3e math mye 2014 p1 answers.docx
TRANSCRIPT
Marking Scheme Paper 13 Express_MYE_20141(a)36.4 % or B1
(b)
B1
21168.672079
B1B1
3(a)
B1
(b)
= B1B1
4(a)
(change to same base)
B1
B1
(b)
B1
5(a)
and
B1B1
(b) | | | ||||||||-4-3-2-10123456
B1
6(a)18CB1
(b)1 unit ------ 200 m12 units ----2400 mB1B1
7
Sub into eq 1
M1
A1
A1
8(a)
B1
(b)
B1
(c)12B1
9(a)9 km/hB1
(b)1m ------ 0.4 s1m ------ 400 msM1A1
10(a)2 cmB1
(b)
Vol. of small bar(prism) = or 26.7 cm3
M1
A1
11(a)72B1
(b)50 %B1
12(a)8.75 kmB1
(b)
0.512 cm2 ------- 0.8 km2B1
B1
13(a)
M1
A1
(b)
M1
A1
14(a)
B1
(b) or
y= 8 or
y= 812 3/5 = 20
20 x 2/5 = 8M1
A1
15(a)(i)
B1
(ii)
B1
(b)8B1
16(a)
h = 2.5 cmM1
A1
(b)75 %B1
171 unit ----- 30 mins12 units ---- 360 mins = 6 hrsM1A1
18(a)
=
=
M1
A1
(b)
=
=
M1
A1
19(a)
Since AB2 + BC2 = AC2 and it obeys Pythagoras theorem, triangle ABC is a right-angled triangle.
B1
(b)48 cm2B1
20(a)540 105 75 105 = 2552x = 255x = 127.5M1
A1
(b)94 + 110 + 12(n 2) = 36012(n 2) =156n 2 = 13n = 15M1
A1
21(a)7x 5 = 27 12x x 20x = 32x = 1.6M1
A1
(b)p = 0 or -6B1
22(a)
B1
(b)
M1
A1
23(a)
y = 1.35M1
A1
(b)(i)$45(Using graph) or $44.75 (Using equation)B1
(ii)40 kmB1
(c)(i)
[B1]
(c)(ii)3 kmB1
24(a)0 m/s2B1
(b)16 m/sB1
(c)
M1
A1
(d)Correct shape and label on y-axis shown ..B1Correct shape and label on y-axis shown ..B1400100
B1,
B1
25(a) - (c)
5