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    1

    Michelson I nterferometer

    1

    This instrument can produce both types of interferencefringes i.e., circular fringes of equal inclination at infinity

    and localized fringes of equal thickness

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    INTERFEROMETER

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    Albert Abraham Michelson

    Michelson Interferometer

    (1852-1931)

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    Michelson-Morley Experiment

    In 1878, Michelson thought the detection of motion through the ether might be

    measurable.

    In trying to measure the speed of the Earth through the supposed "ether", you

    could depend upon one component of that velocity being known - the velocity of

    the Earth around the sun, about 30 km/s. Using a wavelength of about 600 nm,

    there should be a shift of about 0.04 fringes as the spectrometer was rotated 360.

    Though small, this was well within Michelson's capability.

    Michelson, and everyone else, was surprised that there was no shift. Michelson's

    terse description of the experiment: "The interpretation of these results is that

    there is no displacement of the interference bands. ... The result of the hypothesis

    of a stationary ether is thus shown to be incorrect." (A. A. Michelson, Am. J. Sci,

    122, 120 (1881))

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    Experimental set up

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    MichelsonInterferometer

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    Michelson

    Interferometer

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    Effective arrangement of the interferometer

    Circular fringesAn observer at the detector looking into B will see M1, a

    reflected image of M2(M2//) and the images Sand Sof the

    source provided by M1and M2. This may be represented by a

    linear configuration.

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    Longitudinal sectionCircular fringes

    P

    O

    rn

    S Sd

    D

    N

    q

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    2 00

    cos

    2( ) 2 ( )

    m

    m

    SP SP SN d m

    m m nn m m

    d d

    q

    q

    Radius of nthbrightring

    For small qm

    22 2 2 2

    n m

    D nr D

    d

    q

    In Youngs double-hole experiment:

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    11

    I nternal ref lectionimplies that the reflection is from an interface to a

    medium of lesser index of refraction.

    External ref lectionimplies that the reflection is from an interface to a

    medium of higher index of refraction.

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    Maxima:0,1,2,...)(m2

    1cos2

    Minima:0,1,2,...)(mcos2

    q

    q

    md

    md

    m

    m

    In Michelson interferometer

    Order of the fringe:

    When the central fringe is dark the order of the fringe is

    dm

    2

    As dis increased new fringes appear at the centre and the existing

    fringes move outwards, and finally move out of the field of view.

    For any value of d, the central fringe has the largest value of m.

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    q md m cos2

    In Michelson interferometer

    For central dark fringe: omd2

    The first dark fringe satisfies: q )1(cos2 md

    q

    )1(2

    12

    2

    md

    For small

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    14

    Radius of n

    th

    darkring:

    dnDDr

    nmmd

    mn

    om

    q

    q

    2

    222

    2 )(

    q )1(2

    12

    2

    md

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    Haidinger Fringe

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    1. Measurement of wavelength of light

    )(md 02 0 q

    md 2

    m

    d

    nmmdd

    2

    2 0

    2 cosd mq

    Move one of the mirrors to a new position dso that the order of thefringe at the centre is changed from moto m.

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    18

    2. Measurement of wavelength separation

    of a doublet (1and1+)

    1112 qpd )(md 02 0 qIf the two fringe patterns coincide at the centre: (Concordance)

    The fringe pattern is very bright

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    Concordance

    112 pd

    1q

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    2. Measurement of wavelength separation

    of a doublet (1and1+)

    1112 qpd )(md 02 0 q

    As dis increasedpand qincrease by different amounts, with

    pq

    )2/1( pqWhen

    the bright fringes of1coincide with the dark fringes of1+, and

    vice-versa and the fringe pattern is washed away (Discordance).

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    Discordance

    112 pd

    = (q+1/2) 1

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    23

    2. Measurement of wavelength separation

    of a doublet (1and1+)

    1112 qpd

    112 12 nqnpd

    1112 12 nndd

    12

    2

    1

    2 dd

    )(md 02 0 q

    -can be measured by increasing d1to d2so that the two sets of fringes,

    initially concordant, become discordant and are finally concordant again.

    - Ifpchanges top+n, and qchanges to q+(n-1)we have concordant fringesagain.

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    Measurement of the coherence length of a spectral lineMeasurement of thickness of thin transparent flakes

    Measurement of refractive index of gases

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    25

    LIGO- Laser Interferometer Gravitational Wave ObservatoryTo detect Gravitational waves, one of the predictions of Einsteins General Theory of Relativity

    Hanford Nuclear Reservation, Washington, Livingston, Louisiana

    Arm length: 4 Km

    Displacement Sensitivity: 10-16cm

    When Gravitational

    waves pass through the

    interferometer they willdisplace the mirrors!

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    26

    Fabry-Perot I nter ferometer

    26

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    Fabry-Perot Interferometer

    30o

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    28

    Multiple Beam Interference

    28

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    Optical Reversibility and

    Phase Changes on Reflection

    G.G. Stokes used the principle of optical

    reversibility to investigate the reflection oflight at an interface between two media.

    The reversibility principlestates that

    If there is no absorption of light, a light ray

    that is reflected or refracted will retrace its

    original path if its direction is reversed.

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    2

    ttr

    rr

    SPK

    rand tare fractional amplitudes reflected and transmitted respectively

    According toprinciple of

    reversibility, the

    combined effect of

    reversing the reflected

    and transmitted beams

    should just be the incidentbeam (in absence of

    absorption).

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    Thin films: multiple beam interference

    SPK

    0

    0 0 0 0

    0

    0

    0 0

    0 0

    0

    0

    0

    0

    0

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    Path difference between rays 2 and 1

    [(OS + SR)(in film)][OM( in air) ]

    = [(PS+ SR)(in film)][OM( in air)]

    = [(PR)(in film)][OM( in air)]

    = (PN + NR)OM

    = (PN) = (OP Cos )

    = 2d cos

    CASE I

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    If 2d cos m= m

    then rays 2,3,4, 5, . are in phaseand 1 out of phase.

    Amplitude of 2+3+4+5 .

    = aotrt(1+ r + r + r +)2 4 6

    = aotrt(1/(1r ))2

    = aotrt(1/tt) = aor= - aor

    CASE - I

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    Amplitude of transmitted beams , , ,

    = aott(1+ r + r + r +)2 4

    6

    = ao

    = aor +(- aor)

    = 0

    Total reflected Amplitude: 1+(2+3+4+)

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    If 2d cos m= (m+1/2) then rays 1,2,4, 6, are in phase

    and 3,5, are out of phase.

    Rays, , in phase and rays , ,

    are out of phase

    CASE - II

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    1 0( )

    2 0

    3 ( 2 )

    3 05 ( 3 )

    4 0

    (2 3) [ ( 1) ]

    0

    .........................

    i t

    R

    i t

    R

    i t

    R

    i t

    R

    N i t N

    NR

    a a re

    a a tr t e

    a a tr t e

    a a tr t e

    a a tr t e

    Optical field in reflected beam

    : is the incident wave;

    is the phase arising from the extra optical path length.

    0

    i ta e

    where

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    Resultant reflected scalar wave

    0 2

    (1 )

    1

    ii t

    R i

    r ea a e

    r e

    2

    1

    r r

    tt r

    If the number of terms of the

    series approaches infinity, the

    series converges and the

    resultant becomes

    where,

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    2

    0 4 2

    2 (1 cos )

    (1 ) 2 cosR

    rI I

    r r

    Reflected irradiance

    2

    00

    2

    aI

    *.

    2

    R RR

    a aI

    0 2

    (1 )

    1

    ii t

    R i

    r ea a e

    r e

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    1 0

    2 ( )

    2 0

    4 ( 2 )3 0

    (2 1) [ ( 1) ]

    0

    .....................

    .........................

    i tt

    i t

    t

    i tR

    N i t N

    Nt

    a a tt e

    a a tt e

    a a tt r e

    a a tr t e

    Optical field in transmitted beam

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    0 2

    2

    0

    4 2

    1

    ( )

    (1 ) 2 cos

    i t

    T i

    T

    tta a e

    r e

    I ttI

    r r

    Transmitted irradiance

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    0 R TI I I

    2( )I tt

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    For Transmitted rays

    0max cos 1TI I

    22

    min 0 22

    1( ) cos =-1

    1T

    rI I

    r

    0

    4 2

    ( )

    (1 ) 2 cosT

    I ttI

    r r

    = 2m

    Path diff.2d cos m= m

    = (2m+1)

    Path diff.

    2d cos m= (2m+1)/2

    22 (1 cos )rI I

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    2

    max 0 22

    4( ) cos 1

    1R

    rI I

    r

    For Reflected rays

    min 0 cos 1RI

    0 4 2

    2 (1 cos )

    (1 ) 2 cosR

    rI I

    r r

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    Interference filter

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    An interference filter is designed for normal incidence of 488 nm light. The

    refractive index of the spacer is 1.35. What should be the thickness of the

    spacer for normal incidence of light.

    nm47.180

    2

    d

    d

    It will pass different wavelength if the angle of incidence is not 90o.

    q md m cos2

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    We now introduce

    Coeff icient of F inesse

    2

    2

    2

    1

    rF

    r

    22

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    2

    2

    0

    2

    0

    sin / 2

    1 sin / 2

    1

    1 sin / 2

    r

    t

    FI

    I F

    I

    I F

    2cos 1 2sin

    2

    2

    0

    4 2

    ( )

    (1 ) 2 cosT

    I ttI

    r r

    2

    0 4 2

    2 (1 cos )

    (1 ) 2 cosR

    rI I

    r r

    2

    2

    1

    rF

    r

    2sin / 2FI

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    Airy function

    2

    1

    ( )1 sin

    2F

    q A

    2

    0

    2

    0

    sin / 2

    1 sin / 2

    1

    1 sin / 2

    r

    t

    FI

    I F

    I

    I F

    Airy function represents the transmitted flux-density distribution.

    Note: q is related to path difference .

    The complementary [1 -A(q)] represents the reflected flux-density

    distribution.

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    d or

    I0

    Multiple beam interference has resulted in redistribution of energy

    density in comparison to sinusoidal two-beam patter.

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    IR/I IT/I

    d or

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    Variation of intensities with phase

    d or

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    Bright fringes Transmitted rays

    Dark fringes Reflected rays

    Dark fringes Transmitted raysBright fringes Reflected rays

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    53

    Fabry-Perot I nter ferometer

    53

    F b P t I t f t

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    Fabry-Perot Interferometer

    30

    o

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    The conditions of interference are precisely those discussed earlier.

    With =1, the bright fringes in transmission are given by:

    2d cosqm= m

    The radii of the rings are therefore given by the formula obtained in

    Michelson interferometer i.e.,

    Rn D2qm

    2= D2n/d

    However, there is an essential difference between M .I . and F.P.: One

    uses a two beam interference while the other uses multiple beam

    interference. Hence the formula for the intensities and the

    sharpness of the fr inges are qui te different.

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    The intensity is given by:

    2sin1

    cos21

    )(

    224

    2/

    F

    I

    rr

    ttII oot

    WhereFis Coefficient of finesse of the mirror system.

    F= (2r/(1-r2))2

    and we also know that, for bright fringe : 2d cosqm= m

    What we can conclude from these equations:

    a)The intensity falls on either side of the maximum.

    b)The fall in intensity is dictated by the value of the Coefficient offinesse F.

    c)The Coefficient of finesse is larger for values of the reflection

    coefficient rapproaching unity. Thus very sharp rings are obtained

    by increasing the polish of the mirrors.

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    I0

    T itt d i t it

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    Transmitted intensity

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    Full width at half maximum

    m

    =IT/Io

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    wikipedi

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    When two mirrors are held fixed and adjusted for parallelism by

    screwing some sort of spacer, it is said to be an Etalon.

    A quartz plate polished and metal-coated will also serve as an Etalon

    (with 1).

    Chromatic resol ing po er

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    Chromatic resolving power

    - The ability of the spectroscope or the interferometer to separate the

    components of multiplets is known as chromatic resolving power (CRP).

    - In a two beam interferometer, like Michelson interferometer and Youngs

    double slit set-up, the bright fringes are as broad as the dark fringes. The

    fringes are not sharp.

    - For good resolution, the bright fringes must be as sharp as possible.

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    Fabry-Perot

    fringes

    Michelson

    fringes

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    Doublet separation in

    Fabry-Perot interferometer

    R l d l h

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    Resolved wavelengths

    w: widths: separation

    U l d l th

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    Unresolved wavelengths

    Barely resolved

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    Barely resolved

    Chromatic resolving power of

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    Chromatic resolving power of

    Fabry Perot interferometer

    - Where, is the minimum wavelength interval of a doublet that the instrument is

    capable of barely resolving.- The criterion for bare resolution is called theRayleigh criterion.

    - The smaller the value of , the higher is the resolving power of the instrument.

    Barely resolved

    Using: 2d cos m= m; ( Pabry-Perot - bright fringe in transmission )

    )'( 2ttII o

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    2sin1

    cos2)1(

    2

    24

    F

    I

    rrI

    o

    oT

    14

    )(

    2sin2/1

    wmF

    FWHM: Angular distance at which the intensity falls to half the peak intensity

    2

    )(

    2

    1sin1

    2 2 wm

    oo

    F

    II

    1)(

    sin2/1

    wmF

    sin(a+b)=sin a cos b+ cos a sin b

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    142

    sin

    F

    &

    =sin a cos b+ cos a sin b

    4

    )(

    4

    )(sin

    ww

    2/1

    4)(

    Fw

    ;

    Usingmm d q

    cos

    4

    m

    wdF q

    q

    sin)(

    2/1

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    m

    wdF q

    q

    sin)(

    2/1

    F1/2

    Using

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    CRP

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    Sodium doublet

    1= 589.0 nm

    2= 589.6 nm

    CRP ~ 1000

    = 0.6 nm

    /~1000

    di d bl

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    CRP >1000

    Sodium doublet

    1= 589.0 nm

    2= 589.6 nm

    /~1000

    = 0.6 nm

    S di d bl

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    CRP >> 1000

    Sodium doublet

    1= 589.0 nm

    2= 589.6 nm

    = 0.6 nm

    /~1000

    S di d bl

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    CRP>>>1000

    Sodium doublet

    1= 589.0 nm

    2= 589.6 nm

    /~1000

    = 0.6 nm

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    Types of fringes

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    Interference fringes

    Real Virtual Localized Non-localized

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    Real fringe

    - Can be intercepted on a screen placed anywhere in

    the vicinity of the interferometer without a

    condensing lens system.

    Virtual fringe

    - Cannot be projected onto a screen without a

    condensing focusing system. In this case, rays do not

    converge.

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    Non-localized fringe

    - Exists everywhere

    - Result of point/line source

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    Localized fringe

    - Observed over particular surface

    - Result of extended source

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    POHLS INTERFEROMETER

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    Real

    Non-localized

    Virtual

    Localized

    N t Ri

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    Newtons Ring

    Ud