.[SQA] The graph of a function f intersects thex -axis at (−a, 0) and (e, 0) as shown.

There is a point of inflexion at (0, b) and amaximum turning point at (c, d) .

Sketch the graph of the derived function f ′ . 3

O x

y

(−a, 0)

(0, b)

(c, d)

(e, 0)

y = f (x)

Part Marks Level Calc. Content Answer U1 OC3

3 C CN A3, C11 sketch 2002 P1 Q6

•1 ic: interpret stationary points•2 ic: interpret main body of f•3 ic: interpret tails of f

•1 roots at 0 and c (accept a statement tothis effect)

•2 min. at LH root, max. between roots•3 both ‘tails’ correct

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Page 3: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

4.[SQA] A company spends x thousandpounds a year on advertisingand this results in a profit of Pthousand pounds. A mathematicalmodel , illustrated in the diagram,suggests that P and x are related byP = 12x3 − x4 for 0 ≤ x ≤ 12.Find the value of x which gives themaximum profit. 5

O x(12, 0)

P

Part Marks Level Calc. Content Answer U1 OC3

5 C NC C11 x = 9 2001 P1 Q6

•1 ss: start diff. process•2 pd: process•3 ss: set derivative to zero•4 pd: process•5 ic: interpret solutions

•1 dPdx = 36x2 . . . or dPdx = . . .− 4x3•2 dPdx = 36x2 − 4x3•3 dPdx = 0•4 x = 0 and x = 9•5 nature table about x = 0 and x = 9

5.[SQA] Find the equation of the tangent to the curve with equation y = 5x3 − 6x2 at thepoint where x = 1. 4

Part Marks Level Calc. Content Answer U1 OC3

4 C NC C4, G3 1992 P1 Q1

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Page 4: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

6.[SQA] A sequence is defined by the recurrence relation un+1 = 0·3un + 5 with first termu1 .

(a) Explain why this sequence has a limit as n tends to infinity. 1

(b) Find the exact value of this limit. 2

Part Marks Level Calc. Content Answer U1 OC4

(a) 1 C CN A12 1996 P1 Q11

(b) 2 C CN A13

7.[SQA]

Part Marks Level Calc. Content Answer U2 OC1

(a) 4 C NC A4 1996 P2 Q4

(b) 7 C NC A17, A18, A6

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Page 5: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

8.[SQA] The diagram shows a sketch of thegraph of y = x3 − 3x2+ 2x .(a) Find the equation of thetangent to this curve at thepoint where x = 1. 5

(b) The tangent at the point (2, 0)has equation y = 2x− 4. Findthe coordinates of the pointwhere this tangent meets thecurve again. 5

Ox

y

y = x3 − 3x2+ 2x

Part Marks Level Calc. Content Answer U2 OC1

(a) 5 C CN C5 x+ y = 1 2000 P2 Q1

(b) 5 C CN A23, A22, A21 (−1,−6)

•1 ss: know to differentiate•2 pd: differentiate correctly•3 ss: know that gradient = f ′(1)•4 ss: know that y-coord = f (1)•5 ic: state equ. of line

•6 ss: equate equations•7 pd: arrange in standard form•8 ss: know how to solve cubic•9 pd: process•10 ic: interpret

•1 y′ = . . .•2 3x2 − 6x+ 2•3 y′(1) = −1•4 y(1) = 0•5 y− 0 = −1(x− 1)

•6 2x− 4 = x3 − 3x2 + 2x•7 x3 − 3x2 + 4 = 0

•8· · · 1 −3 0 4

· · · · · · · · ·· · · · · · · · · · · ·

•9 identify x = −1 from working•10 (−1,−6)

9. (a)[SQA] Given that x+ 2 is a factor of 2x3 + x2 + kx+ 2, find the value of k . 3

(b) Hence solve the equation 2x3 + x2 + kx+ 2 = 0 when k takes this value. 2

Part Marks Level Calc. Content Answer U2 OC1

(a) 3 C CN A21 k = −5 2001 P2 Q1

(b) 2 C CN A22 x = −2, 12 , 1

•1 ss: use synth division orf (evaluation)

•2 pd: process•3 pd: process

•4 ss: find a quadratic factor•5 pd: process

•1 f (−2) = 2(−2)3 + · · ·•2 2(−2)3 + (−2)2 − 2k+ 2•3 k = −5

•4 2x2 − 3x + 1 or 2x2 + 3x − 2 orx2 + x− 2

•5 (2x− 1)(x− 1) or (2x− 1)(x+ 2) or(x+ 2)(x− 1)and x = −2, 12 , 1

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Higher Mathematics

10. (a) (i) Show that (x− 1) is a factor of f (x) = 2x3 + x2 − 8x+ 5.

(ii) Hence factorise f (x) fully. 5

(b) Solve 2x3 + x2− 8x+ 5 = 0. 1

(c) The line with equation y = 2x − 3 is a tangent to the curve with equationy = 2x3 + x2 − 6x+ 2 at the point G.

Find the coordinates of G. 5

(d) This tangent meets the curve again at the point H.

Write down the coordinates of H. 1

Part Marks Level Calc. Content Answer U2 OC1

(a) 5 C CN A21 (x− 1)(x− 1)(2x+ 5) 2010 P1 Q22

(b) 1 C CN A22 x = 1,− 52(c) 5 C CN A23 (1,−1)(d) 1 C CN A23 (− 52 ,−8)

•1 ss: know to use x = 1•2 ic: complete evaluation•3 ic: state conclusion•4 pd: find quadratic factor•5 pd: factorise completely

•6 ic: state solutions

•7 ss: set ycurve = yline•8 ic: express in standard form•9 ss: compare with (a) or factorise•10 ic: identify xG•11 pd: evaluate yG

•12 pd: state solution

•1 evaluating at x = 1...•2 2+ 1− 8+ 5 = 0•3 (x− 1) is a factor•4 (x− 1)(2x2 + 3x− 5)•5 (x− 1)(x− 1)(2x+ 5)

•6 x = 1 and x = − 52

•7 2x3 + x2 − 6x+ 2 = 2x− 3•8 2x3 + x2 − 8x+ 5 = 0•9 (x− 1)(x− 1)(2x+ 5) = 0•10 x = 1•11 y = −1

•12 (− 52 ,−8)

11.[SQA] One root of the equation 2x3 − 3x2 + px+ 30 = 0 is −3.Find the value of p and the other roots. 4

Part Marks Level Calc. Content Answer U2 OC1

4 C NC A21 1993 P1 Q7

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Higher Mathematics

12.[SQA] Functions f and g are defined on the set of real numbers by f (x) = x − 1 andg(x) = x2 .

(a) Find formulae for

(i) f(

g(x))

(ii) g(

f (x))

. 4

(b) The function h is defined by h(x) = f(

g(x))

+ g(

f (x))

.

Show that h(x) = 2x2 − 2x and sketch the graph of h . 3

(c) Find the area enclosed between this graph and the x -axis. 4

Part Marks Level Calc. Content Answer U2 OC2

(a) 4 C NC A4 1999 P2 Q6

(b) 3 C NC A4

(c) 4 C NC C16

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Higher Mathematics

13.[SQA]

Part Marks Level Calc. Content Answer U2 OC2

(a) 2 C NC A23 1993 P2 Q2

(b) 4 C NC C16

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Higher Mathematics

14.[SQA] A firm asked for a logo to bedesigned involving the letters Aand U. Their initial sketch isshown in the hexagon.

A mathematical representationof the final logo is shown in thecoordinate diagram.

The curve has equationy = (x + 1)(x − 1)(x − 3) andthe straight line has equationy = 5x − 5. The point (1, 0) isthe centre of half-turn symmetry.

Calculate the total shaded area. 7

x

y

(−2,−15)

(4, 15)

−2 −1 0 1 2 3 4

Part Marks Level Calc. Content Answer U2 OC2

7 C CN C17 4012 units2 2001 P2 Q8

•1 ss: express in standard form•2 ss: split area and integrate•3 ss: subtract functions•4 pd: process•5 pd: process•6 pd: process•7 ic: use symmetry or otherwise fortotal area

•1 y = x3 − 3x2 − x+ 3

•2∫ 41 (. . .)dx or

∫ 1−2(. . .)dx

•3∫ [

(5x− 5) − (x3 − 3x2 − x+ 3)]

dxor

∫ [

(x3 − 3x2 − x+ 3) − (5x− 5)]

dx•4

(−x3 + 3x2 + 6x− 8)dx•5

[

− 14x4 + x3 + 3x2 − 8x]

•6 2014 or −2014 depending on chosenintegrals

•7 4012

15.[SQA] A curve for whichdy

dx= 6x2 − 2x passes through the point (−1, 2) .

Express y in terms of x . 3

Part Marks Level Calc. Content Answer U2 OC2

3 C NC C18 1998 P1 Q10

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Higher Mathematics

16.[SQA]

Part Marks Level Calc. Content Answer U2 OC3

(a) 2 C CN CGD 1991 P2 Q3

(a) 1 A/B CN CGD

(b) 5 C CN T10, T11

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Higher Mathematics

17.[SQA] The diagram shows the graph of acosine function from 0 to π .

(a) State the equation of the graph. 1

(b) The line with equation

y = −√3 intersects this

graph at point A and B.

Find the coordinates of B. 3

O x

y

A B y = −√3

π

2

−2

Part Marks Level Calc. Content Answer U2 OC3

(a) 1 C NC T4 y = 2 cos 2x 2002 P1 Q8

(b) 3 C NC T7 B( 7π12 ,−√3)

•1 ic: interpret graph

•2 ss: equate equal parts•3 pd: solve linear trig equation inradians

•4 ic: interpret result

•1 2 cos 2x

•1 2 cos 2x = −√3

•2 2x = 5π6 ,7π6

•3 x = 7π12

18.[SQA]

Part Marks Level Calc. Content Answer U2 OC3

3 C CN T8 1996 P1 Q15

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Higher Mathematics

19.[SQA] On the coordinate diagram shown, A is thepoint (6, 8) and B is the point (12,−5) .Angle AOC = p and angle COB = q .

Find the exact value of sin(p+ q) . 4

O x

yA(6, 8)

C

B(12,−5)

pq

Part Marks Level Calc. Content Answer U2 OC3

4 C NC T9 6365 2000 P1 Q1

•1 ss: know to use trig expansion•2 pd: process missing sides•3 ic: interpret data•4 pd: process

•1 sin p cos q+ cos p sin q•2 10 and 13•3 8

10 · 1213 + 610 · 513

•4 126130

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Higher Mathematics

20.[SQA]

Part Marks Level Calc. Content Answer U2 OC4

(a) 4 C CN G5, G3 1991 P2 Q2

(b) 6 C CN G10, G1

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Page 14: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

21.[SQA] Find the equation of the tangent at the point (3, 1) on the circlex2 + y2 − 4x+ 6y− 4 = 0. 5

Part Marks Level Calc. Content Answer U2 OC4

5 C CN G11 1991 P1 Q8

22.[SQA] For what range of values of k does the equation x2 + y2 + 4kx − 2ky− k − 2 = 0represent a circle? 5

Part Marks Level Calc. Content Answer U2 OC4

5 A NC G9, A17 for all k 2000 P1 Q6

•1 ss: know to examine radius•2 pd: process•3 pd: process•4 ic: interpret quadratic inequation•5 ic: interpret quadratic inequation

•1 g = 2k, f = −k, c = −k− 2stated or implied by •2

•2 r2 = 5k2 + k+ 2•3 (real r ⇒) 5k2 + k+ 2 > 0 (accept ≥)•4 use discr. or complete sq. or diff.•5 true for all k

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Higher Mathematics

23.[SQA]

Part Marks Level Calc. Content Answer U3 OC1

(a) 3 C CN G10 1998 P2 Q6

(b) 3 C CN G9, G25

(c) 3 A/B CN CGD

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Page 16: ExamRevision4(non-calculator)mnthighermaths.weebly.com/uploads/2/7/4/0/27407547/exam_revisi… · Higher Mathematics 10. (a) (i) Show that (x−1) is a factor of f(x) = 2x3 +x2 −8x+5.(ii)

Higher Mathematics

24.[SQA] VABCD is a pyramid with a rectangular base ABCD.

Relative to some appropriate axes,

−→VA represents −7i − 13 j − 11k−→AB represents 6i + 6 j − 6k−→AD represents 8i − 4 j + 4k .

K divides BC in the ratio 1 : 3.

Find−→VK in component form. 3

A B

CD

V

K1

3

Part Marks Level Calc. Content Answer U3 OC1

3 C CN G25, G21, G20

1−8−16

2000 P1 Q7

•1 ss: recognise crucial aspect•2 ic: interpret ratio•3 pd: process components

•1 −→VK =

−→VA +

−→AB +

−→BK or−→

VK =−→VB+

−→BK

•2 −→BK = 1

4

−→BC or 14

−→AD or

2−11

or

−1−7−17

•3 −→VK =

1−8−16

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Higher Mathematics

25.[SQA]

Part Marks Level Calc. Content Answer U3 OC1

1 C CN G26 1997 P1 Q13

3 A/B CN G29, G27

26.[SQA] Given that f (x) = (5x− 4) 12 , evaluate f ′(4) . 3

Part Marks Level Calc. Content Answer U3 OC2

1 C CN C21 58 2000 P2 Q8

2 A/B CN C21

•1 pd: differentiate power•2 pd: differentiate 2nd function•3 pd: evaluate f ′(x)

•1 12(5x− 4)−12

•2 ×5•3 f ′(4) = 5

8

27. (a)[SQA] Find the derivative of the function f (x) = (8− x3) 12 , x < 2. 2

(b) Hence write down∫

x2

(8− x3) 12dx . 1

Part Marks Level Calc. Content Answer U3 OC2

(a) 2 A/B CN C21 − 32x2(8− x3)−12 2002 P1 Q10

(b) 1 A/B CN C24 − 23(8− x3)12 + c

•1 pd: process differentiation•2 pd: use the chain rule

•3 ic: interpret answer from (a)

•1 12(8− x3)−12

•2 . . .×−3x2

•3 − 23 f (x) or − 23(8− x3)12

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Higher Mathematics

28.[SQA] Given f (x) = (sin x+ 1)2 , find the exact value of f ′(π

6 ) . 3

Part Marks Level Calc. Content Answer U3 OC2

3 A/B NC C21, C20, T2 1998 P1 Q16

29.[SQA] Find∫

(

6x2 − x+ cos x)

dx . 4

Part Marks Level Calc. Content Answer U3 OC2

4 C NC C23 1995 P1 Q3

30.[SQA] The curve y = f (x) passes through the point ( π

12 , 1) and f′(x) = cos 2x .

Find f (x) . 3

Part Marks Level Calc. Content Answer U3 OC2

3 A/B NC C23 1997 P1 Q15

31.[SQA] Find x if 4 logx 6− 2 logx 4 = 1. 3

Part Marks Level Calc. Content Answer U3 OC3

3 C NC A32, A28, A31 x = 81 2001 P1 Q8

•1 pd: use log-to-index rule•2 pd: use log-to-division rule•3 ic: interpret base for logx a = 1 andsimplify

•1 logx 64 − logx 42•2 logx 6

4

42

•3 all processing leading to x = 81

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Higher Mathematics

32. (a) The expression 3 sin x− 5 cos x can be written in the form R sin(x+ a) whereR > 0 and 0 ≤ a < 2π .

Calculate the values of R and a . 4

(b) Hence find the value of t , where 0 ≤ t ≤ 2, for which

t∫

0

(3 cos x+ 5 sin x) dx = 3.

7

Part Marks Level Calc. Content Answer U3 OC4

(a) 4 C CN T13 R =√34, a = 5·253 2011 P2 Q6

(b) 7 B CN C23, T3, T16 t = 0·6

•1 ss: use compound angle formula•2 ic: compare coefficients•3 pd: process R•4 pd: process a

•5 pd: integrate given expression•6 ic: substitute limits•7 pd: process limits•8 ss: know to use wave equation•9 ic: write in standard format•10 ss: start to solve equation•11 pd: complete and state solution

•1 R sin x cos a+ R cos x sin a•2 R cos a = 3 and R sin a = −5•3

√34 (accept 5·8)

•4 5·253 (accept 5·3)

•5 3 sin x− 5 cos x•6 (3 sin t− 5 cos t) − (3 sin 0− 5 cos 0)•7 3 sin t− 5 cos t+ 5•8

√34 sin(t+ 5·3) + 5

•9 sin(t+ 5·3) = − 2√34

•10 t+ 5·3 = 3·5, 5·9•11 t = 0·6

33.[SQA] Find the maximum value of cos x− sin x and the value of x for which it occurs inthe interval 0 ≤ x ≤ 2π . 6

Part Marks Level Calc. Content Answer U3 OC4

6 A/B CN T14 max value√2 when

x = 7π4

2000 P1 Q10

•1 ss: use e.g. k cos(x+ a)•2 ic: expand chosen rule•3 pd: compare coefficients•4 pd: process•5 pd: process•6 ic: interpret trig expression

•1 e.g. use k cos(x+ a)•2 k cos x cos a− k sin x sin a•3 k cos a = 1 and k sin a = 1•4 k =

√2

•5 tan a = 1, a = π

4 (45◦ is bad form)

•6 max. value =√2 when x = 7π

4 (donot accept 45◦)

[END OF QUESTIONS]

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