7.1-7.3 2/1/13 this powerpoint will assist you with the packet

7
7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

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Page 1: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

7.1-7.32/1/13

This PowerPoint will assist you with the packet

Page 2: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

Bell Work

Warm UpSolve each proportion.

1. 2. 3.

4. If ∆QRS ~ ∆XYZ, identify the pairs of congruent angles and write

3 proportions using pairs of corresponding sides.

z = ±10

Q X; R Y; S Z;

x = 8

Page 3: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

7.1

1. There are 182 girls in the sophomore class of 305 students. What is the ratio of girls to total students?

182305

2. The ratio of the measures of the sides of a triangle is 3:4:6, and its perimeter is 104 feet. Find the measure of each side of the triangle.

24 ft, 32ft, 48ft

3. The ratio of the measures of the sides of a triangle is 7:9:12, and its perimeter is 84 ft. Find the measure of each side of the triangle.

21 in, 27in, 36 in

4. 5 = x 8 12 X = 7.5

Page 4: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

7.21. Determine whether the polygons are similar. If so,

write the similarity ratio and a similarity statement.

2. The ratio of a model sailboat’s dimensions to the

actual boat’s dimensions is . If the length of the

model is 10 inches, what is the length of the

actual sailboat in feet?

no

25 ft

Page 5: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

7.2

Determine if ∆JLM ~ ∆NPS. If so, write the similarity ratio and a similarity statement.

Step 1 Identify pairs of congruent angles.

N M, L P, S J

Step 2 Compare corresponding sides.

Thus the similarity ratio is , and ∆LMJ ~ ∆PNS.

Page 6: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

7.3

1. Explain why the triangles are

similar and write a similarity

statement.

2. Explain why the triangles are

similar, then find BE and CD.

Page 7: 7.1-7.3 2/1/13 This PowerPoint will assist you with the packet

answers

1. By the Isosc. ∆ Thm., A C, so by the def. of , mC = mA. Thus mC = 70° by subst. By the ∆ Sum Thm., mB = 40°. Apply the Isosc. ∆ Thm. and the ∆ Sum Thm. to ∆PQR. mR = mP = 70°. So by the def. of , A P, and C R. Therefore ∆ABC ~ ∆PQR by AA ~.

2. A A by the Reflex. Prop. of . Since BE || CD, ABE ACD by the Corr. s Post. Therefore ∆ABE ~ ∆ACD by AA ~. BE = 4 and CD = 10.