you may need to close viewing mode to open the window that the link opens up
DESCRIPTION
You may need to close viewing mode to open the window that the link opens up. What is a Log Equation:. ~ A log equation is a different way of writing an exponential equation. For example: 4 20 =5 can be written as log 4 5=20. The Way this works is: . You write log - PowerPoint PPT PresentationTRANSCRIPT
![Page 1: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/1.jpg)
![Page 2: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/2.jpg)
You may need to close viewing mode to open the window that the link opens up
![Page 3: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/3.jpg)
What is a Log Equation:~ A log equation is a different way of
writing an exponential equation.For example: 420=5 can be written as
log45=20
The Way this works is: •You write log•You put the base # is subscript•Then write the # that the original equation is equal to•Put in the = sign•Write the exponent
log4 5=20
![Page 4: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/4.jpg)
Adding logsWhen two or more logs with like bases are added, you multiply the numbers inside the log.log (5)+ log (7) ln(x+3)+ln(x-2)
log 35
=1.544
ln(x +x-6)2
![Page 5: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/5.jpg)
Subtracting logsWhen two or more logs with like bases are
subtracted, you divide the numbers inside the log.
log(x+7)-log(x)
log( )x+7x
ln(360)-ln(15)
36015
ln(24)
ln( )
=3.178
![Page 6: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/6.jpg)
Numbers in front of logs are the same thing as having the number inside the log to a power. so...
1\2ln(25) ln( 25) ln 5 1.609√
Numbers in front of logs
2log (x+1) is the same as log (x+1)5 5
![Page 7: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/7.jpg)
Examples2*5x/4 = 250
2
log5125=x/4
4(log5125)=x
x=12
-Divide both sides by 2-Write as a logarithmic equation.-Multiply Both Sides by 4
-Simplify
![Page 8: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/8.jpg)
Exampleslog(3x)= 15
7
10 =3x157
3
x= 46.317
-Re-write as an exponential equation-Divide both sides by 3
![Page 9: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/9.jpg)
Examples
ln(x-3)-ln(x)=ln(7)
ln =ln7(x-3)x
x-3=7x
6x=-36
x= -12
-Subtract Log's
-Cancel out ln's
-Subtract x from both sides-Divide both sides by 6
-Simplify
![Page 10: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/10.jpg)
log (x+5)+log (x+2)=log (x+6)2 2 2
(x+5)(x+2)=(x+6) -In this situation, because all of the log bases were the same, they cancel, leaving just the numbers inside the logs.
x +7x+10=x+6x +6x+4=0
2
2
-3+ 5 -3- 5√ √
- Multiply-Simplify
-Use the quadratic formula to find the answers
Examples
![Page 11: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/11.jpg)
x +3x-10=92
x +3x-19=0
x=3.110
x=-3.110
-Multiply the logs together
-Cancel the logs and square 3
log(x-2)+log(x+5)=2log(3)2
-Simplify
-Use quadratic formula
2
log(x +3x-10)=log 3
Examples
![Page 12: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/12.jpg)
You Try!1.)ln(x-3)+ln(x+4)=3ln(2)
2.)log (1-x)=13.)1\2ln(x+3)-ln(x)=04.)logx-(1\2)log(x+4)=15.)logx=46.)log (x-5)=-17.)4 =968.)4+log (7x)=10
x=-5, x=4x= -3x= ,x=103.85x=10,000x= 21\4x=5x=104.1433
4
1+ 13√2
1- 13√2
4
x2
![Page 13: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/13.jpg)
Newton's Law of Cooling
T(t)-Tm=(To-Tm)e-Kt
![Page 14: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/14.jpg)
Newton's Law of CoolingWhat Its Used For
• Newton’s Law of Cooling is used to measure the amount of heat lost over a period of time. This equation is often used in Occupations such as Crime scene investigation, where investigators examine bodies to see how long the person has been dead for.
• T(t)-Tm=(To-Tm)e-Kt T(t)=Temperature of object at time T Tm=Temperature of surrounding medium
(To-Tm)=Initial Temperature of the object K=Constant .25387 T=Time
![Page 15: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/15.jpg)
Example
Lets say we (hypothetically) find Chris Kryshak “Accidentally” killed by someone. On the body we find a post-it note left by the killer (definitely not Eric Weber) That says the temperature on death was 37 degrees Celsius. Investigators determine that the current temperature of the body is 30degrees Celsius, and today is a warm day at 29 degrees Celsius. Using T(t)-Tm=(To-Tm)e-Kt
we can determine how long Chris has been dead.
![Page 16: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/16.jpg)
Figuring Out What Time the Killer (Cough*Eric*Cough) killed Chris
• T(t)-Tm=(To-Tm)e-Kt Original Equation
• 30-29=(37)e.25387(T) Subtract 29 from 30
• 1=(37)e.25387(t) divide 1 by 37
• .02702703=e.25387(t) convert to Ln
• Ln.02702703=.25387t find Ln.02702703
• -3.610917803=.25387t Divide -3.610917803 by .25387
• T= -14.22349156*So, We have determined that Chris was killed by someone (who isn’t Eric) 14.22349156 hours ago. *This Number is a negative because it is looking at the time that has passed.
![Page 17: You may need to close viewing mode to open the window that the link opens up](https://reader035.vdocuments.site/reader035/viewer/2022062323/56816032550346895dcf5199/html5/thumbnails/17.jpg)