do now if f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

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Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1) f(3) 2) g(-2) *3) g(4) f(1)

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Page 1: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Do Now

If f(x) = 2x + 3 and g(x) = x2 – 2x, find:

1) f(3) 2) g(-2)

*3) g(4) – f(1)

Page 2: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

What is the meaning of this sign?

1. Icy Road Ahead

2. Steep Road Ahead

3. Curvy Road Ahead

4. Trucks Entering Highway Ahead

Page 3: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

What does the 7% mean?

7% is the slope of the road. It means the road drops 7 feet vertically for every 100 feet

horizontally.

7%

So, what is slope???Slope is the steepness of a line.

7 feet

100 feet

Page 4: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Slope can be expressed different ways:

A line has a positive slope if it is going uphill from left to right.

A line has a negative slope if it isgoing downhill from left to right.

12

12

xx

yy

run

riseslope

Page 5: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Finding Slope Using the Formula

1) Choose ANY TWO points on the line.

2) Label one point (x1, y1) and the other (x2, y2).

3) Substitute the coordinates into the formula:

12

12

xx

yyslope

Page 6: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

1) Find the slope of the line that passes through the points (-2, -2) and (4, 1).

(1 ( 2))

(4 ( 2))m

2 1

2 1

( )

( )

y ym

x x

(1 2)

(4 2)

When given points, it is easier to use the formula!

13

6 2

x1 , y1 x2 , y2

Page 7: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Finding Slope Using the Graph1) Choose ANY TWO points on the line.

2) Graph the points and connect them.

3) Make a right triangle around the points.

4) Count the boxes along the sides of the triangle.

5) Find the slope using:run

riseslope

* Don’t forget to figure out if the slope is +/–

Page 8: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

When given the graph, it is easier to apply “rise over run”.

2) Determine the slope of the line.

Page 9: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Start with the lower point and count how much you rise and run to get to the other

point!

Determine the slope of the line.

6

3

run

3

6= =

1

2

rise

Notice the slope is positive AND the line increases!

Page 10: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Did you notice that Example #1 and Example #2 were the same problem

written differently?

(-2, -2) and (4, 1)6

31

2slope

You can do the problems either way!Which one do you think is easiest?

Page 11: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Find the slope of the line that passes through (3, 5) and (-1, 4).

1. 4

2. -4

3. ¼

4. - ¼

Page 12: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

6

4

2

-2

-4

-6

-10 -5 5 10

Page 13: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

3) Find the slope of the line that goes through the points (-5, 3)

and (2, 1).

)5(2

31

m

52

31

mm y2 y1

x2 x1

7

2m

Page 14: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

6

4

2

-2

-4

-6

-10 -5 5 10

Page 15: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Determine the slope of the line shown.

1. -2

2. -½

3. ½

4. 2

Page 16: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

What is the slope of a horizontal line?

The line doesn’t rise!

m 0

number0

All horizontal lines have a slope of 0.

Page 17: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

What is the slope of a vertical line?

The line doesn’t run!

All vertical lines have an undefined slope.

m number

0undefined

Page 18: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Find the slope of the line passing through the two given points.

1) (-3,5) and (-3,1)

2) (-4,-1) and (1, -5)

3) (4, 6) and (1,6)

Page 19: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

6

4

2

-2

-4

-6

-10 -5 5 10

Page 20: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

The slope of a line that goes through the points (r, 6) and (4, 2) is 4. Find r.

To solve this, plug the given information into the formula

m

( y2 y

1)

(x2 x

1)

.

2 64

4 r

Page 21: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

4 4

1 4 r

To solve for r, simplify and write as a proportion.

4 4

1 4 r

2 6

44 r

Cross multiply.

1(-4) = 4(4 – r)

Page 22: Do Now If f(x) = 2x + 3 and g(x) = x 2 – 2x, find: 1)f(3)2)g(-2) *3) g(4) – f(1)

Simplify and solve the equation.1(-4) = 4(4 – r)

-4 = 16 – 4r-16 -16

-20 = -4r-4 -45 = r

The ordered pairs are (5, 6) and (4, 2)