bohr - rutherford model of atom

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The Bohr – Rutherford Model of the Atom Chemistry - Lesson 8

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Page 1: Bohr - Rutherford Model of Atom

The Bohr – Rutherford Model of the Atom

Chemistry - Lesson 8

Page 2: Bohr - Rutherford Model of Atom

Experiments

There are two experiments that lead to the Bohr Model

1. Gold Foil Experiment

2. Hydrogen Absorption Spectrum

• ..\Links\Rutherford_s_Experiment_Nuclear_Atom.flv

• ..\Links\viewing_hydrogen_spectrum.flv

Page 3: Bohr - Rutherford Model of Atom

The Conclusions

• Protons and Neutrons make up a dense nuclear core• Electrons circle the nucleus in discrete shells or orbitals• Nuclear core is positively charged• Proton and Electron have opposite charges that are

equal in size• The shells can only hold specific numbers of electons• 2, 8, 8, 8….. (This is actually a simplification

Page 4: Bohr - Rutherford Model of Atom

Making Bohr – Rutherford Diagrams

Using these conclusions, we can draw a model of what the atom looks like.

1. Using a periodic table, find the number of protons and neutrons.

• Protons = Atomic Number • Neutrons = Atomic Mass –

Atomic Number

2. Put the protons and the neutrons in the nucleus of the atom.

Example – Oxygen

P = Atomic Number

= 8

N = Atomic Mass – Atomic Number

= 16 – 8

= 8

P=8

N=8

Page 5: Bohr - Rutherford Model of Atom

Now the electrons

3. Using the charge, find the number of electrons

• For now we will assume the atom is neutral (electrons = protons)

4. Put the electrons in the shells. When one shell is full start another shell

• Remember the maximum number of electrons for the shells is 2, 8, 8, 8…..

e = p = 8

P=8

N=8

Page 6: Bohr - Rutherford Model of Atom

Practice

What will the Bohr Rutherford diagram for Aluminum look like?

p = Atomic Number = 13

n = Atomic Mass – Atomic Number= 27 - 13= 14

Since the aluminum is neutral,e = pe = 13

P=13

N=14

Page 7: Bohr - Rutherford Model of Atom

Practice

What will the Bohr Rutherford diagram for Argon look like?

p = Atomic Number

= 18

n = Atomic Mass – Atomic Number

= 40 - 18

=22

Since the argon is neutral,

e = p

e = 18

P=18

N=22

P=18

N=22