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EE 380 Fall 2014 Lecture 12. EE 380 Linear Control Systems Lecture 12 Professor Jeffrey Schiano Department of Electrical Engineering 1

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EE 380 Fall 2014Lecture 12.

EE 380

Linear Control Systems

Lecture 12

Professor Jeffrey SchianoDepartment of Electrical Engineering

1

EE 380 Fall 2014Lecture 12.

Lecture 12 Topics

• Nonlinear System Analysis– Small-signal Analysis– Chapter 9, Sections 9.1 and 9.2

2

EE 380 Fall 2014Lecture 12.

Fundamental Definitions• A system is said to be linear if the following are true

1. The response can be represented as the sum a zero-input and zero-state response

2. The zero-input response obeys the principle of superposition with respect to the initial state

3. The zero-state response obeys the principle of superposition with respect to the input

• If a system does not satisfy all three properties, then it is nonlinear

3

EE 380 Fall 2014Lecture 12.

Example 1

• Determine if the following systems are zero-state linear

4

2

2

2

2

1

1

(1)

(2) sin(

(

)

)

( )

o

o

d y dya dtdtd y dya ydtd

u

a tt

a y t

u

EE 380 Fall 2014Lecture 12.

Example 1 Solution

5

EE 380 Fall 2014Lecture 12.

Control Design for Nonlinear Plants• Most physical systems are inherently nonlinear

• Control design techniques that account for nonlinear plant behavior are beyond the scope of EE 380

• In many applications it is possible to develop a linear model that approximates the behavior of the nonlinear system for small variations about an operating point

• Given a linear small signal-plant model, one can design a linear feedback system using methods from EE 380

6

EE 380 Fall 2014Lecture 12.

Nonlinear Plant Representation• From Lecture 4, an arbitrary time-invariant nonlinear

system can be represented by the state space model

7

,

,

x f x u

y g x u

1 1 1 1 ,, , , ( , )

,n n m n

x x u f x ux x u f x u

x x u f x u

1 1 ,, ( , )

,r r

y g x uy g x u

y g x u

EE 380 Fall 2014Lecture 12.

Example 2

• Determine a state-space representation for a pendulum with damping at the pivot point. Is the system linear?

8

M

B

EE 380 Fall 2014Lecture 12.

Example 2 Solution

9

EE 380 Fall 2014Lecture 12.

Static Equilibrium States• Consider the time-invariant nonlinear system

• Drive the system with a constant input

• The constant state vector(s) xe satisfying

are called static equilibrium states

• In many cases, the constant input uo and equilibrium state xe represent a desired operating point

10

( ) ou t u

,x f x u

10 ,n e of x u

EE 380 Fall 2014Lecture 12.

Example 3

• Determine the static equilibrium state(s) of the pendulum system considered in example 2

11

M

B

EE 380 Fall 2014Lecture 12.

Example 3 Solution

12

EE 380 Fall 2014Lecture 12.

Stability of Static Equilibrium States

13

• Once in a static equilibrium state, if left unperturbed, the system remains in that state because dx/dt = 0

• The equilibrium state xe is said to be stable if for small perturbations from xe, the system returns to the equilibrium state

• The equilibrium state xe is said to be unstable if for small perturbations from xe, the system diverges from xe

EE 380 Fall 2014Lecture 12.

Example 4

• Determine the stability of the static equilibrium state(s) found in example 3

14

M

B

EE 380 Fall 2014Lecture 12.

Example 4 Solution

15

EE 380 Fall 2014Lecture 12.

EE 380

Linear Control Systems

Lecture 12

Professor Jeffrey SchianoDepartment of Electrical Engineering

1

EE 380 Fall 2014Lecture 12.

Lecture 12 Topics

• Nonlinear System Analysis– Small-signal Analysis– Chapter 9, Sections 9.1 and 9.2

2

EE 380 Fall 2014Lecture 12.

Fundamental Definitions• A system is said to be linear if the following are true

1. The response can be represented as the sum a zero-input and zero-state response

2. The zero-input response obeys the principle of superposition with respect to the initial state

3. The zero-state response obeys the principle of superposition with respect to the input

• If a system does not satisfy all three properties, then it is nonlinear

3

EE 380 Fall 2014Lecture 12.

Example 1

• Determine if the following systems are zero-state linear

4

EE 380 Fall 2014Lecture 12.

Example 1 Solution

5

EE 380 Fall 2014Lecture 12.

Control Design for Nonlinear Plants• Most physical systems are inherently nonlinear

• Control design techniques that account for nonlinear plant behavior are beyond the scope of EE 380

• In many applications it is possible to develop a linear model that approximates the behavior of the nonlinear system for small variations about an operating point

• Given a linear small signal-plant model, one can design a linear feedback system using methods from EE 380

6

EE 380 Fall 2014Lecture 12.

Nonlinear Plant Representation• From Lecture 4, an arbitrary time-invariant nonlinear

system can be represented by the state space model

7

EE 380 Fall 2014Lecture 12.

Example 2

• Determine a state-space representation for a pendulum with damping at the pivot point. Is the system linear?

8

EE 380 Fall 2014Lecture 12.

Example 2 Solution

9

EE 380 Fall 2014Lecture 12.

Static Equilibrium States• Consider the time-invariant nonlinear system

• Drive the system with a constant input

• The constant state vector(s) xe satisfying

are called static equilibrium states

• In many cases, the constant input uo and equilibrium state xe represent a desired operating point

10

EE 380 Fall 2014Lecture 12.

Example 3

• Determine the static equilibrium state(s) of the pendulum system considered in example 2

11

EE 380 Fall 2014Lecture 12.

Example 3 Solution

12

EE 380 Fall 2014Lecture 12.

Stability of Static Equilibrium States

13

• Once in a static equilibrium state, if left unperturbed, the system remains in that state because dx/dt = 0

• The equilibrium state xe is said to be stable if for small perturbations from xe, the system returns to the equilibrium state

• The equilibrium state xe is said to be unstable if for small perturbations from xe, the system diverges from xe

EE 380 Fall 2014Lecture 12.

Example 4

• Determine the stability of the static equilibrium state(s) found in example 3

14

EE 380 Fall 2014Lecture 12.

Example 4 Solution

15