e3_4d5

2
 1 Example 5 Evaluate Solution Since the exponents of both sin  x and cos x are e ven, we use the identities and to rewrite the integrand: Use the identity to rewrite the integrand of the first integral. Use the substitution u = sin 2x with du = 2cos 2x dx in the second integral. . cos sin 4 2 dx  x  x ) cos ( sin  x  2 1  2 1 x  2 = ) cos ( cos  x  2 1  2 1 x  2 + = . )cos sin ( cos sin  cos cos cos ) cos cos )( cos (  ) cos )( cos ( ) cos ( ) cos ( cos sin dx x  2 x  2 1 8 1 dx x  2 8 1 x  2  2 1 x 8 1 dx x  2 x  2 x  2 1 8 1 dx x  2 x  2  2 1 x  2 1 8 1 dx x  2 1 x  2 1 8 1 dx x  2 1  2 1 x  2 1  2 1 dx x x  2  2 3  2  2  2  2  4  2       + = + = + + = + = + = ) cos ( cos  x  4 1  2 1 x  2  2 + = du u 1 16 1 x  4  4 1 x 16 1 x  2 16 1 8 x dx x  2  2 x  2 1  2 1 8 1 dx x  4 1  2 1 8 1 x  2  2 1 x 8 1 dx x x  2  2  4  2  sin sin  cos ) sin ( ) cos ( sin cos sin       + + = +       + = 2 C 3 u u 16 1 x  4 64 1 x  2 16 1 16 x dx x x 3  4  2 +       + = sin sin cos sin du u 1 16 1 x  4  4 1 x 16 1 x  2 16 1 8 x dx x x  2  4  2  sin sin cos sin         + + = C x  2  48 1 x  4 64 1 16 x C x  2 3 1 x  2 16 1 x  4 64 1 x  2 16 1 16 x dx x x 3 3  4  2 + + = +       + = sin sin  sin sin sin sin cos sin Substitute u = sin 2x: u = sin 2x:

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  • 11

    Example 5 Evaluate

    Solution Since the exponents of both sin x and cos x are even, we use the

    identities and to rewrite the integrand:

    Use the identity to rewrite the integrand of the first integral.

    Use the substitution u = sin 2x with du = 2cos 2x dx in the second integral.

    . cos sin 42 dxxx) cos(sin x21

    21

    x2 = ) cos(cos x2121

    x2 +=

    . )cossin( cossin

    coscos cos )cos cos)( cos(

    ) cos)( cos( ) cos() cos( cos sin

    dxx2x2181

    dxx281

    x221

    x81

    dxx2x2x2181

    dxx2x221x2181

    dxx21x2181

    dxx2121

    x2121

    dxxx

    22

    322

    22

    42

    +=

    +=++=

    +=

    +=

    ) cos(cos x4121

    x22 +=

    duu1161

    x441

    x161

    x2161

    8x

    dxx22x2121

    81

    dxx4121

    81

    x221

    x81

    dxxx

    2

    242

    sinsin

    cos)sin( ) cos(sin cos sin

    ++=

    +

    +=

    2

    C3u

    u161

    x4641

    x2161

    16x

    dxxx3

    42 +

    += sinsin cos sin

    duu1161

    x441

    x161

    x2161

    8x

    dxxx 242 sinsin cos sin ++=

    Cx2481

    x4641

    16x

    Cx231

    x2161

    x4641

    x2161

    16x

    dxxx

    3

    342

    ++=

    +

    +=sinsin

    sinsinsinsin cos sin

    Substitute u = sin 2x:

    u = sin 2x: