lab-2-mạch-tổ-hợp
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B mn K thut my tnh Khoa Khoa hc v K thut my tnh 8
BI TN 02: MCH T HP I. Mc ch bi th nghim
- Kho st cc cng logic nand, nor. - Bin i mch ch s dng cng nand. - Tng cng k nng rp mch. - Thit k, lp rp cc mch t hp.
II. Ni dung chun b trc - S chn, hot ng ca cc IC 74LS00, 74LS02 - Chun b phn l thuyt cc bi o s 3, 4, 5, 6.
III. Bi o Bi o s 1: kho st IC 74LS00
Tra datasheet, ni dy cp ngun cho IC 74LS00.
Ni mch cho cng th nht nh hnh sau:
1
23
SW_0L
SW_1
Gt cc cng tc ln xung thay i gi tr input. Quan st LED.
Kho st tng t vi 3 cng cn li, in kt qu thu c vo bng sau:
SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L0 0 0 0 0 0 0 00 1 0 1 0 1 0 11 0 1 0 1 0 1 01 1 1 1 1 1 1 1
Cng 4 (13,12 -11)Cng 1 (1,2 - 3) Cng 2 (4,5 - 6) Cng 3 (10,9 - 8)
Kt lun v tnh trng IC kho st:
- S lng cng logic b hng:...................... - S th t cc cng logic b hng: ...............
Bi o s 2: kho st IC 74LS02 Kho st tng t nh kho st cho IC 74LS02. in kt qu vo bng sau: Sinh vin lu th t chn ca IC 74LS02.
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B mn K thut my tnh Khoa Khoa hc v K thut my tnh 9
SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L0 0 0 0 0 0 0 00 1 0 1 0 1 0 11 0 1 0 1 0 1 01 1 1 1 1 1 1 1
Cng 4 (11,12 -13)Cng 1 (2,3 - 1) Cng 2 (5,6 - 4) Cng 3 (8,9 - 10)
Kt lun v tnh trng IC kho st:
- S lng cng logic b hng:...................... - S th t cc cng logic b hng: ...............
Bi o s 3: kho st mch Cho mch nh hnh v.
F
1
23
4
56
9
108
C
B
A
F = ...............................................
Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng ra v in kt qu thc nghim vo bng sau:
C B A F(l thuyt)F
(thc nghim)0 0 00 0 10 1 00 1 11 0 01 0 11 1 01 1 1
Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).
Bi o s 4: kho st mch Cho mch nh hnh v.
5
64
2
31
C
A
F8
910
B
F = ...............................................
Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng
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B mn K thut my tnh Khoa Khoa hc v K thut my tnh 10
ra v in kt qu vo bng sau:
C B A F(l thuyt)F
(thc nghim)0 0 00 0 10 1 00 1 11 0 01 0 11 1 01 1 1
Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).
Bi o s 5: kho st mch Cho mch nh hnh v:
F1
23 1 2
C
A
B
1
23
F = ...............................................
Sinh vin bin i tng ng mch trn thnh mch ch s dng cng nand hai ng nhp.
F = ..............................................
Mch
Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng ra v in kt qu thc nghim vo bng sau:
C B A F(l thuyt)F
(thc nghim)F'
(l thuyt)F'
(thc nghim)0 0 00 0 10 1 00 1 11 0 01 0 11 1 01 1 1
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B mn K thut my tnh Khoa Khoa hc v K thut my tnh 11
Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).
Bi o s 6: kho st mch Cho mch nh hnh v:
9
108
1 2
A
B1
23
3 4D
1
23
4
56
F
12
1311
2
31
5
64
C
1
23
F = ...............................................
Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng ra v in kt qu vo bng sau:
D C B A F(l thuyt)F
(thc nghim)0 0 0 00 0 0 10 0 1 00 0 1 10 1 0 00 1 0 10 1 1 00 1 1 11 0 0 01 0 0 11 0 1 01 0 1 11 1 0 01 1 0 11 1 1 01 1 1 1
Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).
Bi o s 7: thit k mch Sinh vin thit k v rp mch 4 bin F = f(D, C, B, A) vi D l MSB theo hai phng php
tng cc tch v tch cc tng
+= )14 ,13 , 11 ,8 ,4 ,0( )15 ,10 ,5 ,2 ,1( dmF Ba Karnaugh:
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B mn K thut my tnh Khoa Khoa hc v K thut my tnh 12
00 01 11 10 00 01 11 1000 0001 0111 1110 10
BA
DC
BA
DC
Ftich = ........................................... Ftong = ...............................................
Mch:
in kt qu tnh ton trn l thuyt v kt qu thc nghim vo bng sau:
D C B A F(l thuyt)Ftich
(thc nghim)Ftong
(thc nghim)0 0 0 00 0 0 10 0 1 00 0 1 10 1 0 00 1 0 10 1 1 00 1 1 11 0 0 01 0 0 11 0 1 01 0 1 11 1 0 01 1 0 11 1 1 01 1 1 1
Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).
IV. Bi tp lm thm Bi o s 1: thit k mch bo ng xe hi
Tng cc tch Tch cc tng
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B mn K thut my tnh Khoa Khoa hc v K thut my tnh 13
Thit k mch bo ng dng trong xe hi. Mch gm c nm u vo t cc cm bin, vi cc k hiu v quy nh nh sau:
- A = 1 khi bt cng tc in n my - B = 1 khi ti x ngi vo xe - C = 1 khi hnh khch ngi vo xe - D = 1 khi ti x gi dy an tong - E = 1 khi hnh khch gi dy an ton
Mch bo ng (F = 0) khi xe n my m ti x hoc hnh khch ngi vo xe nhng cha gi dy an ton.
Sinh vin lp bng thc tr, rt gn. Sau bin i c th rp mch ch bng cc IC kho st, rp mch v so snh kt qu thc nghim vi kt qu tnh ton l thuyt.
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