bell work: factor: mba – 7a + mbn – 7n. answer: (a + n)(mb – 7)

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Bell Work: Factor: mba – 7a + mbn – 7n

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Page 1: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Bell Work:

Factor:

mba – 7a + mbn – 7n

Page 2: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Answer:

(a + n)(mb – 7)

Page 3: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

LESSON 106:LINEAR EQUATIONS, EQUATION OF A LINE THROUGH TWO POINTS

Page 4: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

The graph of a first-degree equation in two unknowns is a straight line. this is the reason we call these equations linear equations.

Page 5: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

The standard form of the equation of a straight line is

ax + by + c = 0

Where a, b, and c are constants (and where a and b are not both zero).

Page 6: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

The following are equations of straight lines in standard form:

4x + y + 1 = 0

-2x – y – 11 = 0

Page 7: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

We remember that if the equation of a line is written so that y is expressed as a function of x, such as

y = mx + b

We say that we have written the equation in slope-intercept form. In this equation m represents the slope of the line and b represents the y intercept of the line, which is the y coordinate of the point where the line in question crosses the y axis.

Page 8: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Thus far, we have learned how to draw the graph of a given linear equation and have learned how to find a good approximation of the equation of a given line. both of these exercises have helped us to understand the relationship between the equation of a line and the graph of a line.

Page 9: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

We can determine the slope of a line by applying the slope formula that we learned in lesson 98.

m = y – y

x – x 2 1

2 1

Page 10: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Example:

Find the equation of the line that passes through the points (4, 2) and (-5, -3).

Page 11: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Answer:

Slope = 5/9

y = 5/9 x + b

(2) = 5/9(4) + b (-3) = 5/9(-5) + b

b = -2/9 b = -2/9

y = 5/9x – 2/9

Page 12: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Example:

Find the equation of the line that passes through the points (4, -2) and (-3, 4).

Page 13: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Answer:

Slope = -6/7

b = 10/7

y = -6/7x + 10/7

Page 14: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

We see from these two examples that when we are given the coordinates of two points that lie on the line, the exact equation of the line can be determined. Estimated values of the slope and intercept are not acceptable for this type of problem.

Page 15: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Example:

Find the equation of the line that passes through the points (4, 3) and (4, -3).

Page 16: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

Answer:

Equation of the line is x = 4.

Slope = undefined

Page 17: Bell Work: Factor: mba – 7a + mbn – 7n. Answer: (a + n)(mb – 7)

HW: Lesson 106 #1-30