chapter 11 properties of solutions. chapter 11 table of contents copyright © cengage learning. all...
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Chapter 11
Properties of Solutions
Chapter 11
Table of Contents
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11.1 Solution Composition
11.2 The Energies of Solution Formation
11.3 Factors Affecting Solubility
11.4 The Vapor Pressures of Solutions
11.5 Boiling-Point Elevation and Freezing-Point Depression
11.6 Osmotic Pressure
11.7 Colligative Properties of Electrolyte Solutions
11.8 Colloids
Section 11.1
Solution Composition
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Various Types of Solutions
ExampleState of Solution State of Solute
State of Solvent
Air, natural gas Gas Gas Gas
Vodka, antifreeze Liquid Liquid Liquid
Brass Solid Solid Solid
Carbonated water (soda) Liquid Gas Liquid
Seawater, sugar solution Liquid Solid Liquid
Hydrogen in platinum Solid Gas Solid
Section 11.1
Solution Composition
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Solution Composition
AA
moles of soluteMolarity ( ) =
liters of solution
mass of soluteMass (weight) percent = 100%
mass of solution
molesMole fraction ( ) =
total moles of solution
moles of soluteMolality ( ) =
kilogram of s
M
molvent
Section 11.1
Solution Composition
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Molarity
moles of soluteMolarity ( ) =
liters of solution M
Section 11.1
Solution Composition
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Exercise
You have 1.00 mol of sugar in 125.0 mL of solution. Calculate the concentration in units of molarity.
8.00 M
Section 11.1
Solution Composition
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Exercise
You have a 10.0 M sugar solution. What volume of this solution do you need to have 2.00 mol of sugar?
0.200 L
Section 11.1
Solution Composition
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Exercise
Consider separate solutions of NaOH and KCl made by dissolving 100.0 g of each solute in 250.0 mL of solution. Calculate the concentration of each solution in units of molarity.
10.0 M NaOH
5.37 M KCl
Section 11.1
Solution Composition
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Mass Percent
mass of soluteMass (weight) percent = 100%
mass of solution
Section 11.1
Solution Composition
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Exercise
What is the percent-by-mass concentration of glucose in a solution made my dissolving 5.5 g of glucose in 78.2 g of water?
6.6%
Section 11.1
Solution Composition
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Mole Fraction
AA
molesMole fraction ( ) =
total moles of solution
Section 11.1
Solution Composition
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Exercise
A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the mole fraction of H3PO4. (Assume water has a density of 1.00 g/mL.)
0.0145
Section 11.1
Solution Composition
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Molality
moles of soluteMolality ( ) =
kilogram of solvent m
Section 11.1
Solution Composition
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Exercise
A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the molality of the solution. (Assume water has a density of 1.00 g/mL.)
0.816 m
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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Formation of a Liquid Solution
1. Separating the solute into its individual components (expanding the solute).
2. Overcoming intermolecular forces in the solvent to make room for the solute (expanding the solvent).
3. Allowing the solute and solvent to interact to form the solution.
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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Steps in the Dissolving Process
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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Steps in the Dissolving Process
• Steps 1 and 2 require energy, since forces must be overcome to expand the solute and solvent.
• Step 3 usually releases energy.• Steps 1 and 2 are endothermic, and step 3 is
often exothermic.
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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Enthalpy (Heat) of Solution
• Enthalpy change associated with the formation of the solution is the sum of the ΔH values for the steps:
ΔHsoln = ΔH1 + ΔH2 + ΔH3
• ΔHsoln may have a positive sign (energy absorbed) or a negative sign (energy released).
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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Enthalpy (Heat) of Solution
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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Concept Check
Explain why water and oil (a long chain hydrocarbon) do not mix. In your explanation, be sure to address how ΔH plays a role.
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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The Energy Terms for Various Types of Solutes and Solvents
H1 H2 H3 Hsoln Outcome
Polar solute, polar solvent Large Large Large, negative Small Solution forms
Nonpolar solute, polar solvent Small Large Small Large, positive No solution forms
Nonpolar solute, nonpolar solvent
Small Small Small Small Solution forms
Polar solute, nonpolar solvent Large Small Small Large, positive No solution forms
Section 11.2
Atomic Masses
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The Energies of Solution Formation
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In General
• One factor that favors a process is an increase in probability of the state when the solute and solvent are mixed.
• Processes that require large amounts of energy tend not to occur.
• Overall, remember that “like dissolves like”.
Section 11.3
The Mole Factors Affecting Solubility
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• Structural Effects: Polarity
• Pressure Effects: Henry’s law
• Temperature Effects: Affecting aqueous solutions
Section 11.3
The Mole Factors Affecting Solubility
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Pressure Effects
• Henry’s law: C = kPC = concentration of dissolved gas
k = constant
P = partial pressure of gas solute above the solution
• Amount of gas dissolved in a solution is directly proportional to the pressure of the gas above the solution.
Section 11.3
The Mole Factors Affecting Solubility
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A Gaseous Solute
Section 11.3
The Mole Factors Affecting Solubility
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Temperature Effects (for Aqueous Solutions)
• Although the solubility of most solids in water increases with temperature, the solubilities of some substances decrease with increasing temperature.
• Predicting temperature dependence of solubility is very difficult.
• Solubility of a gas in solvent typically decreases with increasing temperature.
Section 11.3
The Mole Factors Affecting Solubility
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The Solubilities of Several Solids as a Function of Temperature
Section 11.3
The Mole Factors Affecting Solubility
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The Solubilities of Several Gases in Water
Section 11.4
The Vapor Pressures of Solutions
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An Aqueous Solution and Pure Water in a Closed Environment
Section 11.4
The Vapor Pressures of Solutions
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Liquid/Vapor Equilibrium
Section 11.4
The Vapor Pressures of Solutions
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Vapor Pressure Lowering: Addition of a Solute
Section 11.4
The Vapor Pressures of Solutions
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Vapor Pressures of Solutions
• Nonvolatile solute lowers the vapor pressure of a solvent.
• Raoult’s Law:
Psoln = observed vapor pressure of
solution
solv = mole fraction of solvent
= vapor pressure of pure solvent
soln solv solv = P P
solvP
Section 11.4
The Vapor Pressures of Solutions
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A Solution Obeying Raoult’s Law
Section 11.4
The Vapor Pressures of Solutions
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Nonideal Solutions
• Liquid-liquid solutions where both components are volatile.
• Modified Raoult’s Law:
• Nonideal solutions behave ideally as the mole fractions approach 0 and 1.
Total A A B B = + P P P
Section 11.4
The Vapor Pressures of Solutions
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Vapor Pressure for a Solution of Two Volatile Liquids
Section 11.4
The Vapor Pressures of Solutions
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Summary of the Behavior of Various Types of Solutions
Interactive Forces Between Solute (A) and Solvent (B)
ParticlesHsoln
T for Solution Formation
Deviation from
Raoult’s Law
Example
A A, B B A B Zero ZeroNone (ideal
solution)Benzene-toluene
A A, B B < A BNegative
(exothermic)Positive Negative
Acetone-water
A A, B B > A BPositive
(endothermic)Negative Positive
Ethanol-hexane
Section 11.4
The Vapor Pressures of Solutions
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Concept Check
For each of the following solutions, would you expect it to be relatively ideal (with respect to Raoult’s Law), show a positive deviation, or show a negative deviation?
a) Hexane (C6H14) and chloroform (CHCl3)
b) Ethyl alcohol (C2H5OH) and water
c) Hexane (C6H14) and octane (C8H18)
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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• Depend only on the number, not on the identity, of the solute particles in an ideal solution: Boiling-point elevation Freezing-point depression Osmotic pressure
Colligative Properties
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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• Nonvolatile solute elevates the boiling point of the solvent.
• ΔT = Kbmsolute
ΔT = boiling-point elevation
Kb = molal boiling-point elevation constant
msolute= molality of solute
Boiling-Point Elevation
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Boiling Point Elevation: Liquid/Vapor Equilibrium
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Boiling Point Elevation: Addition of a Solute
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Boiling Point Elevation: Solution/Vapor Equilibrium
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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• When a solute is dissolved in a solvent, the freezing point of the solution is lower than that of the pure solvent.
• ΔT = Kfmsolute
ΔT = freezing-point depression
Kf = molal freezing-point depression
constant
msolute= molality of solute
Freezing-Point Depression
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Freezing Point Depression: Solid/Liquid Equilibrium
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Freezing Point Depression: Addition of a Solute
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Freezing Point Depression: Solid/Solution Equilibrium
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Changes in Boiling Point and Freezing Point of Water
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Exercise
A solution was prepared by dissolving 25.00 g glucose in 200.0 g water. The molar mass of glucose is 180.16 g/mol. What is the boiling point of the resulting solution (in °C)? Glucose is a molecular solid that is present as individual molecules in solution.
100.35 °C
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Exercise
You take 20.0 g of a sucrose (C12H22O11) and NaCl mixture and dissolve it in 1.0 L of water. The freezing point of this solution is found to be -0.426°C. Assuming ideal behavior, calculate the mass percent composition of the original mixture, and the mole fraction of sucrose in the original mixture.
72.8% sucrose and 27.2% sodium chloride;
mole fraction of the sucrose is 0.313
Section 11.5
Boiling-Point Elevation and Freezing-Point Depression
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Exercise
A plant cell has a natural concentration of 0.25 m. You immerse it in an aqueous solution with a freezing point of –0.246°C. Will the cell explode, shrivel, or do nothing?
Section 11.6
Osmotic Pressure
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• Osmosis – flow of solvent into the solution through a semipermeable membrane.
• = MRT
= osmotic pressure (atm)
M = molarity of the solution
R = gas law constant
T = temperature (Kelvin)
Section 11.6
Osmotic Pressure
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Section 11.6
Osmotic Pressure
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Osmosis
Section 11.6
Osmotic Pressure
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Section 11.6
Osmotic Pressure
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Exercise
When 33.4 mg of a compound is dissolved in 10.0 mL of water at 25°C, the solution has an osmotic pressure of 558 torr. Calculate the molar mass of this compound.
111 g/mol
Section 11.7
Colligative Properties of Electrolyte Solutions
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• The relationship between the moles of solute dissolved and the moles of particles in solution is usually expressed as:
van’t Hoff Factor, i
moles of particles in solution =
moles of solute dissolvedi
Section 11.7
Colligative Properties of Electrolyte Solutions
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Ion Pairing
• At a given instant a small percentage of the sodium and chloride ions are paired and thus count as a single particle.
Section 11.7
Colligative Properties of Electrolyte Solutions
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• The expected value for i can be determined for a salt by noting the number of ions per formula unit (assuming complete dissociation and that ion pairing does not occur). NaCl i = 2 KNO3 i = 2
Na3PO4 i = 4
Examples
Section 11.7
Colligative Properties of Electrolyte Solutions
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• Ion pairing is most important in concentrated solutions.
• As the solution becomes more dilute, the ions are farther apart and less ion pairing occurs.
• Ion pairing occurs to some extent in all electrolyte solutions.
• Ion pairing is most important for highly charged ions.
Ion Pairing
Section 11.7
Colligative Properties of Electrolyte Solutions
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Modified Equations
= T imK
= iMRT
Section 11.8
Colloids
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• A suspension of tiny particles in some medium.
• Tyndall effect – scattering of light by particles.
• Suspended particles are single large molecules or aggregates of molecules or ions ranging in size from 1 to 1000 nm.
Section 11.8
Colloids
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Types of Colloids
Section 11.8
Colloids
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• Destruction of a colloid.• Usually accomplished either by heating or
by adding an electrolyte.
Coagulation