cuhkredceng4480 lecture 02: operational amplifier 1byu/ceng4480/2020fall/slides/l02-opamp.pdf ·...
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![Page 1: CUHKredCENG4480 Lecture 02: Operational Amplifier 1byu/CENG4480/2020Fall/slides/L02-opamp.pdf · CENG4480 Lecture02:OperationalAmplifier–1 Bei Yu byu@cse.cuhk.edu.hk (Latestupdate:August19,2020)](https://reader035.vdocuments.site/reader035/viewer/2022071210/6020dbe1d56404195f044d13/html5/thumbnails/1.jpg)
CENG4480Lecture 02: Operational Amplifier – 1
Bei Yu
[email protected](Latest update: August 19, 2020)
Fall 2020
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Overview
Introduction
Op-Amp Preliminaries
Op-Amp List
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Overview
Introduction
Op-Amp Preliminaries
Op-Amp List
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Computer interfacing Introduction
To Learn:I how to connect the computer to various physical devices.I Overall interfacing schemesI Analog interface circuits, active filters
Some diagrams are taken from references:I [1] S.E. Derenzo, “Interfacing– A laboratory approach using the microcomputer for instrumentation, data
analysis and control”, Prentice Hall, 1990.I [2] Giorgio Rizzoni, “Principles and Applications of Electrical Engineering”, McGraw-Hill, 2005.
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Amplifier in Audio System
Converting low-voltage sensor signal to a level suitable for driving speaksers.
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Typical Data Acquisition and Control System
Sensor filter A/D
Computer
D/APowercircuit
Mechanicaldevice
Timer
Sample&
Hold
Digital controlcircuit
Op-amp
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Analog Interface Example 1
Audio recording systemsI Audio recording systemsI Audio signal is 20–20KHzI Sampling at 40KHz, 16-bit is Hi-FiI Stereo ADC requires to sample at 80KHz.I Calculate storage requirement for one hour?I Audio recording standards: Audio CD; Mini-disk MD; MP3
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Analog Interface Example 2
Analog hand held controller
(a) PS5 (b) Wii (c) Driving wheel
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Operational Amplifier (Op-Amp)
I Why use op amp?
I What kinds of inputs/outputs do you want?
I What frequency responses do you want?
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Direct Current (DC) amplifier
I Example: use power op amp (or transistor) to control the DC motor operation.I Need to maintain the output voltage at a certain level for a long time.I All DC (biased) levels must be designed accurately .I Circuit design is more difficult.
Op-
amp
DC
Source
Load:
DC motor
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Biasing
Biasing in electronics
The method of establishing predetermined voltages or currents at various points of anelectronic circuit for the purpose of establishing proper operating conditions in electroniccomponents
https://en.wikipedia.org/wiki/Biasing
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Alternating Current (AC) amplifier
I Example: Microphone amplifier, signal is AC and is changing at a certain frequencyrange.
I Current is alternating not stable.I Use capacitors to connect different stagesI So no need to consider biasing problems.
Op-
amp
AC
Source
Load
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Overview
Introduction
Op-Amp Preliminaries
Op-Amp List
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Amplifier
A circuit where the output signal power is greater than the input signal power.
Otherwise is referred as an attenuator.
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Black-Box to Consider Circuit Effect
I Without examining actual operation (thousands of elements)I Zin: input impedance (a.k.a. Rin)
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Voltage gain A
A =Vout
Vin
I Usually voltage gain may be either very large or very smallI Invonvenient to express as a simple ratioI Therefore, decibel (dB):
Voltage gain in dB
A = 20 · log10Vout
Vin
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Question: Voltage Gain
Vin = 20mV, Vout = 500mV. Calculate the voltage gain in dB.
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Operational amplifier circuit diagram
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Simplified circuit symbol
V0=A(V+-V-)V-
V+ +
_2
3
6LM741
I Ideal difference amplifierI (+): noninverting inputI (-): inverting inputI A: open-loop voltage gain (order of 105 to 107)
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Rin & Rout
V0=A(V+-V-)V-
V+ +
_2
3
6LM741
I Rin: input impedance (High)I Rout: output impedance (Low)
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Why prefer High Rin, Low Rout?
Stage1(sensor)Vout1Rout1
Stage 2Rin2Vin2
Is equivelent to:
Rout1Vout1Rin2
Vin2
To maximize Vin2
Vin2 = Vout1 ·Rin2
Rout1 + Rin2
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Why prefer High Rin, Low Rout?
Stage1(sensor)Vout1Rout1
Stage 2Rin2Vin2
Is equivelent to:
Rout1Vout1Rin2
Vin2
To maximize Vin2
Vin2 = Vout1 ·Rin2
Rout1 + Rin2
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Open-loop & Closed-loop
I Open-loop gainI Closed-loop gain
Feedback connectionThe effect of the feedback connection from output to inverting input is to force the voltage atthe inverting input to be equal to that at the noninverting input.
“Note that closing the feedback loop turns a generally useless amplifier (the gain is toohigh!) into a very useful one (the gain is just right)!”
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Ideal Op-Amp Rules
Rule 1No current flows in or out of the inputs
Rule 2The Op-Amp tries to keep the inputs the same voltage
* Rule 2 is only for negtive feedback op-amp
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Ideal Op-Amp v.s. Real Op-Amp
Open-Loop Gain A
Ideal: Infinite, thus V+ = V−Real: Typical range (20,000, 200,000), thus Vout = A(V+ − V−)
Input Impedance
Ideal: Infinite. Since Zin =Vin
Iin, zero input current
Real: No such rule.
BandwidthIdeal: Infinite BandwidthReal: Gain-Bandwidth product (GB).
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Gain-Bandwidth Product
I Fixed gain-bandwidth product for any given amplifierI Define bandwidth as the frequency range over which the voltage gain of the amplifier is
above 70.7% or -3dB of its maximum output value
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Slew Rate Limit
Slew Rate
Slew rate = |dv(t)
dt|
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Overview
Introduction
Op-Amp Preliminaries
Op-Amp List
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Voltage follower
_V0
V1 +A
I Unit voltage gainI Output V0 = V1
I high current gain, high input impedance
In real op-amp
V0 = A(V1 − V0)⇒ V0 =V1A
1 + A≈ V1
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Non-inverting Amplifier
_V0
V1
R1R2
+
V2
AInput Output
I Rin: High input impedance
In real op-amp
V0 = A(V1 − V2) andV2
V0=
R1
R1 + R2
⇒V0
V1=
R1 + R2
R1 + (R1 + R2)/A≈
R1 + R2
R1
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Question: Non-inverting Amplifier Gain
_V0
V1
R1R2
+
V2
AInput Output
CalculateV0
V1=
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Current to Voltage Converter
_V0
IR
+A
V0 = -I · R
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Inverting Amplifier
+
_R2
R1V0
V1
Virtual-ground,V2
AInput
Output
Because of Kirchhoff’s circuit laws, i1 + i2 = i− = 0
In real op-amp
V0 = A(0− V2) andV2 − V1
R1=
V0 − V2
R2
⇒ R1(V0 +V0
A) = −R2(
V0
A+ V1)⇒
V0
V1≈ −
R2
R1
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Inverting Amplifier
+
_R2
R1V0
V1
Virtual-ground,V2
AInput
Output
I Rin = R1
I Gain (G) = −R2
R1
Question: How to increase input impedance?
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Inverting Amplifier
+
_R2
R1V0
V1
Virtual-ground,V2
AInput
Output
I Rin = R1
I Gain (G) = −R2
R1
Question: How to increase input impedance?
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Summing Amplifier
_V0
R
+
R1
R2
R3I1+I2+I3
V1
V2
V3Inputs
Output
V0 = −R · {V1R1
+V2R2
+V3R3}
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Differential Amplifier
_V0
R2
+
R1V1
R1V2
R2
AInputOutput
I Calculate the difference between V1 and V2
I Can control gain
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Question: Differential Amplifier Gain
_V0
R2
+
R1V1
R1V2
R2
AInputOutput
Calculate V0 =
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Question: Differential Amplifier Gain
_V0
R2
+
R1V1
R1V2
R2
AInputOutput
Calculate V0 =
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Instrumental Amplifier
I To make a better DC amplifier from op-ampsI combine 2 noninverting amplifier & 1 differential amplifier
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Instrumental Amplifier (cont.)
Solution 1:
v1’
v2’
I For each non-inverting amplifier: A = 1 +2R2
R1I Connecting to differential amplifier:
Vout =RF
R(v′2 − v′1)
=RF
R(1 +
2R2R1
)(v2 − v1)
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Instrumental Amplifier (cont.)
Solution 2:
v1’
v2’
I By rule 2, two input voltages are the same, thus
v2 − v1R
=v′2 − v′12R1 + R
I Therefore: v′2 − v′1 = (1 +2R1
R)(v2 − v1)
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Comparing Amplifiers
Op Amp Inv. Amp Noninv. Amp Diff. Amp Instr. AmpHigh Rin X X X X XDiff Input X X X X X
Define Gain X X X X X
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