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Binomial Expansion
The process of expanding a binomial uses the following pattern
(a + b)2 = a2 + 2ab + b2 (a+b)3 = a3 + 3a2b + 3ab2 + b3 (a+b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4 (a+b)5 = a5 + 5a4b + 10a3b2 + 10a2b3 + 5ab4 + b5
Binomial Expansion
If we continue the expansion all the way to (a+b)n
1. There are n+1 terms in the expansion 2. The exponents of a decrease by one starting with an and
the exponents of b increase by one starting with b0
3. The sum of the exponents in each term will equal the value of n
(a + b)2 = a2 + 2ab + b2 (a+b)3 = a3 + 3a2b + 3ab2 + b3 (a+b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4 (a+b)5 = a5 + 5a4b + 10a3b2 + 10a2b3 + 5ab4 + b5
Binomial Expansion
Pascal’s Triangle
To fill in the questions marks you can use Pascal’s triangle
Expand (a+b)7 a7 + ?a6b + ?a5b2 + ?a4b3 + ?a3b4 + ?a2b5 + ?ab6 + b7
a7 + 7a6b + 21a5b2 + 35a4b3 + 35a3b4 + 21a2b5 + 7ab6 + b7
Using Pascal’s Triangle
Expand (2x + 1)4 4 0 3 1 2 2 1 3 0 4
4 3 2 4
4 3 2
(1)(2 ) (1) (4)(2 ) (1) (6)(2 ) (1) (4)(2 ) (1) (1)(2 ) (1)
(1)(16 )(1) (4)(8 )(1) (6)(4 )(1) (4)(2 )(1) (1)(1)(1)
16 32 24 8 1
x x x x x
x x x x
x x x x
(3+1)2 + (4+1)2 + (5+1)2 + (6+1)2 = 126
Arithmetic with d = 0.7 10 is the 11th term
S10 = (10/2)(3+10) = 65
(2x)4 + 4(2x)3(y) + 6(2x)2(y)2 + 4(2x)(y)3 + y4
16x4 + 4(8x3)(y) + 6(4x2)(y)2 + 4(2x)(y)3 + y4
16x4 + 32x3y + 24x2y2 + 8xy3 + y4
Expand
Binomial Coefficient
Since Pascal’s Triangle might not always be a feasible option you need another way to figure out the value of each coefficient in your expansion.
To do this you will use the following
Binomial Coefficient
Using the method to find the binomial coefficient allows us to write the expansion of (a+b)n as
Binomial Coefficient
Expand (x + 2y)5
5 0 4 1 3 2 2 3 1 4 0 5
5 4 3 2 2 3 4 5
5 4 3 2
5 5 5 5 5 5( ) (2 ) ( ) (2 ) ( ) (2 ) ( ) (2 ) ( ) (2 ) ( ) (2 )
0 1 2 3 4 5
(1)( )(1) (5)( )(2 ) (10)( )(4 ) (10)( )(8 ) (5)( )(16 ) (1)(1)(32 )
10 40 8
x y x y x y x y x y x y
x x y x y x y x y y
x x y x y
2 3 4 50 80 32x y xy y
General Term
Find the 6th term of (a+2b)8
8 (6 1) 6 1
3 5
3 5
3 5
8( ) (2 )
6 1
8( ) (2 )
5
56( )(32 )
1792
a b
a b
a b
a b