beam design lateral stability - uw courses web server
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Beam Design
• Bending
–
– lateral stability
– unbalanced combination of laminations (gluelam)
• Shear
–
• Deflection
–
• Bearing
'
b b
Mf F
S= !
'1.5
v v
Vf F
A= ! (for rectangle beam)
max allow! " !
Lateral Stability
• Cause
• Result
– lateral instability
– decrease in allowable stress
compression
Consider this effect by CL
* CL is a similar adjustment factor with CP
* CP will be discussed in Ch. 7 (for column)
Lateral Stability
• full lateral support
– appropriate connection of a roof or diaphragm (sheathing)
– lu = 0
• Approximate method
– depth-to-thickness ratio (d/b) = 6
bridging or solid blocking required
at intervals of 8 ft max.
b
d
Lateral Stability
Solid blocking Bridging
Lateral Stability (using CL)
• Concept (Euler Buckling)
– Euler critical buckling stress
– Euler-based critical buckling stress
KbE = 0.439 for visually graded lumber
= 0.561 for MEL (machine evaluated lumber)
= 0.610 for MSR (machine stress rating) or gluelam
2
2( )Euler
EF
slenderness ratio FS
!=
"
'
2( )
bE y
bE
B
K EF
R=
Lateral Stability (using CL)
• Procedure of computing CL
Evaluating lu
Evaluating le
Calculating RB
Calculating FbE
Calculating CL
unbraced length of beam
slenderness ratio
b
d
2
e
B
l dR
b=
Lateral Stability (using CL)
• Effective unbraced length, le
Lateral Stability (using CL)
* * *21 / 1 / /
( )1.9 1.9 0.95
bE bx bE bx bE bx
L
F F F F F FC
+ += ! !
• Calculate CL
- Fbx* = tabulated bending stress for x axis multiplied by
adjustment factors (except Cfu, CV, and CL)
- Ey’ = modulus of elasticity about y axis multiplied by
adjustment factors
Lateral Stability (Example)
wTL = 1k / ft, D+S
48’
8 ftul =
6.75*37.5 24F-1.8E gluelam
962.56 7
37.5
ul
d= = < 2.06 198 in
e ul l= =
2
198*37.512.76
6.75
e
B
l dR
b= = =
'
2 2
0.610*16000005994 psi
( ) 12.76
bE y
bE
B
K EF
R= = =
* ( )( )( ) 2400*1.15*1.0*1.0 2760bx bx D M tF F C C C= = = psi
Lateral Stability (Example)
*
59942.172
2760
bE
bx
F
F= =
2* * *
1 / 1 / /
1.9 1.9 0.95
bE bx bE bx bE bx
L
F F F F F FC
! "+ += # #$ %
& '
*1 /
1.6691.9
bE bxF F+
=
0.962=
* Note
Allowable Bending Stress for Strong Axis: Choose the smaller
' ( )( )( )( )bx bx D M t LF F C C C C
+=
' ( )( )( )( )bx bx D M t VF F C C C C
+=
Bearing Stress
0.375b
b
b
lC
l
+=
' ( )( )( )( )c c M t i bF F C C C C
! !=c
Pf
A!= vs.
Unbalanced Combinations of
Laminations