entry task let g(x) be the indicated transformation of f(x). write the rule for g(x). 4. f(x) =...
TRANSCRIPT
![Page 1: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/1.jpg)
Entry taskLet g(x) be the indicated transformation of f(x). Write the rule for g(x).
4. f(x) = –2x + 5; vertical translation 6 units down
g(x) = –2x – 1
g(x) = 2x + 85. f(x) = x + 2; vertical stretch by a factor of 4
I can graph and transform absolute-value functions.
![Page 2: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/2.jpg)
Entry TaskEvaluate each expression for f(4) and f(-3).
1. f(x) = –|x + 1|
2. f(x) = 2|x| – 1
3. f(x) = |x + 1| + 2
–5; –2
7; 5
7; 4
I can graph and transform absolute-value functions.
2.7 Absolute Value Functions and Graphs
Success Criteria: Identify the transformation of function equations Without graphing, identify transformation from
equations Be able to quick sketch a graph from an equation
![Page 3: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/3.jpg)
Gallery Walk
![Page 4: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/4.jpg)
An absolute-value function is a function whose rule contains an absolute-value expression. The graph of the parent absolute-value function f(x) = |x| has a V shape with a minimum point or vertex at (0, 0).
The absolute-value parent function is composed of two linear pieces, one with a slope of –1 and one with a slope of 1. In Lesson 2-6, you transformed linear functions. You can also transform absolute-value functions.
![Page 5: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/5.jpg)
The general forms for translations are
Vertical:
g(x) = f(x) + k
Horizontal:
g(x) = f(x – h)
Remember!
![Page 6: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/6.jpg)
Example 1A: Translating Absolute-Value Functions
Perform the transformation on f(x) = |x|. Then graph the transformed function g(x).
5 units down
Substitute.
The graph of g(x) = |x| – 5 is the graph of f(x) = |x| after a vertical shift of 5 units down. The vertex of g(x) is (0, –5).
f(x) = |x|
g(x) = f(x) + k
g(x) = |x| – 5
f(x)
g(x)
![Page 7: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/7.jpg)
Example 1B: Translating Absolute-Value Functions
Perform the transformation on f(x) = |x|. Then graph the transformed function g(x).
1 unit left
f(x) = |x|
g(x) = f(x – h )
g(x) = |x – (–1)| = |x + 1|
f(x)
g(x)
The graph of g(x) = |x + 1| is the graph of f(x) = |x| after a horizontal shift of 1 unit left. The vertex of g(x) is (–1, 0).
![Page 8: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/8.jpg)
4 units down
f(x) = |x|
g(x) = f(x) + k
g(x) = |x| – 4
Check It Out! Example 1a
Let g(x) be the indicated transformation of f(x) = |x|. Write the rule for g(x) and graph the function.
f(x)
g(x)
The graph of g(x) = |x| – 4 is the graph of f(x) = |x| after a vertical shift of 4 units down. The vertex of g(x) is (0, –4).
![Page 9: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/9.jpg)
Perform the transformation on f(x) = |x|. Then graph the transformed function g(x).
2 units right
f(x) = |x|
g(x) = f(x – h)
g(x) = |x – 2| = |x – 2|
Check It Out! Example 1b
The graph of g(x) = |x – 2| is the graph of f(x) = |x| after a horizontal shift of 2 units right. The vertex of g(x) is (2, 0).
f(x)
g(x)
![Page 10: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/10.jpg)
Because the entire graph moves when shifted, the shift from f(x) = |x| determines the vertex of an absolute-value graph.
![Page 11: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/11.jpg)
Example 2: Translations of an Absolute-Value Function
Translate f(x) = |x| so that the vertex is at (–1, –3). Then graph.
g(x) = |x – h| + k
g(x) = |x – (–1)| + (–3)
g(x) = |x + 1| – 3
The graph of g(x) = |x + 1| – 3 is the graph of f(x) = |x| after a vertical shift down 3 units and a horizontal shift left 1 unit.
f(x)
g(x)
![Page 12: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/12.jpg)
Check It Out! Example 2
Translate f(x) = |x| so that the vertex is at (4, –2). Then graph.
g(x) = |x – h| + k
g(x) = |x – 4| + (–2)
g(x) = |x – 4| – 2
The graph of g(x) = |x – 4| – 2 is the graph of f(x) = |x| after a vertical down shift 2 units and a horizontal shift right 4 units.
g(x)
f(x)
The graph confirms that the vertex is (4, –2).
![Page 13: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/13.jpg)
Reflection across x-axis: g(x) = –f(x)
Reflection across y-axis: g(x) = f(–x)
Remember!
Absolute-value functions can also be stretched, compressed, and reflected.
Vertical stretch and compression : g(x) = af(x)
Horizontal stretch and compression: g(x) = f
Remember!
![Page 14: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/14.jpg)
Example 3A: Transforming Absolute-Value Functions
Perform the transformation. Then graph.
g(x) = f(–x)
g(x) = |(–x) – 2| + 3
Reflect the graph. f(x) =|x – 2| + 3 across the y-axis.
The vertex of the graph g(x) = |–x – 2| + 3 is (–2, 3).
g f
Take the opposite of the input value.
![Page 15: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/15.jpg)
g(x) = af(x)
g(x) = 2(|x| – 1) Multiply the entire function by 2.
Example 3B: Transforming Absolute-Value Functions
Stretch the graph. f(x) = |x| – 1 vertically by a factor of 2.
g(x) = 2|x| – 2
The graph of g(x) = 2|x| – 2 is the graph of f(x) = |x| – 1 after a vertical stretch by a factor of 2. The vertex of g is at (0, –2).
f(x) g(x)
![Page 16: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/16.jpg)
Perform the transformation. Then graph.
g(x) = f(–x)
g(x) = –|–x – 4| + 3
Take the opposite of the input value.
Reflect the graph. f(x) = –|x – 4| + 3 across the y-axis.
Check It Out! Example 3a
g(x) = –|(–x) – 4| + 3
The vertex of the graph g(x) = –|–x – 4| + 3 is (–4, 3).
fg
![Page 17: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/17.jpg)
Compress the graph of f(x) = |x| + 1 vertically
by a factor of .
Check It Out! Example 3b
g(x) = a(|x| + 1)
g(x) = (|x| + 1)
g(x) = (|x| + )
The graph of g(x) = |x| + is the graph of
g(x) = |x| + 1 after a vertical compression by a
factor of . The vertex of g is at ( 0, ).
f(x)
g(x)
![Page 18: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/18.jpg)
Assignment #17
Pg 111 #18-27
On Your Yellow Sheet FILL IN:
D: What did you DO today?
L: What did you LEARN?
I: What was INTERESTING?
Q: What QUESTIONS do you have?
![Page 19: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/19.jpg)
Lesson Quiz: Part I
1. Translate f(x) = |x| 3 units right.Perform each transformation. Then graph.
g(x)=|x – 3|g
f
![Page 20: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/20.jpg)
Lesson Quiz: Part II
Perform each transformation. Then graph.
g(x)=|x – 2| – 1
2. Translate f(x) = |x| so the vertex is at (2, –1). Then graph.
f
g
![Page 21: Entry task Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = – 2x](https://reader035.vdocuments.site/reader035/viewer/2022081504/56649e245503460f94b11eaf/html5/thumbnails/21.jpg)
Lesson Quiz: Part III
g(x)= –3|2x| + 3
3. Stretch the graph of f(x) = |2x| – 1 vertically by a factor of 3 and reflect it across the x-axis.
Perform each transformation. Then graph.