all rights reservedl. manevitz lecture 41 artificial intelligence logic l. manevitz

All rights reserved L. Manevitz Lecture 4 1

Artificial IntelligenceLogic

L. Manevitz


Logic - Advantages

• Pretty universal – (need to choose the correct language).

• Clear semantics– Interpretation.– Intended Interpretation.

• Uniform Method of Manipulating– Theorem proving via Resolution.– Green’s Trick for answer production.


Representing Information

Formulas Formulas

Semanticconnection

Formal connection

RepresentationInterpretation


Basic Concept

Let be a set of formulas.

Let φ be a specific formula.

When does φ logically follow from ?

Meaning : in every possible interpretation where is true then φ is true.

Notationally : φ

( “semantically implies φ).


Syntax

• Language:– Logical symbols.– Relation symbols.– Function symbols.– Constant symbols.

• Terms – recursive.• Formulas – recursive.• Sentences – no free variables.


Semantics - Interpretation

θ= <A|R1,R2,..,Ri,F1,F2,..,Fk,C1,C2,..,Cl>

Ri AxAx..xA

Fk : AxAx..xA A

Cl A

θ θ θ θ θ θ θ θ θ

θ

θ

θ


Semantics

• To handle variables, we extend the notion of satisfaction to include variables

(explain on blackboard)


How to work with

• Basic semantic equivalents :– (e.g. De Morgan’s Laws, Assoc. Laws,

Distr. Laws).

• Fundamental Problem :– Find mechanical procedure to test if

φ or not.


Abstraction of Proof - φ

• Intuitive: φ1

φ2

φn = φ

• Example: “Acceptable Rule”

φ ψ (MP)

Where φi or

φi follows from {φj | j<i}

By “acceptable” rule

φψ


Definitions

• A system S is consistent if whenever φ then φ.

• A system S is complete if whenever φ then φ.

s

s


Theorem

• Completeness Theorem:

There is a system S

s.t. φ φ


Example

• Trivially complete

where A is any formula.

• Sound Rule: (MP)

A

A BAB


What kind of systems ?

• Mimic People (“Natural Deduction”).

• Mimic Mathematical Proof.

• Convenient for Computers.


Proof Systems

“Natural Deduction”

Formal Computationale.g. Resolution

Completeness Theorem


Control

DATA

Set of formulas

Rules of Deduction

What rule to apply to what ?


Resolution System (Syntax)Sound Rule

• Basic Idea:

(φ1 … φn) ( φ1 ψ1 … ψm)

φ2 … φn ψ1 … ψm


Semantic Equivalents

• We can check this, now that we have a definition of truth in interpretations.

• Example ~(~p) is equivalent to p


Semantic Equivalents

• ( A) A

• A B A B

• A B B A

• A B (A B) (B A)

• Associative :– A (B C) (A B) C– A (B C) (A B) C


Semantic Equivalents cont.

• Commutative:– A B B A– A B B A

• Distributive:– A (B C) (A B) (A C)– A (B C) (A B) (A C)


Semantic Equivalents cont.

• De Morgan:– (A B) ( A) ( B)– (A B) ( A) ( B)


Quantifier Equivalences

• De Morgan:• (( x)A(x)) ( x) A(x)• (( x)A(x)) ( x) A(x)

• x A(x) y A(y)• x A(x) y A(y)

• x [P(x) Q(x)] ( x P(x)) ( x Q(x))• x [P(x) Q(x)] ( x P(x)) ( x Q(x))


Resolution (Predicate) S

• Convert to set of clauses.• Convert S to set of clauses.• Let Clauses := all the above clauses.• Repeat until NIL found :

– Select two clauses.

– Resolve (using Unification).

– Check result :• If result is NIL finish.

• Otherwise add result to Clauses


Over all Procedure

1. Eliminate , .

2. Push to atomic.

3. Eliminate .

4. Rename variables in a formula.

5. Move quantifier to the left.


Over all Procedure

6. Push down.

7. Eliminate conj. - By making separate formulas.

8. Rename variables in all formulas.

9. Eliminate - Convention.


Example

• [ x (A(x) B(x)] [ y C(y)]

• [ x (A(x) B(x)] [ y C(y)]

• [ x (A(x) B(x)] [ y C(y)]

• [ x ( A(x) B(x)] [ y C(y)]

• A(a) B(a) y C(y)

• y [ A(a) B(a) C(y)]

• Get Clause [ A(a) B(a) C(y)]

To replace add a constant to language.


- Elimination example

• x y Boss (y,x)– Problem:

• Constant not sufficient.

• y depends on x.

– Solution:• Add a new function symbol f().

• x Boss (f(x),x)


Example

1. x [Brick(x) [ y[On(x,y) Pyramid(y)] y[On(x,y) On(y,x)]

y[ Brick(y) Equal(x,y)]]]

2. x [ Brick(x) [ y[On(x,y) Pyramid(y)] y[On(x,y) On(y,x)]

y[ ( Brick(y)) Equal(x,y)]]]

Eliminate

Push


Example cont.

3. x [ Brick(x) [ y[On(x,y) Pyramid(y)] y[ On(x,y) On(y,x)] y[Brick(y) Equal(x,y)]]]

4. x [ Brick(x) [[On(x,support(x)) Pyramid(support(x))]

y[ On(x,y) On(y,x)] y[Brick(y)

Equal(x,y)]]]

Eliminate

Rename variables apart


Example cont.

5. x [ Brick(x) [[On(x,support(x)) Pyramid(support(x))]

y[ On(x,y) On(y,x)] z[Brick(z) Equal(x,z)]]]

6. x y z [ Brick(x) [[On(x,support(x)) Pyramid(support(x))]

[ On(x,y) On(y,x)] [Brick(z)

Equal(x,z)]]]

Move to left

Push down


Example cont.

7. x y z [ Brick(x) [On(x,support(x)) Pyramid(support(x))]]

[ Brick(x) On(x,y) On(y,x)] [ Brick(x) Brick(z) Equal(x,z)]]


Example cont.

8. x y z [[ Brick(x) On(x,support(x))] [ Brick(x)

Pyramid(support(x))] [ Brick(x) On(x,y) On(y,x)]

[ Brick(x) Brick(z) Equal(x,z)]]Eliminate

conj.


Example cont.

9. x [ Brick(x) On(x,support(x))] x [ Brick(x) Pyramid(support(x))] x y [ Brick(x) On(x,y) On(y,x)] x z [ Brick(x) Brick(z) Equal(x,z)]

Rename variables


Example cont.

10. x [ Brick(x) On(x,support(x))] w [ Brick(w) Pyramid(support(w))] u y [ Brick(u) On(u,y) On(y,u)] v z [ Brick(v) Brick(z) Equal(v,z)]

Eliminate


Example cont.

• Clause form:

Brick(x) On(x,support(x)) Brick(w)

Pyramid(support(w)) Brick(u) On(u,y) On(y,u) Brick(v) Brick(z) Equal(v,z)

all rights reservedl. manevitz lecture 41 artificial intelligence logic l. manevitz

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