review chapter 7 algebra ii jeopardy jeopardy review
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ReviewReviewChapter 7 Algebra II
JEOPARDY
Jeopardy Review
LogarithmsExponential Growth and
Decay
ExponentialFunctions
Solving Solving LogarithmicLogarithmicEquationsEquations
Solving Solving ExponentialExponentialEquationsEquations
200 200 200 200 200
400 400 400 400 400
600 600 600 600 600
800 800 800 800 800
1000 1000 1000 1000 1000
Logarithms200
log3 (1/9) =
A: -2
Jeopardy Review
Logarithms 400
A: -3
log .001
Jeopardy Review
Logarithms 600
A: 1.699
Use the change of base formula to evaluate: log6 21
Jeopardy Review
Jeopardy Review
Logarithms800
A: 2 log x + log y – log z
Jeopardy Review
Using the properties of logarithms, expand log (x2y/z)
Logarithms1000
A: log (m4n2/k3)
Write as a single logarithm:
y = 4 log m + 2 log n – 3 log k
S2C13 Jeopardy Review
Exponential Growth & Decay
200
A: 52%
Identify the percent of decay in the equation: y = 6000 (.48)x
S2C13 Jeopardy Review
Exponential Growth & Decay
400
A: y = 22,000 (1.06)x
Write the equation that models exponential growth of 6% per year with a starting population of 22,000.
S2C13 Jeopardy Review
Exponential Growth & Decay
600
A: 2.62 million
Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990.
S2C13 Jeopardy Review
Exponential Growth & Decay
800
A: 2022
A city’s population is modeled by the equation
y = 14,000 (.98)x, where x represents the number of years after the year 2000. Predict during which year the population will decrease to 8,900.
S2C13 Jeopardy Review
Exponential Growth & Decay
1000
A: a) growth b) 2.58 c) 158%
In the equation: y = 13 (2.58)x, Identify
a) Growth or decay
b) Growth or decay factor
c) Percent of growth or decay
S2C13 Jeopardy Review
Exponential Functions 200
A: y = ½, 1, and 4
Evaluate y = 2x for x = -1, 0, and 2.
S2C13 Jeopardy Review
Exponential Functions 400
A: y = (7/16)(2)x
Write the equation to describe the exponential function with a base of 2, passing through the point (4,7).
S2C13 Jeopardy Review
Exponential Functions 600
A: 20,000 e^(.06*5) = $26,977.18
Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously.
S2C13 Jeopardy Review
Exponential Functions800
A: 3000 e (.05)(3) = $3485.50
Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously.
S2C13 Jeopardy Review
Exponential Functions 1000
A: 2500 = 2000 e (.03t) t = 7.44 years
You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500?
S2C13 Jeopardy Review
Solving Logarithmic Equations
200
A: log28 = 3
2 log24 – log22 =
S2C13 Jeopardy Review
Solving Logarithmic Equations
400
A: 1
log9 √81
S2C13 Jeopardy Review
Solving Logarithmic Equations
600
A: 102 = 5x x = 20
Solve for x.
log 5x = 2
S2C13 Jeopardy Review
Solving Logarithmic Equations
800
A: ln (3x/2) = 6 x = 268.953
Solve for x.
ln 3 + ln x – ln 2 = 6
S2C13 Jeopardy Review
Solving Logarithmic Equations
1000
A: ln (x2 + 3x) = 2 x = 1.6, using quadratic formula
ln x + ln (x + 3) = 2
S2C13 Jeopardy Review
Solving Exponential Equations
200
A: 7 or -7
x2 = 49
S2C13 Jeopardy Review
Solving Exponential Equations
400
A: x = 11.18
4x⅔ = 20
S2C13 Jeopardy Review
Solving Exponential Equations
600
A: x = 2.096
3x – 4 = 6
S2C13 Jeopardy Review
Solving Exponential Equations
800
A: m = 16
4√m3 + 2 = 10
S2C13 Jeopardy Review
e4x = 10
Solving Exponential Equations
1000
A: 4x = ln 10 x = .576S2C13 Jeopardy Review
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