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  • 7/31/2019 CT Lecture 2

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    Complex Numbers and Phasors

    Chapter Objectives:

    Understand the concepts of sinusoids and phasors. Apply phasors to circuit elements.

    Introduce the concepts of impedance and admittance.

    Learn about impedance combinations. Apply what is learnt to phase-shifters and AC

    bridges.

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    Complex Numbers

    A complex number may be written in RECTANGULAR FORM as:

    RECTANGULAR FORM

    z = x+ jy

    j= -1, x=Re z , y=Im(z)

    x is the REAL part.

    y is the IMAGINARY part.

    ris the MAGNITUDE.

    is the ANGLE.

    A second way of representing the complex number is by specifying the

    MAGNITUDE and rand the ANGLE in POLAR form.

    z = x+ jy= zPOLAR FORM

    =r

    The third way of representing the complex number is the EXPONENTIAL form.

    z = x+

    EXPONENT

    jy= z

    IAL FORM

    = jre

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    Complex Numbers

    A complex number may be written in RECTANGULAR FORM as: forms.

    2 2 -1

    j

    2 2 -1

    j

    j

    z = x+ jy j= -1

    cos y sin

    z=

    =tan

    z= e

    RECTANGULAR FORM

    POLAR FORM

    EXPO

    =tan

    z = x + jy=

    NE

    = e

    e =cos +j

    NTIAL FORM

    x r r

    r

    yr x y

    x

    r

    yr x y

    x

    r r

    j

    j

    sin

    cos Re

    Euler's Identity

    Real part

    Imaginary p

    e

    sin Im e art

  • 7/31/2019 CT Lecture 2

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    Complex Number Conversions

    We need to convert COMPLEX numbers from one form to the other form.

    z = (cos sin )jx jy r re r j

    2 2 1 Rectangular to Polar

    Polar to Rectangu

    z = (cos sin )

    , tan

    cos , sin lar

    jx jy r re r j

    yr x y

    x

    x r y r

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    Mathematical Operations of Complex Numbers

    Mathematical operations on complex numbers may require conversions from one

    form to other form.

    1 2 1 2 1 2

    1 2 1 2 1 2

    1 2 1 2 1 2

    1 11 2

    2 2

    z + z =(x + x )+j(y + y )

    z - z =(x -x )+j(y - y )

    z z = r r +

    ADDITION:

    SUBTRACTION:

    MULTIPLICATION:

    DIVISION:

    RECIPROCAL:

    SQUARE ROOT:

    z r= -

    z r

    1 1

    = -z r

    z=

    COMPLEX CO

    r2

    NJUGATE: z

    rj

    x jy re

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  • 7/31/2019 CT Lecture 2

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    Phasors

    (Time Domain Re pr.) (Phasor Domain Re presentation)

    ( ) Re{ } (Converting Phasor back to time)

    ( ) cos( )m m

    j t

    v t V t V

    v t e

    V

    V

    A phasor is a complex number that represents the amplitude and phase of a sinusoid.

    Phasor is the mathematical equivalent of a sinusoid with time variable dropped.

    Phasor representation is based on Eulers identity.

    Given a sinusoidv(t)=Vmcos(t+).

    j

    j

    j

    e =cos jsin

    co

    Euler's Identity

    Real part

    Imaginary pa

    s Re e

    s rtin Im e

    ( )( ) cos( ) Re( ) Re( ) Re( )

    PHA S .OR REP

    j t j t j t

    m m

    j

    m m

    j

    mv t V t V e e

    V

    e e

    V

    V

    e

    V

    V

  • 7/31/2019 CT Lecture 2

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    Phasors

    Given the sinusoids i(t)=Imcos(t+I) and v(t)=Vmcos(t+ V) we can obtain the

    phasor forms as:

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    Phasors Amplitude and phase difference are two principal

    concerns in the study of voltage and current sinusoids.

    Phasor will be defined from the cosine function in all ourproceeding study. If a voltage or current expression is inthe form of a sine, it will be changed to a cosine bysubtracting from the phase.

    Example

    Transform the following sinusoids to phasors:

    i = 6cos(50t40o) A

    v =4sin(30t + 50o) V

    Solution:

    a. I A

    b. Since sin(A) = cos(A+90o);

    v(t) = 4cos (30t+50o+90o) = 4cos(30t+140o) V

    Transform to phasor => V V

    406

    1404

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  • 7/31/2019 CT Lecture 2

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    Phasor as Rotating Vectors

    ( )

    ( ) cos( )

    ( ) Re

    ( ) Re ( )

    Rotating Phasor

    m

    j t

    m

    m

    v t V t

    v t V e

    v t V j t

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    Phasor Diagrams

    The SINOR

    Rotates on a circle of radius Vm at an angular velocity of in the counterclockwise

    direction

    j te

    V

    Ph D

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    Phasor Diagrams

    cos( )

    sin(

    Time

    ) 90

    cos

    Domain Representation Phasor Domain Re

    ( )

    sin( ) 0

    p.

    9

    m m

    m m

    m m

    m m

    V t V

    V t V

    I t I

    I t I

    Ph

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    Time Domain Versus Phasor Domain

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    Differentiation and Integration in Phasor Domain

    (Time Domain) (Phasor Domain)

    ( ) cos( )

    ( ) sin( ) 90

    V

    m m

    m m

    v t V t V

    v t V t V

    dvJ

    dt

    vdtJ

    V

    V

    V

    Differentiating a sinusoid is equivalent to multiplying its corresponding phasor by j.

    ( ) cos( ) Re

    ( )sin( ) cos( 90 )

    = Re

    j t

    m

    m m

    j t

    v t V t e

    dv t

    d

    V t V t dt

    ev

    j Jdt

    V V

    V

    Integrating a sinusoid is equivalent to dividing its corresponding phasor by j.

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    20cos(5 30 ) At 15

    2 F1

    H10

    S l i AC Ci it

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    We can derive the differential equations for the followingcircuit in order to solve for vo(t) in phase domain Vo.

    20

    02

    5 40020 sin(4 15 )

    3 3

    ood v dv v tdt dt

    However, the derivation may sometimes be very tedious.

    Is there any quicker and more systematic methods to do it?

    Instead of first deriving the differential equation and then

    transforming it into phasor to solve for Vo, we can transform all the

    RLC componentsinto phasor first, then apply the KCL laws and other

    theorems to set up a phasor equation involving Vo directly.

    Solving AC Circuits