chapter 6, continued
DESCRIPTION
Chapter 6, Continued. Summary so Far. Work (constant force): W = F || d =Fd cos θ. Work-Energy Principle: W net = (½)m(v 2 ) 2 - (½)m(v 1 ) 2 KE Total work done by ALL forces!. Kinetic Energy: KE (½)mv 2. Sect. 6-4: Potential Energy. - PowerPoint PPT PresentationTRANSCRIPT
Chapter 6, Continued
Summary so Far
• Work-Energy Principle:Wnet = (½)m(v2)2 - (½)m(v1)2 KE Total work done by ALL forces!
• Kinetic Energy:KE (½)mv2
• Work (constant force):
W = F||d =Fd cosθ
Sect. 6-4: Potential Energy
A mass can have a Potential Energy due to its environment
Potential Energy (PE)
Energy associated with the position or configuration of a mass.
Examples of potential energy:
A wound-up spring
A stretched elastic band
An object at some height above the ground
• Potential Energy (PE) Energy associated with the position or configuration of a mass.
Potential work done!
Gravitational Potential Energy:
PEgrav mgy
y = distance above Earth
m has the potential to do work
mgy when it falls
(W = Fy, F = mg)
Gravitational Potential Energy
(PE)grav
So, in raising a mass m to a height h, the work done by the external force is
Fexthcosθ
We know that for constant speedΣFy = Fext – mg = 0
So we define the gravitational potential energy at a height y above some reference point (y1) as
• Consider a problem in which the height of a mass above the Earth changes from y1 to y2:
• The Change in Gravitational PE is:
(PE)grav = mg(y2 - y1)
• Work done on the mass: W = (PE)grav
y = distance above Earth
Where we choose y = 0 is arbitrary, since we take the difference in 2 y’s in (PE)grav
Of course, this potential energy can be converted to kinetic energy if the object is dropped.
Potential energy is a property of a system as a whole, not just of the object (because it depends on external forces).
If PEgrav = mgy, from where do we measure y?
It turns out not to matter,
as long as we are consistent about where we choose y = 0. Because only changes in potential energy can be measured.
Example 6-7: Potential energy changes for a roller coasterA roller-coaster car, mass m = 1000 kg, moves from point 1 to point 2 & then to point 3.
a. Calculate the gravitational potential energy at points 2 & 3 relative to point 1. (That is, take y = 0 at point 1.) b. Calculate the change in potential energy when the car goes from point 2 to point 3. c. Repeat parts a. & b., but take the reference point (y = 0) at point 3.
∆PE depends only on differences in vertical height.
Many other types of potential energy besides gravitational exist!
An Ideal Spring, is characterized by
a spring constant k, which is a measure
of it’s “stiffness”. The restoring force
of the spring on the hand:
Fs = - kx
(Fs >0, x <0; Fs <0, x >0)
This is known as Hooke’s “Law” (but, it isn’t
really a law!) It can be shown that the
work done by the person is
W = (½)kx2 (PE)elastic
We use this as the definition of
Elastic Potential Energy
Consider an Ideal Spring
Work Done to Compress Spring
Elastic Potential Energy (PE)elastic ≡ (½)kx2
Relaxed Spring
The work to compress the spring a distance x is
W = (½)kx2 (PE)elastic The spring stores potential energy!
When the spring is released, it transfers it’s potential energy PEe = (½)kx2 to the mass in the
form of kinetic energy KE = (½)mv2
• In a problem in which compression or stretching distance of spring changes from x1 to x2.
• The change in PE is:
(PE)elastic = (½)k(x2)2 - (½)k(x1)2
• The work done is: W = - (PE)elastic
The PE belongs to the system,
not to individual objects