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Revie Revie w w Chapter 7 Algebra II JEOPARDY Jeopardy Review

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Page 1: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

ReviewReviewChapter 7 Algebra II

JEOPARDY

Jeopardy Review

Page 2: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

LogarithmsExponential Growth and

Decay

ExponentialFunctions

Solving Solving LogarithmicLogarithmicEquationsEquations

Solving Solving ExponentialExponentialEquationsEquations

200 200 200 200 200

400 400 400 400 400

600 600 600 600 600

800 800 800 800 800

1000 1000 1000 1000 1000

Page 3: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Logarithms200

log3 (1/9) =

A: -2

Jeopardy Review

Page 4: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Logarithms 400

A: -3

log .001

Jeopardy Review

Page 5: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Logarithms 600

A: 1.699

Use the change of base formula to evaluate: log6 21

Jeopardy Review

Page 6: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Jeopardy Review

Page 7: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Logarithms800

A: 2 log x + log y – log z

Jeopardy Review

Using the properties of logarithms, expand log (x2y/z)

Page 8: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Logarithms1000

A: log (m4n2/k3)

Write as a single logarithm:

y = 4 log m + 2 log n – 3 log k

S2C13 Jeopardy Review

Page 9: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Growth & Decay

200

A: 52%

Identify the percent of decay in the equation: y = 6000 (.48)x

S2C13 Jeopardy Review

Page 10: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Growth & Decay

400

A: y = 22,000 (1.06)x

Write the equation that models exponential growth of 6% per year with a starting population of 22,000.

S2C13 Jeopardy Review

Page 11: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Growth & Decay

600

A: 2.62 million

Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990.

S2C13 Jeopardy Review

Page 12: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Growth & Decay

800

A: 2022

A city’s population is modeled by the equation

y = 14,000 (.98)x, where x represents the number of years after the year 2000. Predict during which year the population will decrease to 8,900.

S2C13 Jeopardy Review

Page 13: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Growth & Decay

1000

A: a) growth b) 2.58 c) 158%

In the equation: y = 13 (2.58)x, Identify

a) Growth or decay

b) Growth or decay factor

c) Percent of growth or decay

S2C13 Jeopardy Review

Page 14: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Functions 200

A: y = ½, 1, and 4

Evaluate y = 2x for x = -1, 0, and 2.

S2C13 Jeopardy Review

Page 15: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Functions 400

A: y = (7/16)(2)x

Write the equation to describe the exponential function with a base of 2, passing through the point (4,7).

S2C13 Jeopardy Review

Page 16: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Functions 600

A: 20,000 e^(.06*5) = $26,977.18

Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously.

S2C13 Jeopardy Review

Page 17: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Functions800

A: 3000 e (.05)(3) = $3485.50

Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously.

S2C13 Jeopardy Review

Page 18: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Exponential Functions 1000

A: 2500 = 2000 e (.03t) t = 7.44 years

You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500?

S2C13 Jeopardy Review

Page 19: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Logarithmic Equations

200

A: log28 = 3

2 log24 – log22 =

S2C13 Jeopardy Review

Page 20: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Logarithmic Equations

400

A: 1

log9 √81

S2C13 Jeopardy Review

Page 21: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Logarithmic Equations

600

A: 102 = 5x x = 20

Solve for x.

log 5x = 2

S2C13 Jeopardy Review

Page 22: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Logarithmic Equations

800

A: ln (3x/2) = 6 x = 268.953

Solve for x.

ln 3 + ln x – ln 2 = 6

S2C13 Jeopardy Review

Page 23: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Logarithmic Equations

1000

A: ln (x2 + 3x) = 2 x = 1.6, using quadratic formula

ln x + ln (x + 3) = 2

S2C13 Jeopardy Review

Page 24: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Exponential Equations

200

A: 7 or -7

x2 = 49

S2C13 Jeopardy Review

Page 25: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Exponential Equations

400

A: x = 11.18

4x⅔ = 20

S2C13 Jeopardy Review

Page 26: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Exponential Equations

600

A: x = 2.096

3x – 4 = 6

S2C13 Jeopardy Review

Page 27: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review
Page 28: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

Solving Exponential Equations

800

A: m = 16

4√m3 + 2 = 10

S2C13 Jeopardy Review

Page 29: Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

e4x = 10

Solving Exponential Equations

1000

A: 4x = ln 10 x = .576S2C13 Jeopardy Review