clarifier_tank_skert2

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DESIGN CALIFIER TANK

(SLUDGE BLANKET CLARIFIER TYPE : VERTICAL SLUDGE BLANKET)

1. Flow Rate

Q = 150 m3/hr

2. Raw Water Quality input

1 Turbidity = NTU

2 pH =

3 Alkalinity = mg/l as CaCO3

4 Temperature =oC

5 Fe mg/l

6 Mn mg/l

7 Total Hardness mg/l as CaCO3

8:16 AM/2/28/2007 1/1 Design Clarifier Tank(Skert)/Design Flow


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3. Design Criteria

3.1. Kawamura

3.1.1 Flocculation Time = approximate = 20 min

3.1.2 Settling Time = 1 - 2 hr

3.1.3 Surface Loading = 2 - 3 m/hr

3.1.4 Weir Loading = 7.3 - 15 m3/hr

3.1.5 Upflow Velocity = < 10 mm/min

3.1.6 Slurry Circulation rate = up to 3 - 5 time the raw water inflow rate

3.1.7 G = 30 - 50 s-1

3.1.8 MAXIMUM MIXER TIP SPEE0.9 m/s (Baffled Channel)

= 0.9 m/s (Horizontal Shaft with Paddles)

= 1.8 - 2.7 m/s (Vertical Shaft with Paddles)

Equation

3.1.9 Free Board is approxi = 0.6 m

3.1.10 Water Depth = 4 - 5 m.

3.1.11 Length and Width ratio = 6 : 1 (minimum 4 : 1) (Rectangular Basin)

3.1.12 Width and Water Dept = 3 : 1 (maximum 6 : 1) (Rectangular Basin)

3.1.13 Blade area/Rapid Mixing Tank area = 0.1 - 0.2 % (page 121)

3.1.14 Blade : Diameter Blade/Diameter Mixing Tank = 0.2 - 0.4 (page 121)

3.1.15 Shaft rpm = 8 - 12

3.2. Q,Sim

3.2.1 Detention Time = 2 Hr

3.2.2 Surface Loading = 2 - 4 m/hr

3.2.3 Weir Loading = 7.1 m3/m.hr

3.3. Sheet Master Degree of Environmental Engineering

3.3.1 Weir Loading = 7.1 m3/m.hr

3.3.2 Surface Koading

- Q < 0.35 m3/min = 0.5 - 1.0 m/hr

DNspeedtipmixer =

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- Q > 0.35 m3/min = 1.25 - 1.85 m/hr

3.3.3 Water Depth = 3 - 5 m.

3.3.4 Paddle radius = 65 - 75% of radius for Flocculator

3.3.5 Detention Time = 1 - 3 Hr

3.3.6 Diameter Tank < 45 m

3.3.7 Paddle at bottom tank high bottom = 15 - 30 cm

3.3.8 Paddle Velocity = 2 - 3 rpm

3.3.9 Effective Paddle Area = 10 % Sweep area of the fllocculator

3.4. Water Work Engineering Book

3.4.1 Flocculation

2.4.1.1 Detention Time = 20 - 60 min

2.4.1.2 Velocity Gradie = 15 - 60 S-1

2.4.1.3 GT = 1x104

- 15x104

2.4.1.4 Periperal Velocity of Paddle = 0.3 - 0.6 m/s

2.4.1.5 Shaft rotation speed = 1.5 - 5 rpm

3.4.2 Sedimetation (Coagulation)

2.4.2.1 Detention Time = 2 - 8 hr

2.4.2.2 Surface Loadin = 20 - 40 m3/m

2.day

2.4.2.3 Weir Loading = 200 - 300 m3/m.day

3.4.3 Sedimentation (Softening)

2.4.3.1 Detention Time = 1 - 6 Hr

2.4.3.2 Surface Loadin = 40 - 60 m3

/m2

.day

2.4.3.3 Weir Loading = 250 - 350 m3/m.day

3.5 Clarifier Design (Water Poluttion Control Federation 1985)

3.5.1 Detention Time Flocculator central well = 20 - 30 min

3.5.2 Weir Loading (outlet) = 100 to 150 m3/m

2.day

3.5.3 Radial inner feed well = 10 to 13% of the tank radius

3.5.4 velocity gradient = 30 - 50 S-1

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4 GiveContact Time in Hopper inside (Flocculation Zone) = 30 min

5 Flow Rate = 150 m3/hr

6 Volume in Hopper inside =

= 75 m3

7 Give Detention Time in Hopper outside (Sedimentation Zon = 2 Hr

8 Volume in Hopper outside =

= 300 m3

9 Calculation Diameter Hopper inside

Give D1 = 3 m

Surface Area = m2

= 7.06858 m2

10 Theory Volume of Conical Basin =

Give Water Depth = 5 m

Volume Hopper inside = 75 m3

Then 45 = 7.06858 + A2 + 2.658681

0 = -37.9314 + A2 + 2.658681

= 4.97134

= 24.7142 m2

Theory Surface Area =

= 31.4671

= 5.60956 6 m.

Then = 3 m.

= 6 m.

= 5 m.Water Depth

txQ

txQ

4

2

D

( )2121

3AxAAA

d++

2A

( ) 21

2A

2A

2A

1A

4

2

D

2

2D

2D

1D

2D

8:17 AM/2/28/2007 1/3 Design Clarifier Tank(Skert)/Hopper inside&outside


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Free Board from Design Criteria = 0.6 m (Kawamura)

Solid Contact Clarifier Tank Height = 5.6 m



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158.7942

ZONE2

Depth ZONE 2

Depth ZONE 3

Depth ZONE 4

D

D

D

A1

A2

A3



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11 Actual Volume in Hopper inside

Theory Volume of Conical Basin =

= = 7.068583 m2

= = 28.27433 m2

Calculate Acture Volume in Hopper inside

Volume in Hopper inside =

= 82.46681 m3

12 Acture Contact Time = 82.46681 = 0.549779 Hr.

150

= 32.98672 min.

13 Calculate Diameter in Hopper Outside (Sedimentation Zone)

Volume in Hopper Outside (Sedimentation Zone) = 300 m3

= = 28.27433 m2

Calculate A3

Theory Volume of Conical Basin =

229.4801 = 28.27433 + A3 + 5.317362

0 = -201.206 + A3 + 5.317362

= 11.77303 m2

= 138.6043 m2

( )2121

3AxAAA

d++

1A

2A

4

2

D

4

2D

( )21213 AxAAAd

++

Q

Vt =

2A

4

2D

( )3232

3AxAAA

d++

3A

21

3 )( A

3A

3A

8:17 AM/2/28/2007 1/2 Design Clarifier Tank(Skert)/Acture Volume&Contact time


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= 138.6043 m3

= 13.28177 m

Acture Volume in Hopper outside

= = 28.27433 m2

= = 138.5485 m2

14 Calculate Acture Volume in Hopper outside + Outside =

Volume in Hopper outside + Outside = 382.3529 m3

Conclusion

- Volume in Hopper inside = 82.46681 m3

- Volume in Hopper outside = 299.8861 m3

4

2

3D

3D

( )32323 AxAAAd ++

2A

3A

4

2

3D

4

2

2D

8:17 AM/2/28/2007 2/2 Design Clarifier Tank(Skert)/Acture Volume&Contact time


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15 Detention Time in Hopper outside

= 1.999 Hr.

16 Calculate Paddle

16.1 At Depth level = 1.5 m.

Slope = 3.333 m.

Then 3.333333 = 1.5 X1

X1 = 0.45 m.

Diameter Paddle = 3.9 m.

Sweep Area = = 11.94591 m2

Paddle Area = 10 % of Sweep area(Bhole,A.G, Personal Communication)

= 1.195 m2

Assume There are paddle. 4 paddles

Length of each paddle = 65 - 75 % of Radius of Flocculation selection 70 %

- At depth level 1.5 m. Diameter of Flocculator = 3.9 m.

Radius = 1.95 m.

Length of each paddle = m.

Height of each paddle = 4 = 0.218789 m.

1.365

Q

Vt =

t

4

2D

xLength

Area

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Slope = 3.333 m.

Then 3.333333 = 3.5 X2

X2 = 1.05 m.


Sweep Area = = 20.42821 m2


= 2.043 m2




Radius = 2.55 m.




Slope = 3.333 m.

Then 3.333333 = 4.7 X3

X3 = 1.41 m.

1.785

4

2D

xLength

Area



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Sweep Area = = 26.60332 m2


= 2.66 m2




Radius = 2.91 m.



2.037

4

2D

xLength

Area



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SlopeDept

X1

X2

X3

X1

X2

X3



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17 Power Requirement

Give Shaft rotation speed = 3 rpm (Design criteria = 2 - 3 rpm.)

17.1 At depth level = 1.5 m.

Radius of Paddl = 1.365 m.

The rotation speed of paddle =

= 0.428827 m/s

Design Criteria < 0.9 m/s (Horizontal Shaft with Paddles)




= 0.560774 m/s





= 0.639942 m/s


18 Calculation Relative of Paddle with respect to water

m/s

18.1 At depth level = 1.5 m. = 0.428827 m/s

= 0.321621 m/s


= 0.420581 m/s


= 0.479957 m/s

rN2

rN2

rN2

paddleVV 75.0=

paddleV

V

paddleV

V

paddleV

V

8:18 AM/2/28/2007 1/1 Design Clarifier Tank(Skert)/Calculation Velocity Paddle


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19 Calculation Power requirement

Theory

Where :

P = Power requirement of Mixing (watt) or N.m/s

CD = Coefficient of drang of Paddle = 1.8

Ap = Area of Paddle (m2)

= mass fluid density (kg/m3) = 1,000 kg/m

3

= Relative velocity of Paddle with respect to water (m/s)

Then

= 437.27 watt or N.m/s

Efficiency Motor at 60 % = 728.78 watt or N.m/s

(From 1 HP = 0.7457 Kilowatt)

Then = 0.97730575 HP 1 HP

3)(

2

1vACP pD =

v

P

P

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20 Calculation Velocity Gradient (G)

Theory

Where :

G = mean velocity gradient (sec-1

)

P = power requirement for mixing (watt) or N.m/s

= dynamic viscosity (N.s/m2) 0.001 N.s/m

2

V = volume of the tank (m3)

sec-1

0.001 x 82.46680716

94.00646 sec-1

21 Outlet Clarifier Tank

Weir Loading = 7.3 - 15 m3

/m.hr

From Diameter D3 = 13.28177137 m.

Minus outlet hole 2 side = 1 m.

= 12.28177137 m.

Theory

= 12.21322198 m3/m.hr OK.

Give Diameter of Orifice = 1 in. = 0.0254 m.

Give 1 m. of outlet weir have orifice 25 pores/side

2 side = 50 pores

= 1.27 m./ 1 m. weir

1 side = 0.635 m./ 1 m. weir

728.7769012

V

PG

=

=G

)./(

)/(3

3

hrmmLoadingWeir

hrmQweirofLength =

weirofLength

LoadingWeir

OrificeofLength

=G

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Then Free Space of weir = 0.365 m./ 1 m. weir

Space between orifice to orifice = 0.0146 m.

= 1.46 cm.

Give 1 m. of outlet weir have orifice 25 pores/side

2 side = 50 pores

Then total orifice = 614 pores

Then sum area of orifice = 0.31 m2

22 Flow Rate pass through 1 orifice = 0.244 m3

/hr

Each of orifice area =

Each of orifice area = 0.0005067 m2

Theory

Velocity pass through each orifice = 0.133906 m/s

4

2D

AvQ=



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LaunderLaunder

Collection Water at Central Tank



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23 Inlet Structure

From Static Mixer Design criteria velocity pass through static mixer = 1 - 2 m/s

Select velocity = 1.5 m/s

Theory

Area = m2

= 0.027778 m2

Circular pipe area =

= 0.035368

= 0.188063 m.

= 7.404063 in. 7 in.

24 Calculation Surface Loading (Sedimentation Zone)

Surface Area at Sedimentation Zone =

= 13.28177 m.

= 4 m.

Surface Area at Sedimentation Zone = 125.9821 m2

Surface Loading =

= 1.190645 m/hr.

Design Criteria 1.3 - 1.9 m/hr upflow (radial upflow type)

Text Book (Chularrongkron University < 4.2 m/hr.

Water Works Engineering 0.8333 - 1.6666 m/hr

AvQ =

v

Q

4

2D

2D

D

outsideD

A

Q

44

2

2

2

widthxLaundersinsideoutsideDD +

)2( widthxLaundersinsideD

+

clarifier_tank_skert2

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