2_3_series, parallel circuits, voltage and current divider circuits
DESCRIPTION
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01JULY 5, 2011
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY1Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
Kirchhoff’s LawSeries and Parallel CircuitsSeries-Parallel CircuitsVoltage and Current Division
01JULY 5, 2011
Kirchhoff’ Law
1. KVLIn any closed circuits, the algebraic sum of allvoltages is equal to zero.
∑V = 0 or ∑Vrise = ∑Vdrop
2. KCLIn any circuit junction, the algebraic sum of allcurrents is equal to zero.
∑I = 0 or ∑Ientering = ∑Ileaving
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY2Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY3Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Resistance Connections
Series
V
+
-
+ R1 -
+R2
-
+R3
-
I
V = V1 + V2 + V3
I = I1 = I2 = I3
V1
V2
V3
Solving for R
R = R1 + R2 + R3
VI = +V1
I1+V2
I2
V3
I3
Solving for P
P = P1 + P2 + P3
VI = V1I1 + V2I2 + V3I3
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY4Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Parallel
V
+
-
+R1
-
+R2
-
+R3
-
I
Solving for R
IV = +I1
V1+I2
V2
I3
V3
Solving for P
P = P1 + P2 + P3
VI = V1I1 + V2I2 + V3I3
I1I2 I3
V = V1 = V2 = V3
I = I1 + I2 + I3
1R = +1
R1
1R2
+ 1R3
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY5Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY6Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Thank You forlistening!
Let’s discuss Voltage and Current Division...
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY7Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Kirchhoff’s LawSeries and Parallel CircuitsSeries-Parallel CircuitsVoltage and Current Division
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY8Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Voltage Division
From the Series Circuit
V
+
-
+ R1 -
+R2
-
+R3
-
I
V1
V2
V3
I = I1 = I2 = I3
VR = =V1
R1=V2
R2
V3
R3
whereV = supply voltage
V1 , V2, V3 = partial voltage
=V1 V R1
R
=V2 V R2
R
=V3 V R3
R
at this case, total R is
R = R1 + R2 + R3
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY9Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Current Division
From the Parallel Circuit
V
+
-
+R1
-
+R2
-
+R3
-
I
I1I2 I3
V = V1 = V2 = V3
IR = I1R1 = I2R2 = I3R3
whereI = supply current
I1 , I2, I3 = partial current
I1 I= RR1
I2 I= RR2
I3 I= RR3
at this case, total R is
1R = +1
R1+1
R2
1R3
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY10Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
For two branches parallel ciruits
V
+
-
+Ra
-
+Rb
-
I
Ia Ib
=Req Ra + Rb
Ra Rb
from
1Req
= 1Ra
+ 1Rb
to solve for branches currents
IReq = IaRa = IbRb
from
Ia I= ReqRa
I= RbRa + Rb
Ib I= ReqRb
I= RaRa + Rb
For nth common resistance in parallel ciruits
R1 R2 R3 Rn
Req = Rn
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY11Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos
01JULY 5, 2011
Thank You forlistening!
Let’s have sample problems regarding Resistors connected in Series, Parallel,Series-Parallel, Voltage and Current Division...
TOPIC TITLE SY / TERM OF EFFECTIVITY PREPARED BY12Series, Parallel, Series-Parallel Circuits, Voltage and Current Divider Circuits 3rd/ 2013-2014 L. Valcos