1 chapter 11 special functions mathematical methods in the physical sciences 3rd edition mary l....
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Chapter 11 Special functions
Mathematical methods in the physical sciences 3rd edition Mary L. Boas
Lecture 12 Gamma, beta, error, and elliptic
2
2. The factorial function (usually, n : integer)
1!!
32,
2Similarly,
.111
011
010
40
330
2
200
0
00
ndxexn
dxex
dxexdxex
dxexedxxe
edxe
xnn
xn
xx
xxax
xax
3
3. Definition of the gamma function: recursion relation (p: noninteger)
.0,0
1 pdxexp xp- Gamma function
ppp
ppdxexp xp
1
.1,!10
- Example .5/164/94/1,
4/14/14/54/5)4/5(4/9
so
!.1
,!1
0
0
1
ndxexn
ndxexn
xn
xn
- Recursion relation
4
4. The Gamma function of negative numbers
)0(11 ppp
p
- Example
.7.03.13.0
13.1,7.0
3.0
13.0
.0as11
. ppp
pcf
- Using the above relation, 1) Gamma(p= negative integers) infinite. 2) For p < 0, the sign changes alternatively in the intervals between negative integers
5
5. Some important formulas involving gamma functions
2/1
.442/1
.2211
2/1)prove(
2/
0 00 0
2
000
222
22
rdrdedxdye
dyeydyey
dtet
ryx
yyt
.sin
1p
pp
6
6. Beta functions
pqBqpBcfqpdxxxqpB qp ,,..0,0,1,1
0
11
yyxy
dyyqpBiii
xdqpBii
ayxdyyayaa
dy
a
y
a
yqpBi
qp
p
qp
a qpqp
aqp
1/.1
,)
sin.cossin2,)
/.1
1,)
0
1
212122/
0
0
1110
11
7
7. Beta functions in terms of gamma functions
qp
qpqpB
,
.,2
1
2
1sincos4
sincos4
4
2,2
)Prove
0
2/
0
1212122
0
2/
0
1212
0 0
1212
0
12
0
12
0
1
2
2
22
22
qpBqpddrer
rdrderr
dxdyeyxqp
dxexqdyeydtetp
pqrqp
rpq
yxpq
xqyptp
8
- Example
0 5
3
1 x
dxxI
0
1
.1
,. qp
p
y
dyyqpBcf
.
4
1
!4
!3
5
14
.1,431,5
qppqp
9
8. The simple pendulum
.sin0sin
cos2
1
cos
2
1
2
1
22
22
22
l
gmglml
dt
d
mglmlVTL
mglV
lmmvT
- Example 1 For small vibration,
./21
sin
glTl
g
10
- Example 2
integralellipticcf..constcos2
1
:sinsinsin
2
l
g
dl
gdor
l
g
l
g
In case of 180 swings (-90 to +90)
./42.7computer, Using
!function!Beta,cos2
4
.4
22
cos
.2
cos,cos
2,cos
2
1
.0const.090
2/
0
4/
0
2/
0
2
glT
d
g
lT
T
l
gdt
l
gd
dtl
gd
l
g
dt
d
l
g
T
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9. The error function (useful in probability theory)
.2
erf0
2
dtex t- Error function:
- Standard model or Gaussian cumulative distribution function
.2/erf2
1
2
1
2
1
2/erf2
1
2
1
2
1
2/
2/
2
2
xdtex
xdtex
x t
x t
.2
2erfc
,2/erf12
erfc
2/
2/
2
2
x
t
x
t
dtex
xdtex
- Complementary error function
.122erf xx
- in terms of the standard normal cumulative distribution function
12
- Several useful facts
1.!253
2
!21
22erf
.12
12
2
1
2
122erf
erferf
53
0
42
0
0
2
2
xxx
xdtt
tdtex
dte
xx
xx t
t
- Imaginary error function:
xix
dtexx t
ierfierf
.2
erfi0
2
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10. Asymptotic series
.2
erf1erfc2
x
t dtexx
.1
2
1
2
1
1
2
1
2
11
2
11
,2
1111Using
22
2222
2222
2
2
x
tx
x
t
x
t
x
t
x
t
tttt
dtet
ex
dtt
eet
dtedt
d
tdte
edt
d
ttet
tet
e
14
.
1
2
3
2
13
2
1
2
11
2
1
//1/1Using
22222
22
4343
2132
x
tx
x
t
x
t
x
t
tt
dtet
ex
dtt
eet
dtedt
d
edtdtet
1.2
531
2
31
2
11~erf1erfc 32222
2
xxxxx
exx
x
- This series diverges for every x because of the factors in the numerator. For large enough x, the higher terms are fairly small and then negligible. For this reason, the first few terms give a good approximation. (asymptotic series)
15
11. Stirling’s formula
.2~288
1
12
1121
2~!
2pep
pppepp
nenn
pppp
nn
- Stirling’s formula
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11. Elliptic integrals and functions
- Legendre forms:
.10,sin1,:kindSecond -
,10,sin1
,:kindFirst-
0
22
0 22
kdkkE
kk
dkF
- Jacobi forms:
0 0 2
2222
0 0 22222
.1
1sin1,
,10,11sin1
,
sin,sin
dtt
tkdkkE
ktkt
dt
k
dkF
xt
x
x
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- Complete Elliptic integrals (=/2, x=sin=1):
2/
0
1
0 2
222
2/
0
1
0 2222
.1
1sin1,
2
,11sin1
,2
dtt
tkdkkEkEorE
tkt
dt
k
dkFkKorK
t
t
- Example 1
4/,3/sin,/1,2/3,
964951.0~21,3/,sin2/11
1
3/
0
22
EkEorkEkxEor
EkEd
18
- Example 2
3/
0
223/
0
2 sin2/114sin816
dd
.,2,
,2,.cf
,,sin1.cf 21222
1
kEnEknE
kFnKknF
kEkEdk
19
- Example 4. Find arc length of an ellipse.
ellipseoftyeccentrici:,kindsecondtheofintegralelliptical
.sin1sin
.sincos
cos,sin
22
222
22
222222
22222222
ea
bak
da
baadbaads
dbadydxds
byax
(using computer or tables)
20
- Example 5. Pendulum swing through large angles.
2sin24
2sin2
24
integralelliptic2
sin24
2
coscos
.coscos2
.constcos2
0
2
2
Kg
lK
g
lT
KT
l
gd
l
g
l
g
21
2/~2/sin,smallfor
1612
2sin
4
3
2
1
2sin
2
11
24
series.by ion approximat ,/2sinlargetoonotFor
24
22
2
212
g
l
g
lT
α
- For =30, this pendulum would get exactly out of phase with one of very small amplitude in about 32 periods.
22
- Elliptic Functions
uuudu
d
xku
xu
uxxtkt
dtu
xt
dtu
x
x
dncnsn
1dn
1cn
.sn function) elliptic(sn11
sin1
22
2
1
0 222
1
0 2