atterberg limit

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1. Liquid limit test for a soil Number of Blow (N) Moisture Content % 15 42,0 20 40,8 28 39,10 Plastic limit test with moisture content 18,7% a. Draw the flow curve from the liquid limit test data and find the liquid limit and flow index. b. What is the plasticity index of the soil. Answer: a. Flow curve, liquid limit, and flow index Flow curve Liquid limit LL = 39,75% Flow index = 1 (%) 2 (%) 2 1 = 42 40,8 20 15 38.5 39 39.5 40 40.5 41 41.5 42 42.5 0 5 10 15 20 25 30 Kadar Air % Jumlah Pukulan (N) Flow Curve

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atterberg limit

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  • 1. Liquid limit test for a soil

    Number of Blow (N) Moisture Content %

    15 42,0

    20 40,8

    28 39,10

    Plastic limit test with moisture content 18,7%

    a. Draw the flow curve from the liquid limit test data and find the liquid limit and flow

    index.

    b. What is the plasticity index of the soil.

    Answer:

    a. Flow curve, liquid limit, and flow index

    Flow curve

    Liquid limit

    LL = 39,75%

    Flow index

    = 1(%) 2(%)

    2 1

    = 42 40,8

    20 15

    38.5

    39

    39.5

    40

    40.5

    41

    41.5

    42

    42.5

    0 5 10 15 20 25 30

    Kad

    ar A

    ir %

    Jumlah Pukulan (N)

    Flow Curve

  • = 1,2

    1,301 1,176

    = 1,2

    0,125

    = 9,6

    b. Plasticity index of the soil

    =

    = 39,75% 18,7%

    = 21,05%

    2. A saturated soil with a volume 19,65 cm3 has a mass of 36 gram. When the soil was dried,

    its volume and mass were 13,5 cm3 and 25 gram. Determine the shrinkage limit for the soil.

    Answer:

    Known:

    m1 = 36 gram

    m2 = 25 gram

    v1 = 19,65 cm3

    v2 = 13,5 cm3

    w = 1gr/cm3

    Asked:

    Shrinkage Limit (SL)?

    Solved:

    = 1 2

    2

    1 2 2

    100%

    = 36 25

    25

    19,65 13,5 . 1

    25 100%

    = 11

    25

    6,15

    25 100%

    = 4,85

    25 100%

    = 0,194 100%

    = 19,4%

  • 3. The sieves analysis of ten soils and the LL and PL of the fraction passing a No. 40 sieves

    are:

    Soil No Sieves Analysis (% finer)

    LL PL No. 10 No. 40 No. 200

    1 98 80 50 38 29

    2 100 92 80 56 23

    3 100 88 65 37 22

    4 85 55 45 28 20

    5 92 75 62 43 28

    6 97 60 30 25 16

    7 100 55 8 NP

    8 94 80 63 40 21

    9 83 48 20 20 15

    10 100 92 86 70 38

    Answer:

    a. Analisis Sampel 1

    Lolos ayakan No. 200 = 50% (termasuk Finer grained Soils)

    Liquid Limit (LL) = 38 (< 50 )

    Kerikil (gravel) = 100 98 = 2 (2%)

    Pasir (sand) = 98 50 = 48 ( 48%)

    Gravel < sand

  • Diagram Klasifikasi

    b. Analisis sampel 2

    Lolos ayakan No. 200 = 80 (80%) (termasuk Finer grained Soils)

    Liquid Limit (LL) = 56

    Kerikil (gravel) = (0%)

    Pasir (Sand) = 100 80 = 20 (20%)

    Gravel < sand

    Plasticity chart (CH)

  • Diagram Klasifikasi

    c. Analisis sampel 3

    Lolos ayakan No. 200 = 65 (65%) (termasuk Finer grained Soils)

    Liquid Limit (LL) = 37

    Kerikil (gravel) = 100 100 = 0 (0%)

    Pasir (sand) = 100 37 = 63 (63%)

    Gravel < sand

    Plasticity Chart (CL)

  • Diagram Klasifikasi

    d. Analisis sampel 4

    Lolos ayakan No. 200 = 45%

    Kerikil (gravel) = 100 85 = 15 %

    Pasir (sand) = 85 45 = 40%

    Gravel < sand

    Plasticity Chart ( CL)

  • Diagram Klasifikasi

    e. Analisis sampel 5

    Lolos ayakan No. 200 = 62 (62%) (termasuk Finer grained Soils)

    Liquid Limit (LL) = 43

    Kerikil (gravel) = 100 92 = 8 (8%)

    Pasir (sand) = 92 62 = 30 (30%)

    Gravel < sand

    Plasticity Chart ( ML)

  • Diagram Klasifikasi

    f. Analisis sampel 6

    Lolos ayakan No. 200 = 30 (30%)

    Kerikil (gravel) = 100 97 = 3 (3%)

    Pasir (sand) = 97 30 = 67 (67%)

    Gravel < sand

    Plasticy Chart (CL)

  • 010

    20

    30

    40

    50

    60

    70

    80

    90

    100

    0.0010.010.11

    Diagram Klasifikasi (USCS)

    g. Analisis sampel 7

    Lolos ayakan nomor 200 = 8%

    Kerikil (gravel ) = 0%

    Pasir (sand ) = 8%

    Penentuan cu dan cc :

  • Cu = 30

    2

    1060 =

    0,182

    0,080,46 = 0,88

    Cc = 60

    10 =

    0,46

    0,08 = 5,75

    LL dan PP tidak diketahui yang berarti gradasi buruk

    Diagram Klasifikasi (USCS)

    h. Analisis sampel 8

    Analisis nomor 8

    Lolos ayakan No. 200 = 63 (63%) (termasuk Finer grained Soils)

    Liquid Limit (LL) = 40

    Kerikil (gravel) = 100 94 = 6 (6%)

    Pasir (sand) = 94 63 = 31 (31%)

    Gravel < sand

    Plasticy Chart (CL)

  • Diagram Klasifikasi (USCS)

  • i. Analisis sampel 9

    Lolos ayakan nomor 200 = 20%

    Kerikil ( Gravel ) = 100 83 = 17%

    Pasir (sand) = 83 20 = 63%

    Plasticity Chart (CL +ML)

    Diagram Klasifikasi

  • j. Analisis sampel 10

    Lolos ayakan No. 200 = 86 (86%) (termasuk Finer grained Soils)

    Liquid Limit (LL) = 70

    Kerikil (gravel) = 100 100 = 0 (0%)

    Pasir (sand) = 100 86 = 14 (14%)

    Gravel < sand

    Plasticity Chart

    Diagram Klasifikasi (USCS)

  • Tabel Penamaan Sampel

    Sample No Group Symbol Group Name

    1 CL-ML Sandy Silty Clay

    2 CH Fat Clay With Sand

    3 CL Sandy Lean Clay

    4 CL or CH Clay sand with Gravel

    5 ML Sandy Silt

    6 SC Clayey Sand

    7 SP-SM Poorly-graded sand with silt

    8 CL Sandy lean Clay

    9 SC-SM Silty, clayey, sand With Gravel

    10 MH Elastic Silt

  • tugas 5

    MEKANIKA TANAH

    Atterberg Limit

    oleh:

    Fauzi Syaiful Adam

    (D621 13 320)

    PROGRAM STUDI TEKNIK PERTAMBANGAN

    JURUSAN GEOLOGI

    FAKULTAS TEKNIK

    UNIVERSITAS HASANUDDIN

    GOWA

    2015