4.1.1 example single

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Page 1: 4.1.1 Example Single
Page 2: 4.1.1 Example Single
Page 3: 4.1.1 Example Single
Page 4: 4.1.1 Example Single
Page 5: 4.1.1 Example Single

21 x lighting points12 x double 10 A socket-outlets 1 x 15 A socket-outlet 1 x 230 V, 6.0 kW oven 1 x 230 V, 2.4 kW instantaneous water heater

Page 6: 4.1.1 Example Single
Page 7: 4.1.1 Example Single
Page 8: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 9: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 10: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 11: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 12: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 13: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 14: 4.1.1 Example Single

LoadGroup(column 1)

Description of load(given list)

Current allowanceper unit(column 2)

Calculation Demand current(Amps)

A (i) 21 lighting points

3 A 3 + 2 5.0

B (i)12 double outlets(equivalent 24 sockets)

10 A (1st 20)5 A (next 20)

10 + 5 15.0

B (ii) 15 single-phaseoutlets

10 A None 10.0

C Oven rating 50% (or x 0.5)

(6000 / 240) x 0.5

12.5

E InstantaneousHWS

33.3 %(or x 0.33)

(2400 / 240) x 0.33

3.33

Total demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 ATotal demand current = 45.83 A

Page 15: 4.1.1 Example Single