burnng1
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burnerTRANSCRIPT
burnNGGivenFG Flow712Nm3/hrsreekanthtm's CALCthorium90's
CALCCH497.49mol%Calculation of combustion air required for the
given NG and given excess air.Calculation of combustion air
required for the given NG and given excess air.C2H61.5mol%Basis:
100 kmol of given natural gas (NG), normal conditions
(MCR=100%)Basis: 100 kmol of given natural gas (NG), normal
conditions (MCR=100%)N21mol%componentquantitystoichiometric O2
(*)stoichiometric O2Resulting gases after stoichiom
burningcomponentquantitystoichiometric O2 (*)stoichiometric
O2Resulting gases after stoichiom burningCO2-0.01mol%kmolkmol O2 /
kmol compkmolCO2, kmolH2O (g), kmolN2, kmolkmolkmol O2 / kmol
compkmolCO2, kmolH2O (g), kmolN2, kmolSince basis was 100kmol, need
to convert to 31.76kmol,
thereforeN20.317658606200000.3176586062N20.317658606200000.3176586062CH430.9685375212mol%CO2000000CO2000000C2H60.4764879093mol%CH430.9685375212261.937075042430.968537521261.93707504240CH430.9685375212261.937075042430.968537521261.93707504240N20.3176586062mol%C2H60.47648790933.51.66770768270.95297581871.4294637280C2H60.47648790933.51.66770768270.95297581871.4294637280CO2-0.0031765861mol%C3H8050000C3H8050000Notice
CO2 is negative, could be direct import of results from an analyzer
needing abit of calibration, Therefore, some manipulation is
needed. ie: put to 0C4H1006.50000C4H1006.50000CO (assumed)
Kostas Kalaitzoglou: Just to close balance and have total = 100
kmol.You have to do something similar, not necessarily with
CO.00.50000CO (assumed)
Kostas Kalaitzoglou: Just to close balance and have total = 100
kmol.You have to do something similar, not necessarily with
CO.00.50000Total31.76663.631.963.40.32Total31.76663.631.963.40.32Putting
these in, one gets 303kmol "Stoichiometric air for complete
burning"Air for 100% burningkmol303Stoichiometric air for complete
burningAir for 100% burningkmol303Stoichiometric air for complete
burningTaking MW of air to be28.9Air MWMass of air
is8753.2296226423kg airExcess air%20specific value to be advised by
VendorExcess air%20specific value to be advised by VendorFrom
picture below,0.26kg water/kg dry airO2 in with airkmol76O2 in with
airkmol762275.839701887kg waterN2 in with airkmol287N2 in with
airkmol287Convert to kmol18.0153Water MWHumidity inkmol0
Kostas Kalaitzoglou: You can estimate it for more precise
resultsHumidity inkmol126.5
Kostas Kalaitzoglou: You can estimate it for more precise
results
126.328kmol waterTotal air inkmol363Total air inkmol490Total air inNm38147Total air inNm310982Resulting flue gasesResulting flue gasesO2 kmol12.72O2 kmol12.72CO2kmol31.9CO2kmol31.9H2O (g)kmol63.4H2O (g)kmol189.9N2 kmol287N2 kmol287Totalkmol395Totalkmol522TotalNm3/h8864TotalNm3/h11699