B mn K thut my tnh Khoa Khoa hc v K thut my tnh 8

BI TN 02: MCH T HP I. Mc ch bi th nghim

- Kho st cc cng logic nand, nor. - Bin i mch ch s dng cng nand. - Tng cng k nng rp mch. - Thit k, lp rp cc mch t hp.

II. Ni dung chun b trc - S chn, hot ng ca cc IC 74LS00, 74LS02 - Chun b phn l thuyt cc bi o s 3, 4, 5, 6.

III. Bi o Bi o s 1: kho st IC 74LS00

Tra datasheet, ni dy cp ngun cho IC 74LS00.

Ni mch cho cng th nht nh hnh sau:

1

23

SW_0L

SW_1

Gt cc cng tc ln xung thay i gi tr input. Quan st LED.

Kho st tng t vi 3 cng cn li, in kt qu thu c vo bng sau:

SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L0 0 0 0 0 0 0 00 1 0 1 0 1 0 11 0 1 0 1 0 1 01 1 1 1 1 1 1 1

Cng 4 (13,12 -11)Cng 1 (1,2 - 3) Cng 2 (4,5 - 6) Cng 3 (10,9 - 8)

Kt lun v tnh trng IC kho st:

- S lng cng logic b hng:...................... - S th t cc cng logic b hng: ...............

Bi o s 2: kho st IC 74LS02 Kho st tng t nh kho st cho IC 74LS02. in kt qu vo bng sau: Sinh vin lu th t chn ca IC 74LS02.

B mn K thut my tnh Khoa Khoa hc v K thut my tnh 9

SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L SW_0 SW_1 L0 0 0 0 0 0 0 00 1 0 1 0 1 0 11 0 1 0 1 0 1 01 1 1 1 1 1 1 1

Cng 4 (11,12 -13)Cng 1 (2,3 - 1) Cng 2 (5,6 - 4) Cng 3 (8,9 - 10)

Kt lun v tnh trng IC kho st:

- S lng cng logic b hng:...................... - S th t cc cng logic b hng: ...............

Bi o s 3: kho st mch Cho mch nh hnh v.

F

1

23

4

56

9

108

C

B

A

F = ...............................................

Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng ra v in kt qu thc nghim vo bng sau:

C B A F(l thuyt)F

(thc nghim)0 0 00 0 10 1 00 1 11 0 01 0 11 1 01 1 1

Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).

Bi o s 4: kho st mch Cho mch nh hnh v.

5

64

2

31

C

A

F8

910

B

F = ...............................................

Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng

B mn K thut my tnh Khoa Khoa hc v K thut my tnh 10

ra v in kt qu vo bng sau:

C B A F(l thuyt)F

(thc nghim)0 0 00 0 10 1 00 1 11 0 01 0 11 1 01 1 1

Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).

Bi o s 5: kho st mch Cho mch nh hnh v:

F1

23 1 2

C

A

B

1

23

F = ...............................................

Sinh vin bin i tng ng mch trn thnh mch ch s dng cng nand hai ng nhp.

F = ..............................................

Mch

Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng ra v in kt qu thc nghim vo bng sau:

C B A F(l thuyt)F

(thc nghim)F'

(l thuyt)F'

(thc nghim)0 0 00 0 10 1 00 1 11 0 01 0 11 1 01 1 1

B mn K thut my tnh Khoa Khoa hc v K thut my tnh 11

Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).

Bi o s 6: kho st mch Cho mch nh hnh v:

9

108

1 2

A

B1

23

3 4D

1

23

4

56

F

12

1311

2

31

5

64

C

1

23

F = ...............................................

Sinh vin in bng thc tr cho mch. Sau rp mch, thay i d liu u vo, quan st ng ra v in kt qu vo bng sau:

D C B A F(l thuyt)F

(thc nghim)0 0 0 00 0 0 10 0 1 00 0 1 10 1 0 00 1 0 10 1 1 00 1 1 11 0 0 01 0 0 11 0 1 01 0 1 11 1 0 01 1 0 11 1 1 01 1 1 1

Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).

Bi o s 7: thit k mch Sinh vin thit k v rp mch 4 bin F = f(D, C, B, A) vi D l MSB theo hai phng php

tng cc tch v tch cc tng

+= )14 ,13 , 11 ,8 ,4 ,0( )15 ,10 ,5 ,2 ,1( dmF Ba Karnaugh:

B mn K thut my tnh Khoa Khoa hc v K thut my tnh 12

00 01 11 10 00 01 11 1000 0001 0111 1110 10

BA

DC

BA

DC

Ftich = ........................................... Ftong = ...............................................

Mch:

in kt qu tnh ton trn l thuyt v kt qu thc nghim vo bng sau:

D C B A F(l thuyt)Ftich

(thc nghim)Ftong

(thc nghim)0 0 0 00 0 0 10 0 1 00 0 1 10 1 0 00 1 0 10 1 1 00 1 1 11 0 0 01 0 0 11 0 1 01 0 1 11 1 0 01 1 0 11 1 1 01 1 1 1

Gii thch v khc phc nguyn nhn dn ti s khc bit (nu c).

IV. Bi tp lm thm Bi o s 1: thit k mch bo ng xe hi

Tng cc tch Tch cc tng

B mn K thut my tnh Khoa Khoa hc v K thut my tnh 13

Thit k mch bo ng dng trong xe hi. Mch gm c nm u vo t cc cm bin, vi cc k hiu v quy nh nh sau:

- A = 1 khi bt cng tc in n my - B = 1 khi ti x ngi vo xe - C = 1 khi hnh khch ngi vo xe - D = 1 khi ti x gi dy an tong - E = 1 khi hnh khch gi dy an ton

Mch bo ng (F = 0) khi xe n my m ti x hoc hnh khch ngi vo xe nhng cha gi dy an ton.

Sinh vin lp bng thc tr, rt gn. Sau bin i c th rp mch ch bng cc IC kho st, rp mch v so snh kt qu thc nghim vi kt qu tnh ton l thuyt.