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Pipe Flow and Water Distribution Systems

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Page 1: 09pipesandpumps.ppt

Pipe Flow and Water Distribution Systems

Page 2: 09pipesandpumps.ppt

CEE 311—Hydroscience

BackgroundWill now consider pipe systems

under pressure flowWater distribution systemsSewer interceptors

Problems can be solved using:Continuity equationSteady-state energy equation

Page 3: 09pipesandpumps.ppt

CEE 311—Hydroscience

Continuity EquationBetween two points in the system,

continuity equation states that flows are equal:

Q1 =A1V1 =Q2 =A2V2

Page 4: 09pipesandpumps.ppt

CEE 311—Hydroscience

Steady-State Energy EquationTotal head is the sum of elevation,

pressure and velocity headsBetween two points in the system, can

write the steady-state energy equation:

Z1 +P1

γ +α V12

2g =Z2 +P2γ +α V2

2

2g +hf +hm

Elevation Pressur

e Velocity

Friction lossesMinor

losses

(11.1)

Page 5: 09pipesandpumps.ppt

CEE 311—Hydroscience

Definition of TermsHydraulic grade line (HGL)

Line depicting elevation of pressure head + elevation head along the pipe

Energy grade line (EGL)Line depicting elevation of total

head along the pipeFor uniform pipe, V1=V2 thus EGL is

parallel to HGL

Page 6: 09pipesandpumps.ppt

CEE 311—Hydroscience

Hydraulic and Energy Grade Lines

Gupta, Fig. 11.1

L

Sf =hf

L

Page 7: 09pipesandpumps.ppt

CEE 311—Hydroscience

Energy Grade Line ConceptsThe EGL will have discontinuities at

fittings due to minor lossesPumps and turbines also add

discontinuitiesFor pump, add energy term to

LHSFor turbine, subtract energy term

from LHS

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CEE 311—Hydroscience

Computing Friction LossesIn some cases, can determine hf

from energy balanceCan compute hf directly from

equationsChezy equationDarcy-Weisbach equationHazen-Williams equation

Page 9: 09pipesandpumps.ppt

CEE 311—Hydroscience

Chezy EquationRecall the form of the Chezy equation:

Substituting S = hf/L and solving for hf:

V =C RS

hf =LV 2

RC2 =4LV 2

dC2

(10.11)

Page 10: 09pipesandpumps.ppt

CEE 311—Hydroscience

Darcy-Weisbach EquationIn 1845, Darcy and Weisbach found a

corresponding model for pipe flow:

hf =f L

dV2

2g

Where f = friction factor [-], L = pipe length [L], d = pipe diameter [L], V = velocity [LT-1], and g = gravity [LT-2]

(11.2)

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CEE 311—Hydroscience

Darcy-Weisbach EquationEquating this to the Chezy formula,

see the relationship between Chezy coefficient and the friction factor:

f =8g

C2 C = 8g

for

Page 12: 09pipesandpumps.ppt

CEE 311—Hydroscience

Darcy-Weisbach EquationThe friction factor depends on the flow

Different relationship for laminar and turbulent flow

Recall that Reynolds number (Re) can be used to define flow conditions:

Re=Vd

ν (11.3)

Page 13: 09pipesandpumps.ppt

CEE 311—Hydroscience

Darcy-Weisbach EquationFor laminar flow (Re < 2000),

friction factor is a simple function of Re (64/Re)

For turbulent flow (Re > 4000), friction factor is a function of Re and pipe roughness

Pipe roughness determined from equivalent sand roughness ()

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CEE 311—Hydroscience

Roughness terms for pipes

Gupta, Table 11.1

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CEE 311—Hydroscience

Darcy-Weisbach EquationBased on experiments in the 1930s

and 1940s, determined relationship between friction factor and Re

Expressed in graphical form as the Moody diagram

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CEE 311—Hydroscience

Moody Diagram

Gupta, Fig. 11.4

Relative roughness (/d)

Page 17: 09pipesandpumps.ppt

CEE 311—Hydroscience

Darcy-Weisbach EquationIn 1976, Jain derived an empirical

relationship for the family of curves presented in the Moody diagram:

1f

=−2log ε3.7d +5.72

Re0.9⎛ ⎝ ⎜

⎞ ⎠ ⎟ (11.8)

Page 18: 09pipesandpumps.ppt

CEE 311—Hydroscience

Minor LossesTo determine head losses due to pipe

fittings (bends, valves, transitions):

The loss coefficient (K) is a function of the type of fitting (Table 11.2)

hm =K V2

2g (11.12)

Page 19: 09pipesandpumps.ppt

CEE 311—Hydroscience

Minor Loss Coefficients

Gupta, Table 11.2

Page 20: 09pipesandpumps.ppt

CEE 311—Hydroscience

Darcy-Weisbach EquationThere are three main variables in

the Darcy-Weisbach equation: hf, d and V(or Q)

Thus there are three main classes of problems:Compute hf given d and VCompute V given d and hf

Compute d given hf and Q

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CEE 311—Hydroscience

Compute hf (given d, V)Determine Re from V, d and

(function of temperature)Determine f using either Moody

diagram or equation (laminar eqn or Jain formula)

Compute hf directly from D-W equation

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CEE 311—Hydroscience

Compute V (given d, hf)Since V and f are unknown, cannot

determine Re directlySolution is to use a trial-and-error

procedure:Assume a value for fCompute V from D-W eqnDetermine Re and hence fIterate until f converges

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CEE 311—Hydroscience

Compute d (given hf, Q)Since V and f are unknown, cannot

determine Re directlySolution is to use a trial-and-error

procedure:Assume a value for fCompute d from D-W eqn and

continuity (V=Q/A)Determine Re and hence fIterate until f converges

Page 24: 09pipesandpumps.ppt

CEE 311—Hydroscience

Hazen-Williams EquationAnother relationship for hf is

commonly used for pipe flow in water-supply systems:

V =1.318CR0.63S0.54

Where V is velocity in ft/s, C is a coefficient, R is hydraulic radius (d/4) in ft, and S is slope of EGL (hf/L)

(11.9)

Page 25: 09pipesandpumps.ppt

CEE 311—Hydroscience

Hazen-Williams EquationFor circular pipes, can substitute

V=Q/A, A=d2/4, and R=d/4 to get

Q =0.432Cd2.63S0.54

Where Q is flow in ft3/s (m3/s), d is diameter in ft (m), and S is slope of EGL (hf/L), dimensionless

(11.10a)

Q =0.278Cd2.63S0.54 (11.10b)

English

Metric

Page 26: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pipes in SeriesConsider a compound pipeline,

with the pipes in series:

The general approach is to compute the equivalent length of a single diameter pipe

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CEE 311—Hydroscience

Pipes in SeriesFor pipes in series, know that:

Q1=Q2=…=Qn

hf=hf1+hf2+…+hf3

If we assume a value of Q, can compute individual losses

Setting this equal to loss for a single pipe (diameter d), can solve for equivalent length (Leq)

Page 28: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pipes in ParallelConsider a compound pipeline,

with the pipes in parallel:

Page 29: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pipes in ParallelFor pipes in parallel, know that:

hf=hf1=hf2=…=hf3

Q=Q1+Q2+…+Qn

If we assume a value of hf, can compute individual discharges (Qi) for each pipe

Setting total loss for single pipe (diameter d) equal to hf, can solve for equivalent length (Leq)

Page 30: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pipe NetworksFlow through pipe networks has

multiple pathsSolution techniques based on

corrections to assumed flowsHardy-Cross methodLinear theoryNewton-Rhapson method

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CEE 311—Hydroscience

Example Pipe Network

Linsley, Fig. 11.7

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CEE 311—Hydroscience

Pipe NetworksFor a valid solution, two

conditions must hold:The algebraic sum of the

pressure drops around any closed loop must be zero

The flow entering a junction must equal the flow leaving it

Page 33: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pipe NetworksRecall the Darcy-Weisbach and

Hazen-Williams formulas:

hf =16π2 f L

d5Q2

2g

hf = 4.727LC1.85d4.87Q1.85

Both formulas are of the general form hf=KQn, where K is equivalent resistance (see Table 11.5 in Gupta)

Page 34: 09pipesandpumps.ppt

CEE 311—Hydroscience

Hardy-Cross MethodMethod is based on successive

iterationsA flow is assumed in each pipe to

satisfy continuityA correction to each flow is

computed based on pressure drops around closed loops

Page 35: 09pipesandpumps.ppt

CEE 311—Hydroscience

Hardy-Cross MethodThe pressure drop condition can

be written as

hfloop∑ =0

From general resistance formula, this can be written as

K Qa +δ( )loop∑ n =0

Page 36: 09pipesandpumps.ppt

CEE 311—Hydroscience

Hardy-Cross MethodUsing a binomial expansion and

neglecting 2nd and higher order terms,

δ =− hf

loop∑

n hf Qaloop∑

(11.18)

Where hf is the head loss for the assumed Qa and n is the exponent in the resistance formula

Page 37: 09pipesandpumps.ppt

CEE 311—Hydroscience

Systems with PumpsTo accommodate pumps in the

system, the energy equation needs to be modified:

Z1 +P1

γ +α V12

2g +H p =Z2 +P2γ +α V2

2

2g +hf +hm

Hp is the head added to the system by the pump

Page 38: 09pipesandpumps.ppt

CEE 311—Hydroscience

System with a Pump

Gupta, Fig. 11.8

=Hp Z

Z1 +P1

γ +α V12

2g +H p =Z2 +P2γ +α V2

2

2g +hf +hm

=Z+hf+hm

H p = Z2 −Z1( )+

P2 −P1( )γ +α V2

2 −V12

2g⎛ ⎝ ⎜

⎞ ⎠ ⎟ +hf +hm

V1=V2

P1=P2

Page 39: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pump Brake HorsepowerEfficiency of pump () is the ratio of

horsepower out (BHP) and power in, thus BHP can be computed as

BHP =γQHp

550η (11.14)

Where BHP is power (HP), is specific weight (lb/ft3), Q is flow (cfs), Hp is head added (ft), and is efficiency

Page 40: 09pipesandpumps.ppt

CEE 311—Hydroscience

PumpsThere are many different types of

pumpsClosed radial

Open radialMixed flowPropeller

Page 41: 09pipesandpumps.ppt

CEE 311—Hydroscience

PumpsFor design purposes, pumps are

selected based on performancePerformance parameters include:

Rotational speedDischarge capacityPumping headPower appliedEfficiency

Page 42: 09pipesandpumps.ppt

CEE 311—Hydroscience

Affinity LawsFor geometrically similar (homologous)

pumps, dimensional analysis produces

Q2Q1

=N2N1

D2D1

⎛ ⎝ ⎜

⎞ ⎠ ⎟

3

H2H1

= N2N1

⎛ ⎝ ⎜

⎞ ⎠ ⎟

2 D2D1

⎛ ⎝ ⎜

⎞ ⎠ ⎟

2

P2P1

= N2N1

⎛ ⎝ ⎜

⎞ ⎠ ⎟

3 D2D1

⎛ ⎝ ⎜

⎞ ⎠ ⎟

5

Page 43: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pump System TermsStatic suction lift: Vertical

distance from source water level to centerline of pump

Gupta, Fig. 11.17b

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CEE 311—Hydroscience

Pump System TermsStatic discharge lift: Vertical

distance from centerline of pump to water level at outlet

Gupta, Fig. 11.17b

Page 45: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pump System TermsTotal static head: Sum of static

suction lift and static discharge lift

Gupta, Fig. 11.17b

=Z

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CEE 311—Hydroscience

Pump System TermsTotal dynamic head (Hp): Sum of

total static head and head losses

Using Darcy-Weisbach formula for friction losses, in terms of Q:

Hp =ΔZ+hloss=ΔZ+hf +hm

Hp =ΔZ+0.81g f LQ2

d5 + KQ2∑d4

⎛ ⎝ ⎜

⎞ ⎠ ⎟ (11.31)

Page 47: 09pipesandpumps.ppt

CEE 311—Hydroscience

Example System-Head Curve

Gupta, Fig. 11.18

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CEE 311—Hydroscience

Pump CharacteristicsSo far, we’ve assumed the efficiency

() of a pump is constantIn practice, for a given pump running

at a given speed, there are relationships among Q, Hp, and

The relationships are called the pump characteristics or performance curves

Page 49: 09pipesandpumps.ppt

CEE 311—Hydroscience

Pump CharacteristicsThe pump characteristic curves

are experimentally derivedGenerally shown as a function of Q

Pumping head (Hp)Brake horsepower (P)Efficiency ()

Page 50: 09pipesandpumps.ppt

CEE 311—Hydroscience

Example Pump Characteristic Curve

Gupta, Fig. 11.19

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CEE 311—Hydroscience

Pump SystemsIf we superimpose the system-

head curve with the pump-characteristic curve, the intersection will determine the operating point of the pump in the system

If efficiency is too low, then select another pump

Page 52: 09pipesandpumps.ppt

CEE 311—Hydroscience

Economics ReviewIn many cases, comparison of

different water-resources alternatives is difficult due to differing types of costs, benefits

Economic analysis offers a basis for comparison

There are 2 general bases for comparison: money and time

Page 53: 09pipesandpumps.ppt

CEE 311—Hydroscience

Economics ReviewThe time to be considered will be one of

the following:Economic life

Point where benefits < costsPhysical lifeAnalysis period

Planning horizon, generally less than economic or physical life

Since projects have different lives and cash flows, need to reduce to a common unit

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CEE 311—Hydroscience

Time Value of MoneyIn an inflation-free world, there is a

time-value associated with moneyGiven $1 today, I could invest the

money, earn i percent interest, and have $1(1+i) in a year

If we let P = present value, and F1 = future value in 1 year, see that

F1 =P 1+i( ) ⇒ P = F11+i( )

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CEE 311—Hydroscience

Time Value of MoneyThus $1 a year from today is worth

less than $1 in terms of today’s moneyIn general, for a future amount at the

end of N years, see that

FN =P 1+i( )N

P = FN1+i( )Nand

Page 56: 09pipesandpumps.ppt

CEE 311—Hydroscience

Time Value of MoneyUsually use the following notation:

FP i,N( )= 1+i( )N

PF i,N( )= 1

1+i( )N“Present worth of

a future sum”

“Future worth of a present sum”

Page 57: 09pipesandpumps.ppt

CEE 311—Hydroscience

Time Value of MoneyNow consider a series of payments

which result in $A each yearThis is termed an annual seriesFrom the formula for present worth of a

future sum, see that

P = A1+i( )1 + A

1+i( )2 +L + A1+i( )N

Page 58: 09pipesandpumps.ppt

CEE 311—Hydroscience

Time Value of MoneyIt can be shown that:

PA i,N( )= 1+i( )N −1

i 1+i( )N“Present worth of an annual series”

“Equivalent annual series of a

present sum”

AP i,N( )= i 1+i( )N

1+i( )N −1

Page 59: 09pipesandpumps.ppt

CEE 311—Hydroscience

Time Value of MoneyIt is easy to shown that:

FA i,N( )= 1+i( )N −1

i“Future worth of an annual series”

“Equivalent annual series of a

future sum”

AF i,N( )= i

1+i( )N −1

Page 60: 09pipesandpumps.ppt

CEE 311—Hydroscience

Economic AnalysisWith the discounting formulas, can

put projects on an equivalent basis in terms of money and time

In practice, there are three approaches:Present worth methodBenefit-cost ratio methodNet annual benefit method

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CEE 311—Hydroscience

Economic AnalysisConsider the choice between two projects:

Project A

Project B

Initial cost $50,000 $50,000Annual benefits

$12,000 $12,500

Project life 50 yrs 25 yrsDiscount rate 4% 4%Which project should be chosen?

Page 62: 09pipesandpumps.ppt

CEE 311—Hydroscience

Present Worth MethodThe idea is to compute the net present

worth (B-C) of each projectSelect the project with the largest net

present worthRules of analysis:

Bring benefits, costs back to the presentUse the same discount rateUse the same period of analysis

Page 63: 09pipesandpumps.ppt

CEE 311—Hydroscience

Benefit-Cost Ratio MethodThe idea is to move to the next alternative

if benefits increase more than costsRules of analysis:

Bring benefits, costs back to the presentUse the same discount rateUse the same period of analysisRank alternatives from least to greatest

costIf B/C >1, move to next alternative

Page 64: 09pipesandpumps.ppt

CEE 311—Hydroscience

Net Annual Benefit MethodThe idea is to chose the project

with the largest net annual benefit (B-C)

Rules of analysis:Compute annual benefits, costsUse the same discount rateUse the same period of analysis

Page 65: 09pipesandpumps.ppt

CEE 311—Hydroscience

Choosing a Discount Rate (i)The discount rate represents the

“cost” of moneyFor private industry, use the

interest rate corresponding to the least expensive source of capital

For the public sector, generally use the rate paid by the Treasury on securities with terms to maturity exceeding 15 yrs