equipment 2. photoelectric effect. einstein’s photon theory (...
TRANSCRIPT
equipment
2. Photoelectric Effect. Einstein’s Photon Theory ( 光电效应、爱因斯坦光子理论 )
R
K1
K2
E
G
V
les, called photons.
Einstein assumed that the energy in a light beam travelsthrough space in concentratedbund pi
The energy E of a single photon is given by E = hv . Applying the photon concept to the photoelectric effect, Einstein wrote
SI
Si
光电管K
A
)10(2
10
2max Amvh
Equation above says that a photoncarries an energy hv into the sur- face. Part of this energy A0 is used in causing the electron to pass through the metal surface. The excess energy (hv-A0) is given to the electron in the form of kinetic energy.
In 1916, Milikan, experimentsverified Einstein’s ideas in every detail. Einstein succeed in explainingthe photoelectric effect.
h
-
-
金属
electron
-
--A
v
The dual nature of light, particle and wave
光的波粒二象性
particle wave( energy ) ( frequency )
( momentum ) ( wavelength )E
P
h
These two natures are connected by h.
)1( hE
)2(/
h
C
hCEP
220
2 )( cPEE
3. The Compton effect ( 康普顿效应 )
Compelling confirmation of theconcept of the photon as a concen-trated bundle of energy was providedin 1923 by A.H.Compton who earned a Noble prize for this work in 1927. Compton allowed a beam of X-raysof sharply defined wavelengthλto fall on a graphite block. He measured, for various angles of scattering, the intensity of the scattered X-raysas a function of their wavelength.
1) Equipment
Compton allowed a beam of X-rays of sharply defined wavelengthλto fall on a graphite block. He measured, for various angles of scattering, theintensity of the scattered X-rays as a function of their wavelength.
0
X 光光栏
石墨
0.70Å
X 射线分析仪
1) Equipment
0
2) Experimental results :
X 光光栏
石墨
0.70Å
X 射线分析仪2
3
4
1 =00
=450
=900
=1350
0.70 0.75 (Å)
强度
The scattered X-rays have intensity peaks at two wavelengths: one of the them is the same as the incident wavelength, 0, the other, , being
larger by an amount △.
应用程序
2
3
4
1 =00
=450
=900
=1350
0.70 0.75 (Å)
强度
This so-called Compton shift △ varies with the angle at which the scattered X-rays are observed.
Compton shift △ for collisions with tightly bound electrons is immeasurably small.
3) Explain Compton Effect 对康普顿效应的解释 Compton was able to explain his experimental
results by postulation that the incoming X-ray beam was not a wave but an assembly of photons
of energy E (= hv) and that these photons expe- rienced billiard-ball-like collisions with the free
electrons in the scattering block.
h0
0n̂m0
e X
Before After
h0
0n̂e
mV
h
X
Analyze quantitatively
m0
eh0
0n̂
20Cm
m0
e
n̂Before After
Before After
Electron Photon Electron Photon
energy
momentum
2mC0h h
0 00 n̂C
h nC
hˆ
Vm
Let us assume this is an elastic scattering collision.
=+ +
= +
h0
0n̂e
mV
h
Analyze quantitatively
Before After
)1(2200 mChCmh
)2(ˆˆ00
n
C
hVmn
C
h
)4(cos2)()()( 02202 C
h
C
h
C
h
C
hmV
{
nC
hˆ
Vm 0
0 n̂C
h
From ( 1 ) )3()( 200
2 CmhmC From the low of cosine
Xm0
eh0
0n̂
m0
en̂h0
0n̂e
mV
h
Analyze quantitatively
)4(cos2)()()( 02202 C
h
C
h
C
h
C
hmV
)3()( 200
2 CmhmC
)5()cos1(2 0222
02222 hhhCVm
( 3 ) 2- ( 5 )
Before After
nC
hˆ
Vm 0
0 n̂C
hXm0
eh0
0n̂
m0
en̂h0
0n̂e
mV
h
)6()(2 02
0 hCm
)cos1(2)1( 0242
02
242 hCm
C
VCm
)3()( 200
2 CmhmC )5()cos1(2 0
2220
2222 hhhCVm( 3 ) 2- ( 5 ):
)cos1(2 0242
042
0 hCmCm
nC
hˆ
Vm 0
0 n̂C
h
)7()(2 02
0 hCm
)8()cos1()(
00
0
Cm
hC
or
or
2
2
0
1CV
mm
)9()cos1(00
Cm
hCC
)cos1(0
Cm
h0
2sin
2 2
0
Cm
h
( m )
mCm
h 12
0
1043.2
2sin0243.02 2
0
( Å )
….(10)
….(11)
nC
hˆ
Vm 0
0 n̂C
h
)8()cos1()(
00
0
Cm
hC
Compton wavelength
2sin0243.02 2
0
( Å )
)cos1(0
Cm
h0
2sin
2 2
0
Cm
h
( m )
….(10)
….(11)
Discuss ,Equation (11) predicts within experimental error the experimentally observed Compton shifts. The peak for 0 can be understood as resulting
nC
hˆ
Vm 0
0 n̂C
h
Discuss , The peak for 0 can be understood as resulting from a collision between a photon and electrons bound in an ionic core. The electron’s effective mass is much greater.
ionic core 铅球Photon乒乓球
The Compton effect for longer wavelength is hardly observed. quantum results reduces to classical results. For example, 0 = 10 cm, △/ 0 = 2.43×10-11,
the Compton effect is hardly observed.
nC
hˆ
Vm 0
0 n̂C
h
4 ) SignificanceA ) Compelling confirmation of the concept of the photon as a concentrated bundle of energywas provided. The photon hasmass, energy and momentum.B) In microscopic field, the law of conservation of momentum and the law of conservation of energy are still strictly observed. Exp. An X-ray with E = 0.60MeV are scattered from a carbon block. Its wavelength changed 20% in the collision. What kinetic energy is
imparted to the recoiling electron?
nC
hˆ
Vm 0
0 n̂C
h
例:能量为 0.60MeV 的 X 射线在碳块上散射后,波 长变化了 20%,求反冲电子动能。
Known, E0=h0=0.6MeV, =0.20,
Find, Ee=?
Solve,0
00 C
hhE
)(1048.22.12.0 12000 m
)(1007.21060.11060.0
1031063.6/ 12
196
834
00 mEhC
kinetic energy of the recoiling electron,
hhEEEe 00
eEm0
e
n̂h0
0n̂e
mV
h
)(1048.22.12.0 12000 m
kinetic energy of the recoiling electron,
hhEEEe 00
0
0
0
hCCh
Ch
012
0834
1048.2
2.01031063.6
)(1060.1 14 J
MeVEe 10.0 The kinetic energy 0.10Mev imparted to the recoiling electron.
eE
n̂h0
0n̂e
mV
h