6-2 ellipses (presentation)

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    6-2 Ellipses

    Unit 6 Conic Sections

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    Concepts and Objectives

    Ellipses (Obj. 20)

    Identify the equation of an ellipse Find the center,x-radius, andy-radius of an ellipse

    Find the major and minor axes

    Find the foci and focal length of an ellipse Write the equation of an ellipse

    Solve problems involving ellipses

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    Ellipses

    An ellipse, geometrically speaking, is a set of points in a

    plane such that for each point, the sum of its distances,d1 + d2, from two fixed points F1 and F2, is constant.

    What does this mean?

    .

    Place the two pins at least 3" apart.

    Tie your piece of string in a loop that will fit around

    the pins without going off the edge.

    Put the loop around the pins, pull it taut, and trace

    around the loop.

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    Parts of an Ellipse

    Parts of an ellipse:

    Center Vertices (ea. vertex)

    Major axis

    Minor axis Foci (ea. focus)

    What we have done with the string is kept the distancebetween the foci and the points on the ellipse constant

    (i.e. the definition).

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    Parts of an Ellipse

    Other important parts:

    The semi-majorand semi-minoraxes are half thelength of the major and minor axes.

    The distance from the center to the ellipse in thex-

    - . ,

    in they-direction is called they-radius.

    The distance between the foci is called thefocal

    length. The distance between the center and a focus

    is called thefocal radius.

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    Ellipses

    Generally speaking,

    a is the length of the semi-major axis b is the length of the semi-minor axis

    c is the length of the focal radius.

    Therefore,

    The length of the major axis is 2a

    The length of the minor axis is 2b The sum of the distances from a point(x,y) to a point

    on the ellipse is 2a

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    Focal Radius

    Not only does the dotted

    line trace the outline of theellipse, but it is also the

    length of the major axis. As

    ou can see from theb

    a

    picture, half of that length(a) is the hypotenuse of the

    triangle formed by the semi-

    minor axis and the focal

    radius. This gives us the

    formula:= 2 2 2c a b

    c

    (careful!)

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    Standard Form

    The standard form of an ellipse centered at(h, k) is

    + =

    22

    1

    x y

    x h y k

    r r

    where rxis thex-radius and ryis they-radius. To graph an ellipse from the standard form, plot the

    center, mark thex- andy-radii, and sketch in the curve.

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    Standard Form

    Example: Sketch the graph of

    + + =

    2 24 11

    3 5

    x y

    The center is at(4, 1)Thex-radius is 3

    They-radius is 5

    Sketch in the curves

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    Standard Form of an Ellipse

    Example: Sketch the graph of

    To sketch the graph, we have to rewrite the equation.+ + + =

    2 24 9 16 90 205 0 x y x y

    + + = 2 24 16 9 90 205 x x y y

    ( ) ( ) ( ) ( ) + + = + + + +2 2 222 24 4 9 10 2052 5 4 2 9 5 x x y y

    ( ) ( ) ++ =

    2 2

    4 2 9 5 36

    36 36 36

    x y

    + + =

    2 2

    2 51

    3 2

    x y( ) ( ) ++ =

    2 2

    2 51

    9 4

    x y

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    Standard Form of an Ellipse

    Example (cont.):

    + + =

    2 2

    2 51

    3 2

    x y

    The center is at(2, 5)Thex-radius is 3

    They-radius is 2

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    Focal Length

    Example: Write the equation of the ellipse having center

    at the origin, foci at(5, 0) and (5, 0), and major axis oflength 18 units.

    , , .

    The distance between the center and a focus, c, is 5.

    Therefore, we can find b using the formula:

    = 2 2 2c a b

    = 2 2 2

    5 9 b= =2 2 29 5 56b

    = 56b

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    Focal Length

    Example (cont.):

    The foci lie along the major axis, so we know thatrx= a.

    Putting it all together, we have:

    + =

    22

    19 56

    x y

    + =2 2

    1

    81 56

    x y

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    Eccentricity The eccentricity of an ellipse is a measure of its

    roundness, and it is the ratio of the focal length to themajor axis.

    This ratio is written as

    =e a

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    Eccentricity Example: The orbit of Jupiter is an ellipse with the sun

    at one focus (mostly). The eccentricity of the ellipse is0.0489, and the maximum distance of Jupiter from the

    sun is 507.4 million miles. Find the closest distance that

    u iter comes to the sun.

    Jupiter

    Sun

    a + c

    a c= 0.0489ca

    = 0.0489c a+ = 507.4

    a c+ =0.0489 507.4a a

    = 507.4

    483.741.0489

    a

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    Eccentricity Example (cont.):

    ( )= 0.0489 483.74c

    = 23.65c

    Jupiter

    Sun

    a + c

    a c

    = . .a c= 460.1 million miles

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    Homework Algebra & Trigonometry(green book)

    Page 476: 3-18 (3s) Turn in: 9, 15

    College Algebra (brown book) Page 968: 15-39 (3s), 45, 47a, 48

    Turn in: 18, 24, 47, 48