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Chapter 11 Frequency Response 11.1 Fundamental Concepts 11.2 High-Frequency Models of Transistors 11 3 Analysis Procedure 11.3 Analysis Procedure 11.4 Frequency Response of CE and CS Stages 11.5 Frequency Response of CB and CG Stages 11.6 Frequency Response of Followers 11.7 Frequency Response of Cascode Stage 11.8 Frequency Response of Differential Pairs 11.9 Additional Examples CH 10 Differential Amplifiers 1

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  • Chapter 11 Frequency Response

    11.1 Fundamental Concepts 11.2 High-Frequency Models of Transistors 11 3 Analysis Procedure 11.3 Analysis Procedure 11.4 Frequency Response of CE and CS Stages 11.5 Frequency Response of CB and CG Stagesq y p g 11.6 Frequency Response of Followers 11.7 Frequency Response of Cascode Stage 11.8 Frequency Response of Differential Pairs 11.9 Additional Examples

    CH 10 Differential Amplifiers 11

  • Chapter Outline

    CH 10 Differential Amplifiers 2CH 11 Frequency Response 2

  • High Frequency Roll-off of Amplifier

    As frequency of operation increases, the gain of amplifier

    CH 10 Differential Amplifiers 3CH 11 Frequency Response 3

    As frequency of operation increases, the gain of amplifier decreases. This chapter analyzes this problem.

  • Example: Human Voice I

    Natural Voice Telephone System

    Natural human voice spans a frequency range from 20Hz to 20KHz, however conventional telephone system passes

    CH 10 Differential Amplifiers 4

    p y pfrequencies from 400Hz to 3.5KHz. Therefore phone conversation differs from face-to-face conversation. CH 11 Frequency Response 4

  • Example: Human Voice II

    Path traveled by the human voice to the voice recorder

    Mouth RecorderAir

    Path traveled by the human voice to the human ear

    Mouth EarAir

    SkullSkull

    Since the paths are different, the results will also be

    CH 10 Differential Amplifiers 5CH 11 Frequency Response 5

    different.

  • Example: Video Signal

    High Bandwidth Low BandwidthHigh Bandwidth o a d dt

    Video signals without sufficient bandwidth become fuzzy as they fail to abruptly change the contrast of pictures from complete white into complete black.

    CH 10 Differential Amplifiers 6

    complete white into complete black.

    CH 11 Frequency Response 6

  • Gain Roll-off: Simple Low-pass Filter

    In this simple example, as frequency increases the impedance of C decreases and the voltage divider consists

    CH 10 Differential Amplifiers 7

    impedance of C1 decreases and the voltage divider consists of C1 and R1 attenuates Vin to a greater extent at the output.

    CH 11 Frequency Response 7

  • Gain Roll-off: Common Source

    1||

    1||out m in DL

    V g V RC s

    The capacitive load, CL, is the culprit for gain roll-off since

    CH 10 Differential Amplifiers 8CH 11 Frequency Response 8

    at high frequency, it will “steal” away some signal current and shunt it to ground.

  • Frequency Response of the CS Stage

    RV1222

    LD

    Dm

    in

    out

    CRRg

    VV

    At low frequency, the capacitor is effectively open and the gain is flat. As frequency increases, the capacitor tends to

    CH 10 Differential Amplifiers 9CH 11 Frequency Response 9

    g q y , pa short and the gain starts to decrease. A special frequency is ω=1/(RDCL), where the gain drops by 3dB.

  • Example: Figure of Merit

    CVVMOF 1...

    LCCT CVV

    This metric quantifies a circuit’s gain bandwidth and This metric quantifies a circuit s gain, bandwidth, and power dissipation. In the bipolar case, low temperature, supply, and load capacitance mark a superior figure of

    itCH 10 Differential Amplifiers 10CH 11 Frequency Response 10

    merit.

  • Example: Relationship between Frequency Response and Step Responsep p p

    2 2 2

    1H s j 0 1 expouttV t V u t

    R C

    2 2 21 1 1R C

    01 1

    pout R C

    The relationship is such that as R1C1 increases, the bandwidth drops and the step response becomes slower.

    CH 10 Differential Amplifiers 11CH 11 Frequency Response 11

    bandwidth drops and the step response becomes slower.

  • Bode Plot

    11 ss

    21011

    )( zzss

    AsH

    21

    11pp

    When we hit a zero, ωzj, the Bode magnitude rises with a slope of +20dB/dec.

    CH 10 Differential Amplifiers 12CH 11 Frequency Response 12

    When we hit a pole, ωpj, the Bode magnitude falls with a slope of -20dB/dec

  • Example: Bode Plot

    1LD

    p CR1

    1

    The circuit only has one pole (no zero) at 1/(RDCL), so the l d f 0 t 20dB/d

    CH 10 Differential Amplifiers 13CH 11 Frequency Response 13

    slope drops from 0 to -20dB/dec as we pass ωp1.

  • Pole Identification Example I

    11 p CR

    12

    inSp CR1

    LD

    p CR

    222212 11Dm

    in

    out RgVV

    CH 10 Differential Amplifiers 14CH 11 Frequency Response 14

    21 11 ppin

  • Pole Identification Example II

    1 1inS

    p

    Cg

    R

    1||1

    LDp CR

    12

    CH 10 Differential Amplifiers 15CH 11 Frequency Response 15

    mg

  • Circuit with Floating Capacitor

    The pole of a circuit is computed by finding the effective resistance and capacitance from a node to GROUND.

    CH 10 Differential Amplifiers 16CH 11 Frequency Response 16

    The circuit above creates a problem since neither terminal of CF is grounded.

  • Miller’s Theorem

    F

    AZZ

    11

    F

    AZZ

    /112

    If Av is the gain from node 1 to 2, then a floating impedance Z can be converted to two grounded impedances Z and Z

    vA1 vA/11

    CH 10 Differential Amplifiers 17CH 11 Frequency Response 17

    ZF can be converted to two grounded impedances Z1 and Z2.

  • Miller Multiplication

    With Miller’s theorem, we can separate the floating capacitor However the input capacitor is larger than the

    CH 10 Differential Amplifiers 18CH 11 Frequency Response 18

    capacitor. However, the input capacitor is larger than the original floating capacitor. We call this Miller multiplication.

  • Example: Miller Theorem

    in CRR

    11 out

    CR

    11

    1 FDmS CRgR 1 F

    DmD CRg

    R

    1

    CH 10 Differential Amplifiers 19CH 11 Frequency Response 19

  • High-Pass Filter Response

    1212

    12

    1

    11

    CRCR

    VV

    in

    out

    The voltage division between a resistor and a capacitor can be configured such that the gain at low frequency is reduced

    CH 10 Differential Amplifiers 20

    reduced.

    CH 11 Frequency Response 20

  • Example: Audio Amplifier

    nFCi 6.79 nFCL 8.39

    200/1100i

    gKR

    In order to successfully pass audio band frequencies (20 Hz-20 KHz), large input and output capacitances are needed.

    200/1mg

    CH 10 Differential Amplifiers 21CH 11 Frequency Response 21

  • Capacitive Coupling vs. Direct Coupling

    Capacitive Coupling Di t C liCapacitive Coupling Direct Coupling

    Capacitive coupling, also known as AC coupling, passes AC signals from Y to X while blocking DC contents.

    CH 10 Differential Amplifiers 22

    This technique allows independent bias conditions between stages. Direct coupling does not.CH 11 Frequency Response 22

  • Typical Frequency Response

    Lower Corner Upper Corner

    CH 10 Differential Amplifiers 23CH 11 Frequency Response 23

  • High-Frequency Bipolar Model

    b jeC C C

    At high frequency, capacitive effects come into play. Cb represents the base charge, whereas C and Cje are the

    CH 10 Differential Amplifiers 24CH 11 Frequency Response 24

    je junction capacitances.

  • High-Frequency Model of Integrated Bipolar Transistor

    Since an integrated bipolar circuit is fabricated on top of a

    CH 10 Differential Amplifiers 25CH 11 Frequency Response 25

    substrate, another junction capacitance exists between the collector and substrate, namely CCS.

  • Example: Capacitance Identification

    CH 10 Differential Amplifiers 26CH 11 Frequency Response 26

  • MOS Intrinsic Capacitances

    For a MOS, there exist oxide capacitance from gate to channel junction capacitances from source/drain to

    CH 10 Differential Amplifiers 27CH 11 Frequency Response 27

    channel, junction capacitances from source/drain to substrate, and overlap capacitance from gate to source/drain.

  • Gate Oxide Capacitance Partition and Full Model

    The gate oxide capacitance is often partitioned between The gate oxide capacitance is often partitioned between source and drain. In saturation, C2 ~ Cgate, and C1 ~ 0. They are in parallel with the overlap capacitance to form CGS and C

    CH 10 Differential Amplifiers 28CH 11 Frequency Response 28

    CGD.

  • Example: Capacitance Identification

    CH 10 Differential Amplifiers 29CH 11 Frequency Response 29

  • Transit Frequency

    gf mT 2mTgf 2

    C

    fT2GS

    T Cf2

    Transit frequency, fT, is defined as the frequency where the current gain from input to output drops to 1

    CH 10 Differential Amplifiers 30CH 11 Frequency Response 30

    current gain from input to output drops to 1.

  • Example: Transit Frequency Calculation

    THGSnT VVLf 2232

    VVVnmL

    10065

    GHfsVcm

    mVVV

    n

    THGS

    226)./(400

    1002

    CH 10 Differential Amplifiers 31

    GHzfT 226

    CH 11 Frequency Response 31

  • Analysis Summary

    The frequency response refers to the magnitude of the transfer function.

    Bode’s approximation simplifies the plotting of the frequency response if poles and zeros are known.

    In general, it is possible to associate a pole with each node In general, it is possible to associate a pole with each node in the signal path.

    Miller’s theorem helps to decompose floating capacitors i t d d l tinto grounded elements.

    Bipolar and MOS devices exhibit various capacitances that limit the speed of circuits.p

    CH 10 Differential Amplifiers 32CH 11 Frequency Response 32

  • High Frequency Circuit Analysis Procedure

    Determine which capacitor impact the low-frequency region of the response and calculate the low-frequency pole (neglect transistor capacitance).(neglect transistor capacitance).

    Calculate the midband gain by replacing the capacitors with short circuits (neglect transistor capacitance).

    Include transistor capacitances. Merge capacitors connected to AC grounds and omit those

    that play no role in the circuit.t at p ay o o e t e c cu t Determine the high-frequency poles and zeros. Plot the frequency response using Bode’s rules or exact

    l ianalysis.

    CH 10 Differential Amplifiers 33CH 11 Frequency Response 33

  • Frequency Response of CS Stagewith Bypassed Degeneration

    1sCRRgV 11

    SmbS

    bSDm

    X

    out

    RgsCRsCRRgs

    VV

    I d i h idb d i i C i In order to increase the midband gain, a capacitor Cb is placed in parallel with Rs.

    The pole frequency must be well below the lowest signal

    CH 10 Differential Amplifiers 34

    p q y gfrequency to avoid the effect of degeneration.

    CH 11 Frequency Response 34

  • Unified Model for CE and CS Stages

    CH 10 Differential Amplifiers 35CH 11 Frequency Response 35

  • Unified Model Using Miller’s Theorem

    CH 10 Differential Amplifiers 36CH 11 Frequency Response 36