chapter 6: friction force - pdx.edu · block a in fig. 6-56 has mass ma 4.0 kg, and block b has...
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PH-211 Andres La Rosa
CHAPTER 6: Friction Force ____________________________________________________________________
View of the contact surface at a microscopic scale
Surfaces are rough at microscopic levels
Stationary surface
Moving block
Stationary surface
Then, it turns out, to keep the mass M moving at constant
Here we describe an experimental fact:
velocity, we need to apply a force Fk somewhat smaller than Fs, max
(external force )M
Interpretation of the experimental fact described above:
Stationary surface
Static friction forces
Then, it turns out, to keep the mass M moving at constant
velocity , we need to apply a force Fk somewhat lower than Fs, max
>
Fs, max
Fk
FkFs, max
Maximum static friction force
Kinetic friction force
(external force )
M
What happens when we apply an external force of increasing strength?
M
M
Stationary surface
Stationary surface
Friction force
Magnitude of the friction force
2N
Example
Exercise
If m = 1 Kg then,
N"
m = 1 Kg
mg
N'
N'
N' + N' = mg - 2 Newtons
STATIC CASE
KINETIC CASE
Quantifying the friction force
=
=
Exercise μs = 0.15
CH-6, Problem #25
B
A
What is the maximum weight of block-A, for which the system will remain stationary? (Block-B weights 711 N)
No horizontal motion implies
Maximum static friction force
No motion along the vertical direction implies,
WB= 711 N
μ = 0.25
fs, max
=
=
=
= Newtons = 178 Newtons
fs, max
Warm up, for problems involving inclined planes 1)
Resolving the force mg into components parallel and perpendicular to the ramp
2)
3)
4)
5)
Ff
Ff
Ch-6 Problem 79. Block A in Fig. 6-56 has mass mA 4.0 kg, and
block B has mass mB 2.0 kg. The coefficient of kinetic friction
between block B and the horizontal plane is �k 0.50. The inclined
plane is frictionless and at angle � 30°. The pulley serves only to change the direction of the cord connecting the blocks. The cord has negligible mass. Find (a) the tension in the cord and (b) the magnitude of the acceleration of the blocks.
Is a1 =a2?
a1
a2 2 Kg4 Kg
Forces on m1 Forces on m2
Example. A block is placed on an inclined plane
Question: Is ?
a) First, let's consider no other external force than the gravitational force
m g sin θ =
b) Let's apply now an external force Fext
v = 0 v � 0
2. Usually μs > μk
0.1 < μ <1 for many pair of materials
v = 0 v
However: μ depends very much on surface conditions (cleanliness)
This rule is true only if the objects in contact do not deform appreciable.
1. The friction force is proportional to the normal force at the surface: f = μs N
N1
N2
f1 f2
General rules for dry sliding friction
3. For a given object, the friction force is independent of the apparent area in contact with the supporting surface
In both cases the same force F is needed to drag the block.
apparent areaa
Explanation: The actual contact area is the same in both cases (since the normal force is the same)
actual contact area
Increasing the load increases the normal force N, and increases the actual contact area
fs, max α actual contact area Actual contact area α N Hence fs, max α N More quantitatively, fs, max = μ N
Key aspects in friction: - The actual contact area is proportional to the normal force - When two objects are forced together, the high peaks of their surface will crumble, bringing more and more area into intimate contact.
Metal-metal friction