data portal frame 2d

8/17/2019 Data Portal Frame 2d

1/26

PORTAL FRAME 2D

DATA

Geometri Struktur

Lebar bentang h = 3 m

Tinggi bangunan 5h = 15 m

a!ok " = #$##1 m%

#$2 m

#$% m

&o!om

#$%5m

rho = "b = #$##1#'''''( = #$#()#3'))%'

%"* #$#13'')(5

bb =

hb =

b* =


2/26

= #$5 " ba!ok


3/26

PORTAL FRAME 2D

DATA

Geometri Struktur

Lebar bentang h = 3 m

Tinggi bangunan 5h = 15 m

a!ok " = #$##1 m% =

#$2 m

#$% m

&o!om

+ m

Soa! , ==-

Subt$

=

#$##1#'( = #$#%1''''''(

= #$##1#'''''(

#$#%1''''''(

= #$% m

atau

= #$2 . #$% /3

#$5

= #$#25'

atau

bb =

hb =

b* =

"b = #$5. "

*"

ba!ok= #$5 . "

ko!om

"b = 1012 . b

b. h

b3

"* = 1012 . b

. b

3 = 1012 . b

*%

1012 . bb . hb3 #$5 . 1012 . b*%

b*%

b*%

b*

b*%

b*%


4/26

2 . #$2 .

= #$#25'

= #$% m

b*%

b*%

b*


5/26

#$5 " ba!ok


6/26

#$% /3


7/26

eni4 materia! E = 2%)555() k60m2

erat 7eni4 = 2% k60m3

Porta! Frame 1

E!emen b h rho T

8m9 8m9 8m29 8m%9 "b0%"* Se*a!ok #$2 #$% #$#) #$##1#'(

#$#()#3( #$%%3%))&o!om #$%5 #$%5 #$2#25 #$##3%1(

Porta! Frame 2

E!emen b h rho T

8m9 8m9 8m29 8m%9 "b0%"* Se*

a!ok #$2 #$% #$#) #$##1#'(#$125 #$%%315:

&o!om #$% #$% #$1' #$##2133

#$5

Reka;

Framea!ok &o!om

b h

i 8m9 8m9 8m29 8m%9 8m9 8m29

1 #$2 #$% #$#) #$##1#'( #$%5 #$2#25

2 #$2 #$% #$#) #$##1#'( #$% #$1'

T1


8/26

? = 2π$@

?1 = 2π$10T1?2 = 2π$10T2


9/26

rho T

"b0%"*

8m%9 84e*9

#$##3%1(1)) #$#()#3( #$%%3%))

#$##2133333 #$125 #$%%315:

"*

0.07 0.08 0.09 0.1 0.11 0.12 0.13

0

2

4

6

8

10

12

14

16

18

20

Colum


10/26

2311

13%321#

1$2'%#E#) b2%a*

2a

%'3$12%)

11' 11)$#::)(5(

1%3)


11/26

n F


12/26


13/26

TABLE: Modal Periods And Frequencies

utputCas StepType StepNum Period requenc CircFreq igenalue

Te.t Te.t Bnit!e44 Se* C*04e* ra04e* ra204e*2

MODAL Moe 1 #$%%3%)) 2$25%: 1%$1') 2##$(2

MODAL Moe 2 #$125(:) ($:%:2 %:$:%( 2%:%$(

MODAL Moe 3 #$#'#(#: 1'$%(2 1#3$5 1#(11

MODAL Moe % #$#3'%3 2($%5 1(2$%( 2:(%(MODAL Moe 5 #$#2'%(2 3($((' 23($35 5'33(

MODAL Moe ' #$#22(51 %3$:55 2('$1( ('2(3

MODAL Moe ( #$#2252: %%$3)( 2()$): ((((:

MODAL Moe ) #$#1#::: :#$:1) 5(1$2' 32'33#

MODAL Moe : #$#1#: :1$(%% 5('$%% 3322:#

MODAL Moe 1# #$#1#'12 :%$232 5:2$#) 35#55#

MODAL Moe 11 #$#1#1:' :)$#)1 '1'$2' 3(:()#

MODAL Moe 12 #$##)((3 113$:: (1'$2 512:%#


14/26

TABLE: Modal Periods And Frequencies

utputCas StepType StepNum Period requenc CircFreq igenalue

Te.t Te.t Bnit!e44 Se* C*04e* ra04e* ra204e*2

MODAL Moe 1 #$%%315: 2$25'5 1%$1() 2#1$#2

MODAL Moe 2 #$13#'35 ($'5%: %)$#:( 2313$3

MODAL Moe 3 #$#''13 15$122 :5$#13 :#2($5

MODAL Moe % #$#%1#:5 2%$33% 152$: 233((MODAL Moe 5 #$#3#%:3 32$(:% 2#'$#5 %2%5(

MODAL Moe ' #$#23(#' %2$1)% 2'5$#5 (#252

MODAL Moe ( #$#23%3 %2$') 2')$1' (1:12

MODAL Moe ) #$#1#1%1 :)$'#' '1:$5' 3)3)'#

MODAL Moe : #$#1##) ::$2#2 '23$3 3))51#

MODAL Moe 1# #$##::#( 1##$:% '3%$2% %#225#

MODAL Moe 11 #$##:'52 1#3$'1 '5#$:: %23(:#

MODAL Moe 12 #$##)25( 121$11 ('#$:( 5(:#(#


15/26

-11046923.6 # # #

-11046923.56 -1E+007 0 0

# -11046923.6 >>> #

# # >>> -11046924

# # # -1E+007

11046924 - ωn

2.191.743

22093847.1 - 266.055ωn

2

22093847.1 - 266.055ωn

2

22093847.1 - 266.055ωn

2

22093847.1 - 266.055ωn

2


16/26

KONVERSI SATUAN

1 kgf = 10 N

1 Pa = 1 N/m²

1 MPa = ### Pa

1 m² = ### mm²

1 m² = 10,000 cm²

1MPa = 1 N/mm²

1 MPa = 1,000 kN/m²

1 MPa = 10 kg/cm² 1 kg/cm²= 10,000

1 MPa = 100,000 kg/m²

1kNm = 100 kgm

1 kN = 100 kg

1 kNm = 10,000 kgcm

MPa x mm² = N

1 kN = 100 kg

m2 m2

BJ Beton = 23.5631 kN = 2402.77 kgf

m3 m3

E = 24855578 kN = 2.54E+09 kgf

m2 m2

2.5E+009


17/26

5 m 5000 mm

5 m 500 cm

5 kg 5000 g

kg/m² 5 kg E!502 N

KG-M KN-M

244.8012 2.4007

2402.6159 23.5616

9.8145593241 9.8144707794

0.1018894448 0.1018903640

101.889444751 101.890363982

288 2400

576


18/26

24.5166

250

10.197172528

101.9707585288

101.9716784938

1.971678493820450000000

1.970758528762450000000


19/26

"ece#$t$n g$%&t$'& (um&) g = 9.81 m*t2 "em(ul$t$n men,$& =

fc- = 20 #$

kon%e'& ke /

/ = fc-*0.83 g

/ = 240.9639 == #em(ul$t$n men,$& 250 kg*cm2

,$& fc - = 20 #$ = /250


20/26

10 m*t2


21/26

Diketahui 4truktur ;orta! bertingkat 3 8tiga9 engan ;embebanan berat ;er !antai an k

1600 -1600 0 3 0

& = -1600 3600 -2000 M = 0 4.5

0 -2000 4400 0 0

1600 -1600 0 3 0 0

-1600 3600 -2000 0 4.5 0

0 -2000 4400 0 0 4.5

1'## 3 1'## #

1'## # 3'## %$5

# # 2### #

1'## 3 1'## #

et 1'## # 3'## %$5

# # 2### #

ωn

2

ωn

2 ωn2

ωn

2 ωn2

ωn

2 ωn2

ωn2 ωn2

ωn

2 ωn2

ωn

2 ωn2

81'## 3ωn29 H 83'## %$5 ω

n29 8 %%## %$5ω

n29 I 81'##9 H81'##9 8%%## %$

ωn

' 2311ωn% 13%321# ω

n2 1$2'% 81#)9 = #

Mi4a!kan β = ωn2 maka akan i;ero!eh ;er4amaan

β3 2311β2 13%321# β 1$2'% 81#)9 = #

1

2

3

m1

m2

m3


22/26

Dia;at ,

11' 10.77033

: 1 : 1 : 1

' #$()25 ' #$%1: ' 1$':'

3 #$%#3' 3 #$:)%% 3 1$'3%#

# # # # # #

β = ω1

2 = ra20et2 → ω1 = √β =

0

1

2

3

4

5

6

78

9

10

Mo! 1

oe

1

2 1 0 1 2

0

1

2

3

4

5

6

78

9

10

Mo! "

oe 2


23/26

ekakuan 4;erti tergambar

0

0

4.5

= #

# #

2### # = #

%%## %$5

# # 1'## 3

2### # 1'## #

%%## %$5 # #

ωn

2

ωn

2

ωn

2

ωn2 ωn2

ωn

2 ωn

2

ωn

2 ωn

2

5ωn29I 81'## 3ω

n29 H82###982###9I = #


24/26

ra0et

2 1.5 1 0.5 0 0.5 1 1.5 2

0

2

4

6

8

10

Mo!

oe 3


25/26

1'## #

3'## %$5

2### #

ωn2

ωn2

ωn2


26/26

data portal frame 2d

Documents